/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Graph the plane curve given by t... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph the plane curve given by the parametric equations. Then find an equivalent rectangular equation. $$x=1+2 \cos t, y=2+2 \sin t ; 0 \leq t \leq 2 \pi$$

Short Answer

Expert verified
The rectangular equation is \( (x-1)^2 + (y-2)^2 = 4 \).

Step by step solution

01

Understand the Parametric Equations

Given the parametric equations are \[ x = 1 + 2 \,\cos(t) \]\[ y = 2 + 2 \,\sin(t) \] where the parameter \( t \) ranges from \( 0 \) to \( 2\pi \). These equations describe a plane curve.
02

Identify Trigonometric Relationships

Recall the Pythagorean identity: \( \cos^2(t) + \sin^2(t) = 1 \). We will use this identity to eliminate the parameter \( t \).
03

Isolate Cosine and Sine

From the parametric equations, isolate \( \cos(t) \) and \( \sin(t) \): \( \cos(t) = \frac{x-1}{2} \) \( \sin(t) = \frac{y-2}{2} \).
04

Substitute into the Identity

Substitute \( \cos(t) \) and \( \sin(t) \) into the Pythagorean identity: \[ \left( \frac{x-1}{2} \right)^2 + \left( \frac{y-2}{2} \right)^2 = 1 \].
05

Simplify the Equation

Simplify the equation: \[ \left( \frac{x-1}{2} \right)^2 + \left( \frac{y-2}{2} \right)^2 = 1 \] Multiply both sides by 4: \[ (x-1)^2 + (y-2)^2 = 4 \].
06

Recognize the Equation of a Circle

Recognize that the equation \( (x-1)^2 + (y-2)^2 = 4 \) represents a circle with center at \( (1, 2) \) and radius 2.
07

Graph the Circle

Graph the circle with center at \( (1, 2) \) and radius 2. This is the geometric representation of the original parametric equations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

trigonometric identities
In order to transform parametric equations into a rectangular equation, knowing some fundamental trigonometric identities is crucial. One key identity we often use is the Pythagorean identity, \( \cos^2(t) + \sin^2(t) = 1 \). This allows us to relate cosine and sine functions to each other. For example, if we isolate \( \cos(t) \) and \( \sin(t) \) from the given parametric equations, we can substitute them into the Pythagorean identity.
This process lets us eliminate the parameter \( t \,\). By doing so, we convert the parametric equations into a single rectangular equation. This crucial step simplifies our task of understanding and graphing the associated curve.
rectangular equation
A rectangular equation describes a relationship between \( x \) and \( y \,\) without involving a parameter \( t \.\) To find a rectangular equation from parametric equations, we first isolate the trigonometric functions, as shown:
From \( x = 1 + 2 \cos(t)\,\):
\(\cos(t) = \frac{x-1}{2}\,\)
From \( y = 2 + 2 \sin(t)\,\):
\(\sin(t) = \frac{y-2}{2}\,\)
We then substitute these expressions for \( \cos(t) \) and \( \sin(t) \) into the Pythagorean identity:
\[ \left( \frac{x-1}{2} \right)^2 + \left( \frac{y-2}{2} \right)^2 = 1 \]
Simplifying gives:
\[ (x-1)^2 + (y-2)^2 = 4 \,\]
This is the rectangular form of the given parametric equations.
graphing parametric curves
Graphing parametric equations involves plotting points that correspond to different values of the parameter \( t \,.\) As \( t \) varies from \( 0 \) to \( 2\pi \,,\) each pair \( (x,y) \) represents a point on the curve.
For the given parametric equations \[ x = 1 + 2 \cos(t)\,\] and \[ y = 2 + 2 \sin(t)\,\], start by choosing values of \( t \). Calculate corresponding \( x \) and \( y \) values, and plot these points on a coordinate plane.
Once you have enough points, connect them smoothly to reveal the shape of the curve. In this case, the points form a circle centered at \( (1, 2) \) with a radius of 2. This helps visualize how the curve evolves as the parameter \( t \) changes.
circle equations
A circle's equation in the rectangular form is \[ (x-h)^2 + (y-k)^2 = r^2 \,\] where \( (h,k) \) is the center and \( r \) is the radius.
From our rectangular equation \[ (x-1)^2 + (y-2)^2 = 4 \,\] we identify:
  • Center: \( (1, 2) \.\)
  • Radius: \( \sqrt{4} = 2 \,.\)
This gives us a clear representation of the circle described by the parametric equations.
Knowing this form is essential because it simplifies graphing the curve and understanding its geometric properties.
By converting parametric equations into this format, we gain insight into the nature of the curve, making problems easier to solve and visualize.

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