Chapter 4: Problem 44
Sketch the graph of each function, and state the domain and range of each function. $$f(x)=4-\log (x+6)$$
Short Answer
Expert verified
Domain: \(x > -6\). Range: \(( -\infty, \infty )\).
Step by step solution
01
Understand the basic function
The given function is a logarithmic function transformed. Start with the basic log function: \(f(x) = \log(x)\).
02
Apply horizontal shift
Identify the horizontal shift in the function: \(f(x) = \log(x+6)\). This shifts the graph 6 units to the left.
03
Apply vertical shift
The function given is \(f(x) = 4 - \log(x+6)\). Rewriting this, we observe a vertical shift. This can be written as: \(f(x) = - \log(x+6) + 4\). This means the graph of \(\log(x+6)\) is vertically shifted up by 4 units and reflected across the x-axis.
04
Determine the domain
The domain of a logarithmic function \(\log(x+6)\) is determined by the inside of the log being greater than 0. So, \(x + 6 > 0\) which simplifies to \(x > -6\).
05
Determine the range
Since a basic log function spans all real numbers in its range and reflecting it does not alter this property, the range of the function remains all real numbers \((-\backslashinfty, \backslashinfty)\).
06
Sketch the graph
Plot points for the function considering the transformations: shift left by 6 units, reflect across the x-axis, and shift up by 4 units. The vertical asymptote will be at \(x = -6\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
domain and range
Understanding the domain and range of a logarithmic function is crucial when graphing transformations. The domain refers to all the possible input values (x-values) for which the function is defined. For the function \(f(x) = 4 - \log(x+6)\), we want the inside of the logarithm to be greater than 0, which means \(x + 6 > 0\) or \(x > -6\). Therefore, the domain is \[(-6, \infty)\].
The range, on the other hand, is the set of all possible output values (y-values). Since the basic log function \log(x)\ spans all real numbers in its range, and the transformations applied in the given function (reflection across the x-axis and vertical shift) do not change this property, the range consists of all real numbers, \((-\infty, \infty)\).
The range, on the other hand, is the set of all possible output values (y-values). Since the basic log function \log(x)\ spans all real numbers in its range, and the transformations applied in the given function (reflection across the x-axis and vertical shift) do not change this property, the range consists of all real numbers, \((-\infty, \infty)\).
horizontal shift
Horizontal shifts in logarithmic functions can significantly impact the shape and position of their graphs. A horizontal shift occurs when the input variable x is adjusted by adding or subtracting a constant. For the function \(f(x) = \log(x+6)\), the graph is shifted 6 units to the left due to the \(+6\) inside the log. This shift means that every point on the basic log function \(\log(x)\) is moved 6 units to the left along the x-axis.
Horizontal shifts do not change the range of the function but do alter its domain, which for this function moves from \((0, \infty)\) in the basic log graph to \[(-6, \infty)\]. This leftward shift also shifts the vertical asymptote from \(x=0\) to \(x=-6\).
Horizontal shifts do not change the range of the function but do alter its domain, which for this function moves from \((0, \infty)\) in the basic log graph to \[(-6, \infty)\]. This leftward shift also shifts the vertical asymptote from \(x=0\) to \(x=-6\).
vertical shift
Vertical shifts modify the graph of a function by moving it up or down along the y-axis. For the given function \(f(x) = 4 - \log(x+6)\), we observe a vertical shift because of the constant \(+4\) added to the term \(-\log(x+6)\). Rewriting the function as \(f(x) = -\log(x+6) + 4\) shows more clearly that it reflects the \log(x+6)\ function across the x-axis and then shifts it up by 4 units.
This vertical shift impacts the y-values of the function, moving every point on the graph upwards by 4 units. Consequently, the horizontal asymptote of the transformed function, originally at y=0 in the basic log function, moves up to y=4.
This vertical shift impacts the y-values of the function, moving every point on the graph upwards by 4 units. Consequently, the horizontal asymptote of the transformed function, originally at y=0 in the basic log function, moves up to y=4.
graphing functions
Graphing the function \(f(x) = 4 - \log(x+6)\) involves a few specific steps that incorporate all previously discussed transformations. Here's how you can sketch the graph step-by-step:
- Start with the basic log function \(\log(x)\).
- Apply the horizontal shift leftward by 6 units to get the graph of \(\log(x+6)\).
- Reflect the graph across the x-axis to obtain \(-\log(x+6)\).
- Finally, apply the vertical shift upward by 4 units, resulting in \(f(x) = -\log(x+6) + 4\).