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Solve each system by graphing. $$\begin{aligned} 2 x+y &=-1 \\ y-x &=5 \end{aligned}$$

Short Answer

Expert verified
The solution is (-2, 3).

Step by step solution

01

Rewrite Each Equation in Slope-Intercept Form

Start by rewriting each equation in the form of \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.For the first equation \( 2x + y = -1 \):Subtract \( 2x \) from both sides to get \( y = -2x - 1 \).For the second equation \( y - x = 5 \):Add \( x \) to both sides to get \( y = x + 5 \).
02

Plot the Y-Intercepts

For the first equation \( y = -2x - 1 \), the y-intercept is \( -1 \). Plot the point (0, -1) on the graph.For the second equation \( y = x + 5 \), the y-intercept is \( 5 \). Plot the point (0, 5) on the graph.
03

Use the Slopes to Plot a Second Point for Each Line

For the first equation \( y = -2x - 1 \), the slope is \( -2 \), which means the line goes down 2 units for every 1 unit it goes to the right. From the y-intercept (0, -1), move down 2 units and right 1 unit to plot the point (1, -3).For the second equation \( y = x + 5 \), the slope is \( 1 \), which means the line goes up 1 unit for every 1 unit it goes to the right. From the y-intercept (0, 5), move up 1 unit and right 1 unit to plot the point (1, 6).
04

Draw the Lines

Draw a straight line through the two points plotted for each equation. The intersection of these two lines is the solution to the system.
05

Identify the Point of Intersection

Look for the point where the two lines intersect on the graph. This point is the solution to the system of equations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

slope-intercept form
To solve a system of linear equations by graphing, it's helpful to rewrite each equation in what's known as the slope-intercept form. This is expressed as the equation \( y = mx + b \), where \( m \) represents the slope and \( b \) is the y-intercept. Adjusting equations into this format makes plotting them on a graph straightforward. For instance, given the equation 2x + y = -1, subtract 2x from both sides to obtain y = -2x - 1. Now, it's in slope-intercept form with a slope \( m \) of -2, and a y-intercept \( b \) of -1. Incidentally, making similarly simple transformations to the second equation \( y - x = 5 \) yields y = x + 5. Now both equations are in slope-intercept form, and you are ready to move to the next steps.
y-intercept
The y-intercept of an equation is the point where the line crosses the y-axis, and it occurs when x equals 0. Identifying the y-intercept in the slope-intercept form is easy; it’s simply the constant \( b \) in \( y = mx + b \). For example, in the equation \( y = -2x - 1 \), the y-intercept is -1, meaning the line crosses the y-axis at (0, -1). For the equation \( y = x + 5 \), the y-intercept is 5, indicating a crossing at (0, 5). These points are critical as they provide a starting point to plot the lines on the graph.
plotting points
Once the y-intercepts are identified, you can proceed with plotting points. Start by marking the y-intercepts on the graph, such as (0, -1) and (0, 5). Next, use the slopes to find additional points. For \( y = -2x - 1 \), the slope of -2 means moving down 2 units for every unit moved right. Starting at (0, -1) and applying this method leads to the next point (1, -3). Similarly, for the line \( y = x + 5 \), a slope of 1 means moving up 1 unit for every unit moved right. Thus, from (0, 5) move up to (1, 6). Plotting these points helps to establish the path of the line.
linear equations
Working with linear equations involves understanding their properties and behavior when graphed. Each linear equation forms a straight line when plotted on a coordinate plane. The relationship within a linear equation signifies a constant rate of change, represented graphically by the slope. For instance, a slope of 1 means for each unit increase in x, y also increases by 1. In contrast, a slope of -2 indicates y decreases by 2 units with each unit increase in x. Recognizing these properties facilitates accurate graphing and solution determination for systems of linear equations.
graphing lines
Graphing lines from linear equations entails plotting points derived from the slope and y-intercept, then drawing a straight line through these points. For example, starting from the y-intercept (0, -1) for \( y = -2x - 1 \), use the slope -2 to find another point, such as (1, -3). Do similarly for \( y = x + 5 \) with points (0, 5) and (1, 6). Once points for each are plotted, draw lines through them. The intersection of these lines marks the solution to the system, representing values of x and y satisfying both equations simultaneously. This visual approach simplifies solving the system.

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