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Solve each problem. Solve the equation \(A=P e^{n t}\) for \(r,\) then find the rate at which a deposit of \(\$ 1000\) would double in 3 years compounded continuously.

Short Answer

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Step by step solution

01

Identify the given variables

The given equation is
02

Solve the equation for r

We start with the equation We need to solve for .
03

Input the given values

We need to find the rate at which deposit of } will double in .
04

Solve logorithmically

We need to take the ln() of the equation which will be
05

Solve for r

Subsitute known vales into the equation and solve for r which results to

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth

Exponential growth is a process where a quantity increases over time at a rate proportional to its current value. This means the larger the quantity, the faster it grows. The function for exponential growth can be expressed as:


\( A = P e^{rt} \)


  • \( A \) is the amount of money accumulated after time \( t \)
  • \( P \) is the principal amount (initial investment)
  • \( r \) is the annual interest rate
  • \( t \) is the time in years
  • \( e \) is the base of the natural logarithm, approximately equal to 2.71828

This formula is particularly relevant to problems involving continuously compounded interest.

Natural Logarithm

The natural logarithm, denoted as \( \ln \), is the logarithm to the base \( e \). It's a fundamental concept in mathematics, especially in calculus and exponential growth equations. The natural logarithm of a number \( x \) gives the power to which \( e \) must be raised to obtain \( x \). Mathematically, if \( y = \ln(x) \), then \( e^y = x \).


For example, to solve the equation \( A = P e^{rt} \) for \( r \), we can take the natural logarithm of both sides to make it manageable:


\( \ln(A) = \ln(P) + rt \)


  • Using the logarithmic rules makes it easier to isolate the variable \( r \).
  • Once \( r \) is isolated, we can solve for it using algebraic methods.
  • This step is crucial in problems involving continuous compounding.
Solving Equations

In this context, solving equations involves isolating the variable of interest. Here are the steps to solve the exponential growth problem:


  • Identify the given variables: We start with the equation \( A = P e^{rt} \).
  • Substitute known values: Since the amount doubles, \( A = 2P \). For a principal amount of \$1000 doubling in 3 years, we have \( 2P = P e^{3r} \).
  • Use natural logarithms: Divide both sides by \( P \), giving \( 2 = e^{3r} \). Taking the natural logarithm of both sides, we get \( \ln(2) = 3r \).
  • Solve for \( r \): Finally, isolate \( r \) by dividing both sides by 3: \( r = \frac{\ln(2)}{3} = 0.23105 \approx 23.11\% \)

This process helps in understanding how to handle problems involving continuous compounding and exponential relationships.

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Most popular questions from this chapter

Computers per Capita The number of personal computers per 1000 people in the United States from 1990 through 2010 is given in the accompanying table (Consumer Industry Almanac, www.c-i-a.com). a. Use exponential regression on a graphing calculator to find the best- fitting curve of the form \(y=a \cdot b^{x},\) where \(x=0\) corresponds to 1990. b. Write your equation in the form \(y=a e^{e x}.\) c. Assuming that the number of computers per 1000 people is growing continuously, what is the annual percentage rate? d. In what year will the number of computers per 1000 people reach \(1500 ?\) e. Judging from the graph of the data and the curve, does the exponential model look like a good model? $$\begin{array}{|l|c|} \hline \text { Year } & \begin{array}{c} \text { Computers } \\ \text { per 1000 } \end{array} \\ \hline 1990 & 192 \\ 1995 & 321 \\ 2000 & 628 \\ 2005 & 778 \\ 2010 & 932 \\ \hline \end{array}$$

Visual Magnitude of a Star If all stars were at the same distance, it would be a simple matter to compare their brightness. However, the brightness that we see, the apparent visual magnitude \(m,\) depends on a star's intrinsic brightness, or absolute visual magnitude \(M_{V},\) and the distance \(d\) from the observer in parsecs ( 1 parsec \(=3.262\) light years), according to the formula \(m=M_{V}-5+5 \cdot \log (d) .\) The values of \(M_{V}\) range from \(-8\) for the intrinsically brightest stars to \(+15\) for the intrinsically faintest stars. The nearest star to the sun, Alpha Centauri, has an apparent visual magnitude of 0 and an absolute visual magnitude of 4.39 . Find the distance \(d\) in parsecs to Alpha Centauri.

Which exponential and logarithmic functions are increasing? Decreasing? Is the inverse of an increasing function increasing or decreasing? Is the inverse of a decreasing function increasing or decreasing? Explain.

Factor \(3 x-9+w x-3 w\)

Room Temperature Marlene brought a can of polyurethane varnish that was stored at \(40^{\circ} \mathrm{F}\) into her shop, where the temperature was \(74^{\circ} .\) After 2 hr the temperature of the varnish was \(58^{\circ} .\) If the varnish must be \(68^{\circ}\) for best results, then how much longer must Marlene wait until she uses the varnish?

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