/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Write each complex number in the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write each complex number in the form \(a+b i\). $$\sqrt{6}\left(\cos 60^{\circ}+i \sin 60^{\circ}\right)$$

Short Answer

Expert verified
\( \frac{\sqrt{6}}{2} + i \frac{3\sqrt{2}}{2} \)

Step by step solution

01

- Identify the given complex number in polar form.

The complex number is given in polar form as \ \( \sqrt{6}(\cos 60^{\circ} + i \sin 60^{\circ}) \). Here, \( r = \sqrt{6} \), \( \theta = 60^{\circ} \), and it can be expressed as \( r(\cos \theta + i \sin \theta) \).
02

- Convert the trigonometric functions to their respective values.

Using the known values for cosine and sine at 60 degrees, \ \( \cos 60^{\circ} = \frac{1}{2} \) and \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \).
03

- Substitute the trigonometric values into the expression.

Substitute \( \cos 60^{\circ} \) and \( \sin 60^{\circ} \) into the given expression: \ \( \sqrt{6}(\frac{1}{2} + i \frac{\sqrt{3}}{2}) \).
04

- Distribute \( \sqrt{6} \) to both parts inside the parenthesis.

Multiply \( \sqrt{6} \) by each part of the expression: \ \( \sqrt{6} \cdot \frac{1}{2} + \sqrt{6} \cdot i \frac{\sqrt{3}}{2} \).
05

- Simplify the expression.

Perform the multiplication: \ \( \sqrt{6} \cdot \frac{1}{2} = \frac{\sqrt{6}}{2} \) and \( \sqrt{6} \cdot i \frac{\sqrt{3}}{2} = i \frac{\sqrt{18}}{2} = i\frac{3\sqrt{2}}{2} \). So, the simplified expression is \( \frac{\sqrt{6}}{2} + i \frac{3\sqrt{2}}{2} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Form
Polar form is a way to express complex numbers which are numbers in the form of \( a + bi \). This form is particularly useful in multiplication and division of complex numbers because it leverages the magnitude (or modulus) and the angle of the complex number.

In polar form, a complex number is represented as \( r(\text{cos} \theta + i \text{sin} \theta) \), where \( r \) is the magnitude and \( \theta \) is the argument or angle.

For example, given the complex number \( \sqrt{6} (\text{cos} 60^{\circ} + i \text{sin} 60^{\circ}) \), we see that:
  • \( r = \sqrt{6} \)
  • \( \theta = 60^{\circ} \)

This establishes an easily recognizable structure for complex numbers, making operations more intuitive. It’s especially useful for converting into a more standard form, like \( a + bi \).
Trigonometric Conversion
Trigonometric conversion is the process of using trigonometric function values to convert from polar form to rectangular form (\( a + bi \)). In our example:
  • \( \text{cos} 60^{\circ} = \frac{1}{2} \)
  • \( \text{sin} 60^{\circ} = \frac{\sqrt{3}}{2} \)

By substituting these values back into the polar form expression, we have:

\( \sqrt{6} (\text{cos} 60^{\circ} + i \text{sin} 60^{\circ}) = \sqrt{6} (\frac{1}{2} + i \frac{\sqrt{3}}{2}) \)

This step makes the equation more manageable by transforming it from an abstract form involving trigonometric functions into a more familiar algebraic expression. This is a key part of solving and understanding the complex number.
Simplification
To fully simplify a complex equation, you need to break down and combine the terms efficiently. In our given example, once we substitute with trigonometric values, we simplify it further by distributing \( \sqrt{6} \):

\( \sqrt{6} (\frac{1}{2} + i \frac{\sqrt{3}}{2}) \)

Distribute \( \sqrt{6} \):
\( \sqrt{6} \cdot \frac{1}{2} + \sqrt{6} \cdot i \frac{\sqrt{3}}{2} \)
Performing the multiplication gives:

  • \( \sqrt{6} \cdot \frac{1}{2} = \frac{\sqrt{6}}{2} \)
  • \( \sqrt{6} \cdot i \frac{\sqrt{3}}{2} = i \frac{\sqrt{18}}{2} = i \frac{3\sqrt{2}}{2} \)

So, it simplifies to:

\( \frac{\sqrt{6}}{2} + i \frac{3\sqrt{2}}{2} \).
This final form is much simpler and is expressed in the standard format of complex numbers, \( a + bi \). Understanding the importance of these steps - from substitution to distribution, and then the final multiplication - is vital in mastering the simplification of complex numbers.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.