Chapter 3: Problem 61
For each of the following, find the discriminant, \(b^{2}-4 a c\) and then determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist. $$5 t^{2}-7 t=0$$
Short Answer
Expert verified
The discriminant is 49 and there are two different real-number solutions.
Step by step solution
01
Write the equation in standard form
Rewrite the given equation in the standard quadratic form, which is axt^2 + bt + c = 0axt^2 + bt + c = 0. The given equation is 5t^2 - 7t = 0. This is already in the standard form axt^2 + bt + c = 0 axt^2 + bt + c = 0, where a = 5, b = -7, and c = 0.
02
Identify coefficients
From the equation 5t^2 - 7t = 0, identify the coefficients a, b, and c.a = 5b = -7c = 0
03
Write the discriminant formula
The discriminant Δdelta is found using the formula b^2 - 4ac.b^2 − 4ac. So in this problem, Δ = b^2 - 4ac.
04
Calculate the discriminant
Substitute a = 5, b = -7, and c = 0 into the discriminant formula. b^2 - 4ac = (-7)^2 - 4(5)(0).This simplifies to: 49 - 0 = 49.So the discriminant Δis 49.
05
Determine the nature of the roots
To determine the nature of the roots, analyze the discriminant:If Δ > 0, there are two different real-number solutions.If Δ = 0, there is one real-number solution.If Δ < 0, there are two different imaginary-number solutions.In this problem, the discriminant Δis 49, which is greater than 0. Therefore, there are two different real-number solutions.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic equations
Quadratic equations are a foundational concept in algebra and are of the form \(ax^2 + bx + c = 0\). These equations can be recognized by their characteristic \(t^2\) term, representing a second-degree polynomial. The coefficients \(a, b, \text{ and } c\) play crucial roles in determining the behavior and solutions of the equation. Here, \(a\) cannot be zero because that would reduce the equation to a linear equation. Quadratic equations are essential because they describe a wide range of phenomena in science, engineering, and mathematics. They can represent things like the trajectory of a projectile, the potential outcomes of a financial investment, or even the geometry of parabolas.
real-number solutions
Real-number solutions for quadratic equations occur under specific conditions. The key factor that determines the type of solutions is called the discriminant, which is calculated using the formula \(b^2 - 4ac\). When solving a quadratic equation, the discriminant tells us how many real-number solutions we have:
- If \(\Delta > 0\), there are two different real-number solutions.
- If \(\Delta = 0\), there is exactly one real-number solution.
imaginary-number solutions
Imaginary-number solutions occur when the discriminant of a quadratic equation is less than zero (\(\Delta < 0\)). Imaginary numbers involve the imaginary unit \(i\), where \(i\) is defined as \(\sqrt{-1}\). In simpler terms, \(i\) represents numbers that, when squared, give a negative result. If a quadratic equation has an imaginary solution, it means that the solutions cannot be represented on the real number line. Therefore, they involve a component of \(i\). For instance, in the quadratic equation where \(ac > b^2\), the discriminant \(b^2 - 4ac\) would result in a negative number, indicating the presence of two different imaginary-number solutions.
discriminant formula
The discriminant formula is a critical tool in determining the nature of solutions for quadratic equations. Given by \( \Delta = b^2 - 4ac \), this formula tells us whether we have real or imaginary solutions. Here's how it works:
- First, identify the coefficients \(a, b,\text{ and }c\) from the quadratic equation \(ax^2 + bx + c = 0\).
- Next, substitute these values into the discriminant formula \( b^2 - 4ac\).
- Calculate the result to find \(\Delta\).