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Find all real solutions to each equation. Check your answers. $$w^{-4 / 3}=16$$

Short Answer

Expert verified
The real solution is \(w = \frac{1}{8}\).

Step by step solution

01

Isolate the Exponent

Identify the given equation, which is \(w^{-4/3} = 16\). The goal is to isolate the term containing the variable.
02

Remove the Negative Exponent

Rewrite the equation to get rid of the negative exponent. Recall that \(w^{-4/3} = \frac{1}{w^{4/3}}\). So, the equation becomes \(\frac{1}{w^{4/3}} = 16\).
03

Invert Both Sides

Multiply both sides of the equation by \(w^{4/3}\) to isolate it: \(1 = 16 \times w^{4/3}\). Then, divide both sides by 16: \(w^{4/3} = \frac{1}{16}\).
04

Solve for the Base Variable

To find \(w\), raise both sides of the equation to the power of \(\frac{3}{4}\). This cancels out the current exponent on \(w\): \[w = \bigg(\frac{1}{16}\bigg)^{\frac{3}{4}}\].
05

Simplify the Expression

Simplify the right-hand side: \(\frac{1}{16} = 16^{-1}\), so \[w = \big(16^{-1}\big)^{\frac{3}{4}} = 16^{-\frac{3}{4}}\].
06

Calculate the Final Value

Calculate the final value. Since \(16 = 2^4\), \(16^{-\frac{3}{4}} = (2^4)^{-\frac{3}{4}} = 2^{-3}\), which results in \(\frac{1}{8}\). Therefore, \[w = \frac{1}{8}\].
07

Check the Solution

Substitute \(w = \frac{1}{8}\) back into the original equation to verify: \(\bigg(\frac{1}{8}\bigg)^{-4/3} = 16\). Converting \(\frac{1}{8} = 2^{-3}\), \(\big( 2^{-3} \big)^{-4/3} = 2^{4} = 16\), which confirms our solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

negative exponents
Negative exponents can initially seem challenging, but they're just another way to express the reciprocal of a base raised to a positive exponent. When you see something like \( a^{-n} \), it translates to \( \frac{1}{a^n} \). For example, \( w^{-4/3} = \frac{1}{w^{4/3}} \). Understanding this concept helps in transforming equations into a more familiar form, making them easier to solve. Always remember, flipping the fraction is key to solving negative exponents.

To practice, start with simple examples. Rewrite \( 5^{-2} \) as \( \frac{1}{5^2} = \frac{1}{25} \). Get comfortable with these conversions, as they form fundamental steps in solving more complex equations.
isolating variables
Isolating the variable means getting the variable on one side of the equation, usually by itself. This often involves reversing the operations applied to the variable. For instance, given \( w^{-4/3} = 16 \), the term \( w^{-4/3} \) includes the variable we want to solve for. To isolate it, work to eliminate other elements through mathematical operations such as multiplication, division, or exponentiation.

Following our example, we first rewrite the negative exponent: \( \frac{1}{w^{4/3}} = 16 \). Next, we need to isolate \( w^{4/3} \). Multiply both sides of the equation by \( w^{4/3} \): \( 1 = 16w^{4/3} \). Finally, divide both sides by 16: \( w^{4/3} = \frac{1}{16} \). By systematically isolating the variable, solving equations becomes straightforward.
exponentiation
Exponentiation is a critical mathematical operation where a number (the base) is raised to a power (the exponent). This operation is concise and powerful, especially in equations involving variables. Consider the step where we solved for \( w \) by raising both sides to the power of \( \frac{3}{4} \): \( w^{4/3} = \frac{1}{16} \). To counter the \( 4/3 \) exponent on \( w \), both sides are raised to \( \frac{3}{4} \), resulting in \( w = \left( \frac{1}{16} \right)^{3/4} \).

Simplify further by recognizing that \( \frac{1}{16} \) is \( 16^{-1} \). Therefore, \( \big(16^{-1}\big)^{3/4} \) becomes \( 16^{-3/4} \). Also, remember that \( 16 = 2^4 \). So, we have \( 16^{-3/4} = (2^4)^{-3/4} = 2^{-3} = \frac{1}{8} \). Thus, \( w = \frac{1}{8} \).

Practicing exponentiation with different bases and exponents can build your algebra proficiency. Try raising fractions or decimals to various powers and simplifying the expressions to develop a deeper understanding of exponentiation.

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