/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 97 Fill in the missing coordinate i... [FREE SOLUTION] | 91Ó°ÊÓ

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Fill in the missing coordinate in each ordered pair so that the pair is a solution to the given equation. $$y=3^{x}$$ $$(2, \quad),(, 3),(-1, \quad),(\quad, 1 / 9)$$

Short Answer

Expert verified
The completed pairs are (2, 9), (1, 3), (-1, 1/3), and (-2, 1/9).

Step by step solution

01

Complete the pair (2, )

Substitute x = 2 in the equation y = 3^x. \[ y = 3^2 = 9 \]So, the completed pair is (2, 9).
02

Complete the pair (, 3)

Substitute y = 3 in the equation y = 3^x. \[ 3 = 3^x \Rightarrow x = 1 \]So, the completed pair is (1, 3).
03

Complete the pair (-1, )

Substitute x = -1 in the equation y = 3^x. \[ y = 3^{-1} = \frac{1}{3} \]So, the completed pair is (-1, 1/3).
04

Complete the pair (, 1/9)

Substitute y = 1/9 in the equation y = 3^x. \[ \frac{1}{9} = 3^x \Rightarrow 3^{-2} = 3^x \Rightarrow x = -2 \]So, the completed pair is (-2, 1/9).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

solving equations
To solve equations involving exponential functions, it's essential to understand the properties and behavior of these functions. The equation given in the exercise is an exponential function:
y = 3^x

Exponential functions have the general form y = a^x, where a is a positive constant. They grow rapidly for positive x and decay towards zero for negative x.

When solving for specific values, we substitute the given x or y values into the equation and simplify:
  • For y = 3^x with x = 2, calculate y by substituting x: y = 3^2 = 9. So, the ordered pair is (2, 9).
  • For y = 3^x with y = 3, solve for x:
    3 = 3^x → x = 1. Hence, the ordered pair is (1, 3).
It's crucial to use the properties of exponential functions in reversing the exponentiation when needed, such as:
3 = 3^x → x = 1

Also, remember that negative exponents indicate taking the reciprocal, such as 3^{-1} = 1/3.
ordered pairs
Ordered pairs are essentially points on a coordinate plane represented by two values: (x, y). The first value in the pair is the x-coordinate, and the second is the y-coordinate.
  • The pair (2, 9) tells us that when x is 2, y is 9.
  • The pair (1, 3) tells us that when x is 1, y is 3.
To determine a missing value in an ordered pair, you can substitute the known value into the equation:
  • For (2, ), substituting x = 2 we get y = 9.
  • For (, 3), substituting y = 3 we solve x to get 1.
This process helps us find the correct points that satisfy the given equation.
coordinate completion
When completing coordinates, our goal is to find the missing value that makes the pair true for the given equation. Here are the steps:
  • Start with the known value of x or y.
  • Substitute into the equation y = 3^x.
Here are examples from our exercise:
  • For (-1, ), given x = -1, substitute: y = 3^{-1} = 1/3. So, the pair is (-1, 1/3).
  • For (, 1/9), given y = 1/9, we solve: 1/9 = 3^x. Recognize that 1/9 is 3^{-2}, so x = -2. So, the pair is (-2, 1/9).
By understanding the properties of exponential functions, solving for missing coordinates becomes a straightforward task.

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Most popular questions from this chapter

Consider the function \(y=\log \left(10^{n} \cdot x\right)\) where \(n\) is an integer. Use a graphing calculator to graph this function for several choices of \(n .\) Make a conjecture about the relationship between the graph of \(y=\log \left(10^{n} \cdot x\right)\) and the graph of \(y=\log (x) .\) Save your conjecture and attempt to prove it after you have studied the properties of logarithms, which are coming in Section \(4.3 .\) Repeat this exercise with \(y=\log \left(x^{n}\right)\) where \(n\) is an integer.

Find the amount when \(\$ 10,000\) is invested for 5 years and 3 months at \(4.3 \%\) compounded continuously.

Computers per Capita The number of personal computers per 1000 people in the United States from 1990 through 2010 is given in the accompanying table (Consumer Industry Almanac, www.c-i-a.com). a. Use exponential regression on a graphing calculator to find the best- fitting curve of the form \(y=a \cdot b^{x},\) where \(x=0\) corresponds to 1990. b. Write your equation in the form \(y=a e^{e x}.\) c. Assuming that the number of computers per 1000 people is growing continuously, what is the annual percentage rate? d. In what year will the number of computers per 1000 people reach \(1500 ?\) e. Judging from the graph of the data and the curve, does the exponential model look like a good model? $$\begin{array}{|l|c|} \hline \text { Year } & \begin{array}{c} \text { Computers } \\ \text { per 1000 } \end{array} \\ \hline 1990 & 192 \\ 1995 & 321 \\ 2000 & 628 \\ 2005 & 778 \\ 2010 & 932 \\ \hline \end{array}$$

To evaluate an exponential or logarithmic function we simply press a button on a calculator. But what does the calculator do to find the answer? The next exercises show formulas from calculus that are used to evaluate \(e^{x}\) and \(\ln (1+x)\). Infinite Series for \(e^{x}\) The following formula from calculus is used to compute values of \(e^{x}\) : $$e^{x}=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\cdots+\frac{x^{n}}{n !}+\cdots$$ where \(n !=1 \cdot 2 \cdot 3 \cdot \cdots \cdot n\) for any positive integer \(n .\) The notation \(n !\) is read " \(n\) factorial." For example, \(3 !=1 \cdot 2 \cdot 3=6\) In calculating \(e^{x},\) the more terms that we use from the formula, the closer we get to the true value of \(e^{x}\). Use the first five terms of the formula to estimate the value of \(e^{0.1}\) and compare your result to the value of \(e^{0.1}\) obtained using the \(e^{x}-\) key on your calculator.

Solve each equation. Find the exact solutions. $$\log _{3}(2 x)=\log _{3}\left(24-x^{2}\right)$$

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