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Convert to an exponential equation. \(\log _{t} Q=k\)

Short Answer

Expert verified
The exponential form is \(t^k = Q\).

Step by step solution

01

Understand the Logarithmic Form

The given equation is in the form \(\text{log}_t Q = k\). This states that the logarithm of \(Q\) with base \(t\) is equal to \(k\).
02

Recall the Logarithm-Exponential Relationship

The logarithmic equation \(\text{log}_b a = c\) can be rewritten in exponential form as \(b^c = a\).
03

Rewrite the Equation in Exponential Form

Using the rule from the previous step, the base \(t\) raised to the power \(k\) equals \(Q\). Therefore, the equation \(\text{log}_t Q = k\) can be written as \(t^k = Q\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Logarithmic Form
Logarithms are a way to express exponents. When you see an equation like \(\text{log}_t Q = k\), it means that we are looking for the exponent to which the base \(\text{t}\) must be raised to get \(\text{Q}\).

This form states that \(\text{k}\) is the power you raise \(\text{t}\) to in order to obtain \(\text{Q}\). It's much like saying \(\text{'t raised to the power of k is Q'}\).

This format is very compact, making it easier to manipulate larger numbers and solve for unknown exponents.
The Logarithm-Exponential Relationship
Logarithms and exponentials are two sides of the same coin.

If you have a logarithmic equation like \(\text{log}_b a = c\), you can express it equivalently in exponential form as \(b^c = a\).

This means that logarithms essentially 'invert' exponentiation. If \(\text{log}_b a = c\), then raising \(\text{b}\) to \(\text{c}\) will give you \(\text{a}\).
  • For example, \(\text{log}_2 8 = 3\) because raising 2 to the power of 3 gives 8, i.e., \(2^3 = 8\).
  • Understanding this relationship helps in switching between these two forms, simplifying maths problems significantly.
Converting Logarithms to Exponentials
To convert a logarithmic equation to exponential form, just remember that \(\text{log}_b a = c\) is the same as \(b^c = a\). Let's put this into practice using our initial equation \(\text{log}_t Q = k\).

Here, our base is \(\text{t}\), the argument is \(\text{Q}\), and the exponent is \(\text{k}\). So, translating this into exponential form gives us:

\[t^k = Q\]

This tells us that raising \(\text{t}\) to the power \(\text{k}\) yields \(\text{Q}\). Practicing converting between these two forms will improve your algebraic skills and make solving equations much easier.

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Most popular questions from this chapter

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