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Find the approximate solution to each equation. Round to four decimal places. $$e^{x}=2$$

Short Answer

Expert verified
0.6931

Step by step solution

01

Understand the equation

The given equation is an exponential equation: \( e^{x} = 2 \). Our goal is to find the value of \( x \) that makes this equation true.
02

Take the natural logarithm of both sides

To solve for \( x \), take the natural logarithm (ln) of both sides of the equation:\[ \ln(e^{x}) = \ln(2) \]
03

Simplify using logarithm properties

Utilize the property of logarithms: \( \ln(e^{x}) = x \cdot \ln(e) \). Since \( \ln(e) = 1 \), the equation simplifies to:\[ x = \ln(2) \]
04

Calculate the natural logarithm

Use a calculator or a logarithm table to find the value of \( \ln(2) \). Make sure to round the result to four decimal places. The approximate value is:\[ x \approx 0.6931 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, denoted as \(\text{ln}\), is a logarithm to the base \(e\), where \(e\) is an irrational and transcendental number approximately equal to 2.71828. It is widely used in mathematics due to its unique properties that simplify many calculations involving exponential functions. The natural logarithm answers the question: 'To what power must \(e\) be raised to yield a given number?' For instance, in the equation \(e^{x} = 2\), taking the natural logarithm of both sides helps us find the exponent \(x\). By using \(\text{ln}(e^{x})\), we simplify our calculation thanks to the relationship \(\text{ln}(e^{x}) = x\cdot \text{ln}(e)\). Knowing that \(\text{ln}(e) = 1\), the equation \(e^{x}=2\) reduces to \(x=\text{ln}(2)\).
Logarithm Properties
Logarithms have several important properties that are crucial for solving equations involving exponential functions. These properties simplify the manipulation and transformation of equations. Some key properties include:
  • Product Property: \(\text{log}_{b}(xy) = \text{log}_{b}(x) + \text{log}_{b}(y)\)

  • Quotient Property: \(\text{log}_{b}(\frac{x}{y}) = \text{log}_{b}(x) - \text{log}_{b}(y)\)

  • Power Property: \(\text{log}_{b}(x^{y}) = y\cdot \text{log}_{b}(x)\)

  • Change of Base Formula: \(\text{log}_{b}(x) = \frac{\text{log}_{k}(x)}{\text{log}_{k}(b)}\) for any base \(k\)
The power property is particularly useful for equations in the form \(e^{x}=2\). Applying the natural logarithm, we use the property \(\text{ln}(e^{x}) = x\cdot \text{ln}(e)\). This property allows us to move the exponent in front of the logarithm, turning it into a simple multiplication that can be easily evaluated since \(\text{ln}(e)=1\).
Solving Equations
When solving exponential equations, our goal is to isolate the variable, usually found in the exponent. Let’s walk through the solution using the example \(e^{x} = 2\):
  • Step 1: Recognize that we have an exponential equation where the base is \(e\).

  • Step 2: Apply the natural logarithm to both sides of the equation: \(\text{ln}(e^x) = \text{ln}(2)\).

  • Step 3: Use the logarithm property \(\text{ln}(e^x) = x\cdot\text{ln}(e)\). Since \(\text{ln}(e) = 1\), this simplifies to \(x = \text{ln}(2)\).

  • Step 4: Find the numerical value of \(\text{ln}(2)\) using a calculator, which gives approximately 0.6931, rounded to four decimal places.

Therefore, the solution to the equation \(e^x = 2\) is \(x \approx 0.6931\). This example demonstrates how logarithms, especially natural logarithms, are powerful tools for solving exponential equations effectively.

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