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Solve each problem by using a system of three linear equations in three variables. Stocks, Bonds, and a Mutual Fund Marita invested a total of \(\$ 25,000\) in stocks, bonds, and a mutual fund. In one year she earned \(8 \%\) on her stock investment, \(10 \%\) on her bond investment, and \(6 \%\) on her mutual fund, with a total return of \(\$ 1860\). Unfortunately, the amount invested in the mutual fund was twice as large as the amount she invested in the bonds. How much did she invest in each?

Short Answer

Expert verified
She invested \$4000 in stocks, \$7000 in bonds, and \$14000 in mutual funds.

Step by step solution

01

Define the variables

Let’s define the variables for the amounts invested in different types of investments. Let \( x \) be the amount invested in stocks, \( y \) be the amount invested in bonds, and \( z \) be the amount invested in the mutual fund.
02

Set up the equations based on total investment

The total investment is \$25,000. Therefore, the first equation is:\[ x + y + z = 25000 \]
03

Set up the equation based on total return

The total return from all investments in a year is \$1860. The return from stocks is 8\% of \( x \), from bonds is 10\% of \( y \), and from the mutual fund is 6\% of \( z \). Therefore, the second equation is:\[ 0.08x + 0.10y + 0.06z = 1860 \]
04

Set up the equation based on the relationship between fund and bond investments

The amount invested in the mutual fund is twice as large as the amount invested in bonds. Therefore, the third equation is:\[ z = 2y \]
05

Solve the system of equations

Substitute \( z = 2y \) into the first and second equations: \[ x + y + 2y = 25000 \] \[ x + 3y = 25000 \] Solve for \( x \): \[ x = 25000 - 3y \] Substitute \( x = 25000 - 3y \) and \( z = 2y \) into the second equation: \[ 0.08(25000 - 3y) + 0.10y + 0.06(2y) = 1860 \] Simplify and solve for \( y \): \[ 2000 - 0.24y + 0.10y + 0.12y = 1860 \] \[ 2000 - 0.02y = 1860 \] \[ 0.02y = 140 \] \[ y = 7000 \] Then, \( z = 2y = 14000 \). Substitute \( y = 7000 \) back into the equation for \( x \): \[ x = 25000 - 3(7000) \] \[ x = 25000 - 21000 \] \[ x = 4000 \]
06

Verify the solution

Verify the amounts by plugging them back into the original equations:\[ 4000 + 7000 + 14000 = 25000 \] \[ 0.08(4000) + 0.10(7000) + 0.06(14000) = 1860 \] \[ 320 + 700 + 840 = 1860 \] Both equations are satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

investment problems
Investment problems often involve determining how money is distributed across different investment options. These can include stocks, bonds, mutual funds, or other investment vehicles. The goal is usually to figure out the amounts invested in each option based on a set of conditions and constraints.
For instance, you might be given the total amount of investment, different rates of return for each option, total returns, or specific relationships between the invested amounts.
Such problems can be effectively solved using a system of linear equations. This helps in simultaneously solving for multiple unknowns by using the given conditions as equations.
Understanding investment problems is crucial as it applies mathematical concepts to real-world financial decisions.
three variables
When solving investment problems, you often encounter multiple unknown values, or 'variables', that need to be determined.
In the example problem, we have three variables:
  • \(x\) for the amount invested in stocks
  • \(y\) for the amount invested in bonds
  • \(z\) for the amount invested in the mutual fund
Each variable represents a specific segment of the total investment. Using three variables makes it possible to create a system of equations that models the entire problem.
With the variables defined, it becomes easier to set up equations based on the given parameters such as total investment, returns on investment, and relationships between different investments. This structured approach simplifies the problem-solving process significantly.
solving equations
Solving a system of linear equations with three variables involves several steps. First, you set up three equations based on the problem's conditions.
For example, in the given problem, we use:
  • Total investment: \( x + y + z = 25000 \)
  • Total return: \( 0.08x + 0.10y + 0.06z = 1860 \)
  • Relationship between investments: \( z = 2y \)
With these equations established, you can use substitution or elimination methods to find the values of the variables.
Substitution involves replacing one variable with an equivalent expression from another equation. You solve one of the equations in terms of one variable and then substitute this expression into the other equations.
Elimination involves adding or subtracting equations to eliminate one of the variables, making it easier to solve for the remaining variables.
Let's break down the solution:
  • First, substitute \( z = 2y \) into the first and second equations
  • Rearrange and solve one of the equations for a single variable, such as \( x \)
  • Use the obtained value to find the other variables
  • Finally, verify the solution by plugging the values back into the original equations
This structured method ensures that the equations are solved systematically and correctly.

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