Chapter 3: Problem 15
Write each quadratic function in the form \(y=a(x-h)^{2}+k\) and sketch its graph. $$y=-3 x^{2}+6 x-3$$
Short Answer
Expert verified
The vertex form of the function is \(y = -3(x - 1)^2\). The vertex is at \( (1, 0)\) and the parabola opens downwards.
Step by step solution
01
Identify coefficients
For the quadratic function given by the equation \(y = -3x^2 + 6x - 3\), identify the coefficients. Here, \(a = -3\), \(b = 6\), and \(c = -3\).
02
Complete the square
To convert the quadratic equation into vertex form, \(y = a(x-h)^2 + k\), we need to complete the square.First, factor out the coefficient of \(x^2\) from the quadratic and linear terms: \(y = -3(x^2 - 2x) - 3\).Next, to complete the square inside the parenthesis, take half of the linear coefficient (\(-2\)), square it, and add & subtract this inside the parenthesis:\(y = -3(x^2 - 2x + 1 - 1) - 3 = -3((x - 1)^2 - 1) - 3\).
03
Simplify the expression
Distribute the \(-3\) and combine constants:\(y = -3(x - 1)^2 + 3 - 3\).Simplifying this gives:\(y = -3(x - 1)^2\).
04
Identify vertex form and graph
The function is now in vertex form \(y = a(x - h)^2 + k\) where \(h = 1\) and \(k = 0\). This corresponds to a vertex at \((1, 0)\).Since \(a = -3\), the parabola opens downwards and is stretched by a factor of 3.
05
Sketch the graph
Plot the vertex \((1, 0)\). Because the parabola opens downwards (as \(a = -3\)) and is stretched, plot points on either side of the vertex accordingly. Sketch the parabolic curve through these points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
completing the square
Completing the square is a method used to convert a quadratic equation into its vertex form. This is helpful for easy graphing and understanding properties of the parabola.
To complete the square for the quadratic function:
1. Start with the equation: \( y = -3x^2 + 6x - 3 \).
2. Factor out the coefficient of \( x^2 \) from the first two terms: \( y = -3(x^2 - 2x) - 3 \).
3. Take half of the linear term's coefficient (\b) squared and add and subtract it inside the parenthesis: \( y = -3(x^2 - 2x + 1 - 1) - 3 \).
4. Simplify, group the perfect square inside the parenthesis, and distribute the constant: \( y = -3((x - 1)^2 - 1) - 3\).
5. Finally, combine constants to get the vertex form: \( y = -3(x - 1)^2 + 3 - 3 \), which simplifies to \( y = -3(x-1)^2 \).
Using this method, the equation is transformed into a form that easily reveals the vertex of the parabola.
To complete the square for the quadratic function:
1. Start with the equation: \( y = -3x^2 + 6x - 3 \).
2. Factor out the coefficient of \( x^2 \) from the first two terms: \( y = -3(x^2 - 2x) - 3 \).
3. Take half of the linear term's coefficient (\b) squared and add and subtract it inside the parenthesis: \( y = -3(x^2 - 2x + 1 - 1) - 3 \).
4. Simplify, group the perfect square inside the parenthesis, and distribute the constant: \( y = -3((x - 1)^2 - 1) - 3\).
5. Finally, combine constants to get the vertex form: \( y = -3(x - 1)^2 + 3 - 3 \), which simplifies to \( y = -3(x-1)^2 \).
Using this method, the equation is transformed into a form that easily reveals the vertex of the parabola.
vertex form of a quadratic function
The vertex form of a quadratic function is \(y = a(x-h)^2 + k\). This form is beneficial because it clearly shows the vertex \((h, k)\) and the direction the parabola opens.
The quadratic function we started with, \( y = -3x^2 + 6x - 3 \), has been converted to vertex form: \( y = -3(x-1)^2 \). This indicates:
Using the vertex form allows us to quickly identify transformations from the base parabola \( y = x^2 \), such as reflections, translations, and dilations.
The quadratic function we started with, \( y = -3x^2 + 6x - 3 \), has been converted to vertex form: \( y = -3(x-1)^2 \). This indicates:
- The vertex \( (h, k)\) is at \( (1, 0)\).
- The coefficient \( a = -3 \) means the parabola opens downwards and is vertically stretched by a factor of 3.
Using the vertex form allows us to quickly identify transformations from the base parabola \( y = x^2 \), such as reflections, translations, and dilations.
graphing parabolas
Graphing a parabola is straightforward once it is in vertex form: \( y = a(x-h)^2 + k \).
For the quadratic function \( y = -3(x-1)^2 \), follow these steps:
By following these steps, you can accurately sketch the graph of \( y = -3(x-1)^2 \). The process reveals the transformation applied to the basic \( y = x^2 \) parabola to obtain the desired shape.
For the quadratic function \( y = -3(x-1)^2 \), follow these steps:
- Identify the vertex: here it is \( (1, 0) \).
- Determine the direction the parabola opens: since \( a = -3 \), it opens downward.
- Consider the vertical stretch factor: here, the stretch factor is 3, making the parabola narrower than \( y = x^2 \).
- Plot the vertex and additional points around it to visualize the shape.
- Use symmetry about the vertex to plot corresponding points on either side.
By following these steps, you can accurately sketch the graph of \( y = -3(x-1)^2 \). The process reveals the transformation applied to the basic \( y = x^2 \) parabola to obtain the desired shape.