/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Find the indicated value of the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indicated value of the logarithmic functions. $$\log _{16}(16)$$

Short Answer

Expert verified
1

Step by step solution

01

Understand the Logarithmic Function

Recognize that \( \log_{b}(b) = 1 \) for any base \( b \) because any number raised to the power 1 equals itself.
02

Apply the Property

In this case, the base is 16 and the value inside the logarithm is also 16. Therefore, applying the property gives us: \( \log_{16}(16) = 1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithm properties
To fully understand logarithmic functions, it's essential to know the basic properties of logarithms. These properties simplify complex calculations and help solve logarithmic equations. Here are some key properties:

* **Product Property**: The logarithm of a product is the sum of the logarithms of the factors. Mathematically, \(\text{log}_{b}(xy) = \text{log}_{b}(x) + \text{log}_{b}(y)\).
* **Quotient Property**: The logarithm of a quotient is the difference between the logarithms of the numerator and the denominator. It can be written as \(\text{log}_{b}\frac{x}{y} = \text{log}_{b}(x) - \text{log}_{b}(y)\).
* **Power Property**: The logarithm of a number raised to an exponent is the exponent times the logarithm of the base number. This is expressed as \(\text{log}_{b}(x^y) = y \text{log}_{b}(x)\).
* **Change of Base Formula**: Any logarithm can be converted to a different base using the formula \(\text{log}_{b}(x) = \frac{\text{log}_{c}(x)}{\text{log}_{c}(b)}\), where `c` is the new base.

Let's take a closer look at the special property that was used in the exercise: \(\text{log}_{b}(b) = 1\). This property states that the logarithm of a base `b` to itself is always 1.
base of logarithm
The base of a logarithm is a crucial part of understanding how logarithms work. It is the number that we raise to a certain power in order to obtain the argument of the logarithm.

For example, in \(\text{log}_{2}(8)\), the base is 2. We want to find out to what power we need to raise 2 to get 8. In this case, \(\text{log}_{2}(8) = 3\), because \({2}^{3}= 8\).

Common bases include:
* **Base 10**: Known as the common logarithm and often written as \(\text{log}(x)\) without any base.
* **Base e**: Known as the natural logarithm, typically written as \(\text{ln}(x)\). The number `e` (approximately 2.718) is an important mathematical constant in many fields.
* **Base 2**: Commonly used in computer science and information theory.

In the problem \(\text{log}_{16}(16)\), the base and the argument are both 16. Using the property that \(\text{log}_{b}(b) = 1\), we find that \(\text{log}_{16}(16) = 1\). Understanding the base helps in easily applying this property.
evaluating logarithms
Evaluating logarithms means finding the power to which the base must be raised to produce a given number. Here are some steps and tips to help evaluate logarithms:

1. **Recognize the Form**: Identify the base `b` and the argument (the number inside the logarithm). For example, in \(\text{log}_{2}(32)\), the base is 2, and the argument is 32.
2. **Rewrite the Logarithmic Equation**: Convert the logarithm into an exponential form. Using the example \(\text{log}_{2}(32)\), rewrite it as \({2}^{x}= 32\).
3. **Solve for the Exponent**: Determine the power `x` needed so that when the base is raised to this power, it equals the argument. For \({2}^{x}= 32\), since \({2}^{5}= 32\), \(\text{log}_{2}(32) = 5\).
4. **Use Properties of Logarithms**: Employ properties such as the product, quotient, and power properties to break down more complex logarithms into simpler parts you can evaluate.

When dealing with simple cases like \(\text{log}_{16}(16)\), recognize that the base and argument are the same. This immediately tells you, by the property \(\text{log}_{b}(b) = 1\), the result is 1.

Practicing these steps will greatly improve your skill in evaluating logarithms, making them less intimidating and more intuitive.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Crude Oil Prices The average cost in dollars of a barrel of domestic crude oil for each year from 2000 to 2008 is shown in the accompanying table (www.inflationdata.com). $$\begin{array}{|c|c|} \hline \text { Year } & \begin{array}{c} \text { Cost } \\ \text { per Barrel } \end{array} \\ \hline 2000 & 27 \\ 2001 & 23 \\ 2002 & 23 \\ 2003 & 28 \\ 2004 & 38 \\ 2005 & 50 \\ 2006 & 58 \\ 2007 & 64 \\ 2008 & 130 \\ \hline \end{array}$$ a. Use exponential regression on a graphing calculator to find the best- fitting curve of the form \(y=a \cdot b^{x},\) where \(x=0\) corresponds to 2000 b. Use the exponential model from part (a) to predict the average price of a barrel of domestic crude in 2015 .

Marginal Revenue The revenue in dollars from the sale of \(x\) items is given by the function \(R(x)=500 \cdot \log (x+1) .\) The marginal revenue function \(M R(x)\) is the difference quotient for \(R(x)\) when \(h=1 .\) Find \(M R(x)\) and write it as a single logarithm. What happens to the marginal revenue as \(x\) gets larger and larger?

To evaluate an exponential or logarithmic function we simply press a button on a calculator. But what does the calculator do to find the answer? The next exercises show formulas from calculus that are used to evaluate \(e^{x}\) and \(\ln (1+x)\). Infinite Series for \(e^{x}\) The following formula from calculus is used to compute values of \(e^{x}\) : $$e^{x}=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\frac{x^{4}}{4 !}+\cdots+\frac{x^{n}}{n !}+\cdots$$ where \(n !=1 \cdot 2 \cdot 3 \cdot \cdots \cdot n\) for any positive integer \(n .\) The notation \(n !\) is read " \(n\) factorial." For example, \(3 !=1 \cdot 2 \cdot 3=6\) In calculating \(e^{x},\) the more terms that we use from the formula, the closer we get to the true value of \(e^{x}\). Use the first five terms of the formula to estimate the value of \(e^{0.1}\) and compare your result to the value of \(e^{0.1}\) obtained using the \(e^{x}-\) key on your calculator.

Find the approximate solution to each equation. Round to four decimal places. $$\frac{1}{10^{x}}=2$$

Depreciation and Inflation Boris won a \(\$ 35,000\) luxury car on Wheel of Fortune. He plans to keep it until he can trade it evenly for a new compact car that currently costs \(\$ 10,000\). If the value of the luxury car decreases by \(8 \%\) each year and the cost of the compact car increases by \(5 \%\) each year, then in how many years will he be able to make the trade?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.