Chapter 3: Problem 4
a) Find the vertex. b) Find the axis of symmetry. c) Determine whether there is a maximum or a minimum value and find that value. d) Graph the function.$$g(x)=x^{2}+7 x-8$$
Short Answer
Expert verified
a) Vertex: \(-\frac{7}{2}, -\frac{81}{4}\). b) Axis of symmetry: \(x = -\frac{7}{2}\). c) Minimum value: \(-\frac{81}{4}\).
Step by step solution
01
Identify coefficients
The given function is in standard form: \(g(x) = ax^2 + bx + c\). Here, identify the coefficients: \(a = 1\), \(b = 7\), and \(c = -8\).
02
Calculate the vertex
Use the vertex formula for a parabola in standard form: \(x = -\frac{b}{2a}\). Plug in the values for \(a\) and \(b\). \[ x = -\frac{7}{2(1)} = -\frac{7}{2} \]. Then, calculate the y-coordinate of the vertex by substituting \(x = -\frac{7}{2}\) into the function: \[ g\left(-\frac{7}{2}\right) = \left(-\frac{7}{2}\right)^2 + 7\left(-\frac{7}{2}\right) - 8 \]. Calculate each term: \[ \left(-\frac{7}{2}\right)^2 = \frac{49}{4} \], \[ 7\left(-\frac{7}{2}\right) = -\frac{49}{2} = -\frac{98}{4} \], and \(-8 = -\frac{32}{4}\). Now, sum these values: \[ g\left(-\frac{7}{2}\right) = \frac{49}{4} - \frac{98}{4} - \frac{32}{4} = -\frac{81}{4} \]. Thus, the vertex is \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\).
03
Find the axis of symmetry
The axis of symmetry is the vertical line that passes through the vertex. It is given by the equation \(x = -\frac{b}{2a}\). Thus, the axis of symmetry is \(x = -\frac{7}{2}\).
04
Determine if there is a maximum or minimum value
Since the parabola opens upwards (because \(a > 0\)), there is a minimum value at the vertex. The minimum value of the function occurs at \(y = -\frac{81}{4}\).
05
Graph the function
Plot the vertex \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\) and the axis of symmetry \(x = -\frac{7}{2}\). Identify additional points around the vertex and use the symmetry of the parabola to sketch the curve. The function forms a U-shaped curve opening upwards.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
vertex of a parabola
The vertex of a parabola is a crucial concept in understanding quadratic functions. It represents the highest or lowest point on the graph. For a quadratic function in standard form, \(f(x) = ax^2 + bx + c\), the vertex can be found using a simple formula:
The x-coordinate of the vertex is given by \(x = -\frac{b}{2a}\). By substituting the values of \(a\) and \(b\), you can find this coordinate. For the function \(g(x) = x^2 + 7x - 8\), we identified that \(a = 1\) and \(b = 7\).
Plugging these into the formula, we get:
\(x = -\frac{7}{2(1)} = -\frac{7}{2}\).
Next, substitute \(x = -\frac{7}{2}\) back into the function to find the y-coordinate:
\( g\left(-\frac{7}{2}\right) = \left(-\frac{7}{2}\right)^2 + 7\left(-\frac{7}{2}\right) - 8 = -\frac{81}{4}\).
So, the vertex of the parabola \(g(x)\) is at \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\).
The x-coordinate of the vertex is given by \(x = -\frac{b}{2a}\). By substituting the values of \(a\) and \(b\), you can find this coordinate. For the function \(g(x) = x^2 + 7x - 8\), we identified that \(a = 1\) and \(b = 7\).
Plugging these into the formula, we get:
\(x = -\frac{7}{2(1)} = -\frac{7}{2}\).
Next, substitute \(x = -\frac{7}{2}\) back into the function to find the y-coordinate:
\( g\left(-\frac{7}{2}\right) = \left(-\frac{7}{2}\right)^2 + 7\left(-\frac{7}{2}\right) - 8 = -\frac{81}{4}\).
So, the vertex of the parabola \(g(x)\) is at \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\).
axis of symmetry
The axis of symmetry of a parabola is a vertical line that divides the graph into two mirror images. It passes through the vertex of the parabola. For a quadratic function in the standard form \(f(x) = ax^2 + bx + c\), you can find the axis of symmetry using the same formula as the x-coordinate of the vertex: \(x = -\frac{b}{2a}\).
Given our function \(g(x) = x^2 + 7x - 8\), the axis of symmetry is:
\(x = -\frac{7}{2(1)} = -\frac{7}{2}\).
Therefore, the axis of symmetry is \(x = -\frac{7}{2}\). This line helps us understand how the parabola is oriented on the graph and is useful for plotting additional points symmetrically around the vertex.
Given our function \(g(x) = x^2 + 7x - 8\), the axis of symmetry is:
\(x = -\frac{7}{2(1)} = -\frac{7}{2}\).
Therefore, the axis of symmetry is \(x = -\frac{7}{2}\). This line helps us understand how the parabola is oriented on the graph and is useful for plotting additional points symmetrically around the vertex.
minimum value
In a quadratic function, the minimum or maximum value depends on the direction in which the parabola opens. If the parabola opens upwards (\(a > 0\)), the vertex represents the minimum value. If it opens downwards (\(a < 0\)), the vertex is the maximum value.
Since the coefficient \(a = 1\) in our function \(g(x) = x^2 + 7x - 8\) is positive, the parabola opens upwards. This means there is a minimum value at the vertex.
The minimum value is the y-coordinate of the vertex. From our calculation, the vertex is \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\), and thus the minimum value is \(y = -\frac{81}{4}\).
Understanding this helps us know the lowest point the function can reach, which is crucial for graphing and solving real-life problems.
Since the coefficient \(a = 1\) in our function \(g(x) = x^2 + 7x - 8\) is positive, the parabola opens upwards. This means there is a minimum value at the vertex.
The minimum value is the y-coordinate of the vertex. From our calculation, the vertex is \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\), and thus the minimum value is \(y = -\frac{81}{4}\).
Understanding this helps us know the lowest point the function can reach, which is crucial for graphing and solving real-life problems.
graphing quadratic functions
Graphing a quadratic function involves plotting its key features: vertex, axis of symmetry, and additional points. For the function \(g(x) = x^2 + 7x - 8\), we start by noting the main characteristics:
Steps to graphing:
This visual representation provides a deeper understanding of how the function behaves and aids in interpreting solutions.
- Vertex: \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\)
- Axis of symmetry: \(x = -\frac{7}{2}\)
- Direction: Parabola opens upwards since \(a = 1\) is positive
Steps to graphing:
- First, plot the vertex \(\left(-\frac{7}{2}, -\frac{81}{4}\right)\) on the coordinate plane.
- Draw the axis of symmetry as a vertical line through the vertex at \(x = -\frac{7}{2}\).
- Choose additional x-values around the vertex and calculate their corresponding y-values to get more points.
- Plot these points and use the symmetry of the parabola to reflect them across the axis of symmetry.
- Connect the points with a smooth U-shaped curve.
This visual representation provides a deeper understanding of how the function behaves and aids in interpreting solutions.