/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 96 Let \(f(x)=2^{x}, g(x)=(1 / 3)^{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(f(x)=2^{x}, g(x)=(1 / 3)^{x}, h(x)=10^{x},\) and \(m(x)=e^{x} .\) Find the value of \(x\) in each equation. $$m(x)=1$$

Short Answer

Expert verified
x = 0

Step by step solution

01

Understand the equation

We need to solve the equation where the function is given as \(m(x) = e^x\) and the equation is \(e^x = 1\).
02

Use properties of exponents

Recall that \(e^0 = 1\). This means that the exponent must be 0 for the equation \(e^x = 1\) to hold true.
03

Solve for x

Set the exponent equal to 0: \(x = 0\). This is the value of \(x\) that satisfies the equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are a type of mathematical function where the variable appears in the exponent. These functions have the general form of \(f(x) = a^x\), where \(a\) is a constant and \(x\) is the variable. In exponential functions, the base \(a\) is a positive real number. For example, \(f(x) = 2^x\) and \(h(x) = 10^x\) are exponential functions. These functions are often used to model growth or decay processes, such as population growth, radioactive decay, and interest compounding.
One key feature of exponential functions is their rapid rate of change. When the base \(a > 1 \), the function grows very quickly. Conversely, if the base \(0 < a < 1 \), the function decays rapidly as \(x\) increases.
Properties of Exponents
To solve exponential equations, it's essential to understand the properties of exponents. These properties can simplify expressions and equations involving exponential functions. Some important properties include:
  • Product of Powers: \[a^m \times a^n = a^{m+n} \]
  • Quotient of Powers: \[\frac{a^m}{a^n} = a^{m-n} \]
  • Power of a Power: \[(a^m)^n = a^{mn} \]
  • Zero Exponent: \[a^0 = 1 \] for any non-zero \(a\)
  • Negative Exponent: \[(a^{-n}) = \frac{1}{a^n} \]
In our specific example, we used the property \(e^0 = 1\) to solve for the variable.
Recognizing and applying these properties can greatly simplify the process of solving exponential equations.
Solving Exponential Equations
When solving exponential equations, the goal is to isolate the variable in the exponent. Here is a step-by-step method you can follow:
  • 1. Identify the exponential equation: Look for an equation where the variable is in the exponent, such as \[(e^x = 1)\]
  • 2. Use properties of exponents: Apply relevant properties like \(a^0 = 1\) to simplify the equation. In our case, we recognized that \(e^0 = 1\).
  • 3. Isolate the variable: Solve for the variable \(x\) by setting the exponent equal to the corresponding value. For example, if \(e^x = 1\), then \(x = 0\).
  • 4. Check your work: Always verify your solution by substituting back into the original equation. In our case, substituting \(x = 0\) gives \(e^0 = 1\).
By understanding these steps and the underlying properties of exponents, you can effectively solve exponential equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Factor \(3 x-9+w x-3 w\)

Solve each problem. At what interest rate would a deposit of \(\$ 30,000\) grow to \(\$ 2,540,689\) in 40 years with continuous compounding?

Solve each problem. Because of the Black Death, or plague, the only substantial period in recorded history when the earth's population was not increasing was from 1348 to \(1400 .\) During that period the world population decreased by about 100 million people. Use the exponential model \(P=P_{0} e^{r t}\) and the data from the accompanying table to find the annual growth rate for the period 1400 to 2000 . If the 100 million people had not been lost, then how many people would they have grown to in 600 years using the growth rate that you just found? $$\begin{array}{|c|c|}\hline \text { Year } & \begin{array}{c}\text { World } \\\\\text { Population }\end{array} \\\\\hline 1348 & 0.47 \times 10^{9} \\\1400 & 0.37 \times 10^{9} \\\1900 & 1.60 \times 10^{9} \\\2000 & 6.07 \times 10^{9} \\\\\hline\end{array}$$

To evaluate an exponential or logarithmic function we simply press a button on a calculator. But what does the calculator do to find the answer? The next exercises show formulas from calculus that are used to evaluate \(e^{x}\) and \(\ln (1+x)\). Infinite Series for \(e^{x}\) The following formula from calculus is used to compute values of \(e^{x}\) : $$e^{x}=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\cdots+\frac{x^{n}}{n !}+\cdots$$ where \(n !=1 \cdot 2 \cdot 3 \cdot \cdots \cdot n\) for any positive integer \(n .\) The notation \(n !\) is read " \(n\) factorial." For example, \(3 !=1 \cdot 2 \cdot 3=6\) In calculating \(e^{x},\) the more terms that we use from the formula, the closer we get to the true value of \(e^{x}\). Use the first five terms of the formula to estimate the value of \(e^{0.1}\) and compare your result to the value of \(e^{0.1}\) obtained using the \(e^{x}-\) key on your calculator.

Find the approximate solution to each equation. Round to four decimal places. $$\frac{1}{e^{x-1}}=5$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.