/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 Solve \(e^{x^{2}-x}=1\).... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve \(e^{x^{2}-x}=1\).

Short Answer

Expert verified
The solutions are \(x = 0\) and \(x = 1\).

Step by step solution

01

Identify the equation structure

Recognize that the equation is of the form \(e^{f(x)}=1\), where \(f(x)=x^2 - x\). The goal is to find the values of \(x\) that satisfy this equation.
02

Set the exponent equal to zero

Since \(e^{0}=1\), set the exponent \(x^2 - x\) equal to zero to solve for \(x\). So, we have: \( x^2 - x = 0 \).
03

Factor the equation

Factor the quadratic equation \(x^2 - x = 0\) to find the solutions. The equation can be written as: \( x(x - 1) = 0 \).
04

Solve for x

Set each factor equal to zero and solve: \(x = 0\) or \(x - 1 = 0\). Therefore, the solutions are \(x = 0\) and \(x = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions in which a variable appears as an exponent. They take the form of \( a^x \), where 'a' is a constant base and 'x' is the exponent. These functions grow rapidly and are widely used in various fields such as finance, biology, and physics.
In the given exercise, we have a specific type of exponential function: \( e^{x^2 - x} \). Here, 'e' is the base, which is a mathematical constant approximately equal to 2.71828. The exponent is \( x^2 - x \). To solve equations involving exponential functions, we often look for ways to simplify the exponent.
In our example, we simplify the expression \( e^{x^2 - x} = 1 \) by recognizing that \( e^0 = 1 \). By setting the exponent equal to zero, we transform this into a simpler quadratic problem.
Quadratic Equations
Quadratic equations are polynomial equations of the second degree and have the general form \( ax^2 + bx + c = 0 \), where 'a', 'b', and 'c' are constants. Solving for 'x' requires finding the values that satisfy the equation.
In our exercise, once we set the exponent \( x^2 - x \) equal to zero, we end up with a quadratic equation: \( x^2 - x = 0 \). This is a simpler form of a quadratic equation where 'c' is zero.
To solve a quadratic equation, we can use various methods such as factoring, completing the square, or using the quadratic formula. In this case, factoring is the most straightforward approach.
Factoring
Factoring is a technique used to simplify polynomial expressions by expressing them as a product of simpler polynomials. It's especially useful in solving quadratic equations.
For the quadratic equation \( x^2 - x = 0 \), factoring allows us to write this as \( x(x - 1) = 0 \). This step breaks the equation into two simpler parts. Each factor can then be set to zero: \( x = 0 \) or \( x - 1 = 0 \).
Solving these two linear equations gives us the solutions \( x = 0 \) and \( x = 1 \). This demonstrates that factoring is a powerful tool in solving quadratics, making the process more manageable.
  • Start by looking for common factors.
  • Write the equation as a product of simpler expressions.
  • Set each factor to zero to solve for the variable.

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