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Define \(y_{1}=\sqrt{x+1}\) and \(y_{2}=3 x-4\) on your graphing calculator. For each function \(y_{3},\) defined in terms of \(y_{1}\) and \(y_{2}\) determine the domain and range of \(y_{3}\) from its graph on your calculator and explain what each graph illustrates. $$y_{3}=\sqrt{y_{2}+1}$$

Short Answer

Expert verified
Domain: \[ [1, \text{inf}) \]. Range: \[ [0, \text{inf}) \]. Graph starts at (1,0) and increases without bound.

Step by step solution

01

Define the Functions

Input the functions into the graphing calculator: 1. Define the first function as \[ y_1 = \text{sqrt}(x + 1) \] 2. Define the second function as \[ y_2 = 3x - 4 \]
02

Define the Composite Function

Define the function: \[ y_3 = \text{sqrt}(y_2 + 1) \]Since we have defined both \( y_1 \) and \( y_2 \), now update the calculator to define \( y_3 \) as \[ y_3 = \text{sqrt}(3x - 3) \]
03

Find the Domain for \( y_2 \)

Determine the domain of \(y_2 = 3x - 4\): - \(y_2\) is a linear function, so it is defined for all real numbers.Therefore, the domain of \( y_2 \) is \[ (-\text{inf}, \text{inf}) \]
04

Find the Domain for \( y_3 \)

Determine the domain of \(y_3\): \( y_3 = \text{sqrt}(3x - 3) \). For the expression inside the square root to be non-negative: \[ 3x - 3 \text{ must be} \geq 0 \] Solve the inequality:\[ 3x - 3 \geq 0 \Rightarrow x \geq 1 \].Thus, the domain of \( y_3 \) is \[ [1, \text{inf}) \]
05

Find the Range for \( y_3 \)

Determine the range of \(y_3\): Since \( y_3 \) is defined as the square root function \( \text{sqrt}(u) \), the range will be all non-negative values of \(u\), thus \( y_3 = \text{sqrt}(3x - 3) \geq 0 \).Since \( x \geq 1 \), \( y_3 \geq \text{sqrt}(0) = 0 \).Therefore, the range of \( y_3 \) is \[ [0, \text{inf}) \]
06

Interpret the Graph

Explain what the graph illustrates: - The graph of \( y_3 \) starts at \( x = 1 \) (since \( 3(1) - 3 = 0 \)) and for \( x > 1 \), \( y_3 \) increases.It shows a continuous curve starting at the point \( (1,0) \) and increasing without upper bound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
Understanding domain and range is essential when dealing with functions. The **domain** of a function is the set of all possible input values (x-values) that the function can accept. For example, the domain of the linear function \( y_2 = 3x - 4 \) is all real numbers, which we write as \( (-\infty, \infty) \). This is because a linear function, like a straight line, extends indefinitely in both directions.

The **range** is the set of all possible output values (y-values) produced by the function. To find the range, we consider the function's behavior. For the composite function \( y_3 = \sqrt{y_2 + 1} \), first, we note that \( y_3 \) must be non-negative since a square root cannot produce a negative number. Hence, the range for the square root function starts from zero and increases: \( [0, \infty) \).

Understanding domain and range helps in accurately depicting and analyzing functions, whether simple or composite.
Graphing Calculator
A graphing calculator is an invaluable tool for visualizing mathematical functions. By helping you input functions and view their graphs, it gives a real-time look at how the functions behave.

In our exercise, we first define the functions:
  • \( y_1 = \sqrt{x + 1} \)
  • \( y_2 = 3x - 4 \)
Next, we use the calculator to define the composite function \( y_3 = \sqrt{y_2 + 1} \). When you graph these functions, it becomes easier to understand the relationship between them and visually interpret the domain and range.

Using a graphing calculator simplifies complex calculations and offers a visual representation, aiding in deeper comprehension.
Square Root Function
The square root function, represented as \( y = \sqrt{x} \), is a common mathematical function. It only produces non-negative results because it represents the principal (positive) square root.

For instance, in our exercise where \( y_3 = \sqrt{y_2 + 1} \), the function requires that the expression within the square root, \( y_2 + 1 \), be zero or greater. Thus, solving for this gives the domain constraints for \( y_3 \).

To solve:
  • Set the expression inside the square root to be non-negative: \( 3x - 3 \geq 0 \)
  • This results in \( x \geq 1 \)
Consequently, the domain of \( y_3 \) is \( [1, \infty) \).

The range of the square root function starts from zero and extends to infinity, reflecting that it only produces non-negative outputs: \( [0, \infty) \).
Linear Function
A linear function is represented as \( y = mx + b \), where **m** is the slope and **b** is the y-intercept. Linear functions graph as straight lines and possess a domain and range of all real numbers, given they extend indefinitely in both directions.

For example, consider \( y_2 = 3x - 4 \):
  • The slope (**m**) is 3, indicating the line rises 3 units for every unit increase in x.
  • The y-intercept (**b**) is -4, meaning the line crosses the y-axis at (0, -4).
Since \( y_2 \) is linear, its domain is \( (-\infty, \infty) \).

When composing functions, understanding linear functions helps precisely predict the behavior of composite functions like \( y_3 = \sqrt{3x - 3} \).

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