Chapter 1: Problem 80
Evaluate the expression \(\frac{-b+\sqrt{b^{2}-4 a c}}{2 a}\) for each choice of \(a, b\) and \(c\) $$a=5, b=-4, c=1$$
Short Answer
Expert verified
0.4 + 0.2i
Step by step solution
01
Identify the values
Given the values are: \(a = 5\), \(b = -4\), and \(c = 1\).
02
Substitute the values into the expression
Substitute \(a\), \(b\), and \(c\) into the quadratic formula \(\frac{-b+\sqrt{b^{2}-4ac}}{2a}\).So, it becomes: \(\frac{-(-4) + \sqrt{(-4)^{2} - 4(5)(1)}}{2(5)}\)
03
Simplify inside the square root
Calculate the expression inside the square root:\((-4)^{2} - 4(5)(1) = 16 - 20 = -4\)
04
Evaluate the square root
The expression inside the square root is negative, so: \(\sqrt{-4}=2i\)
05
Simplify the expression
Separate the expression into real and imaginary parts:\(\frac{4 + 2i}{10}\)
06
Final simplification
Divide both real and imaginary parts by 10: \(\frac{4}{10} + \frac{2i}{10} = 0.4 + 0.2i\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Numbers
Imaginary numbers arise when we need to take the square root of a negative number. In the real number system, this isn't possible, so mathematicians introduced a new number, which they call 'i'.
'i' is defined as \(i = \sqrt{-1}\).
The key property of 'i' is that \(i^2 = -1\).
This allows us to express the square root of any negative number as some multiple of 'i'. For example, \(\sqrt{-4} = 2i\) because \(\sqrt{-4} = \sqrt{4 \cdot (-1)} = \sqrt{4} \cdot \sqrt{-1} = 2i\).
In practice, whenever you see a negative number under a square root, you can convert it into an imaginary number using these properties.
'i' is defined as \(i = \sqrt{-1}\).
The key property of 'i' is that \(i^2 = -1\).
This allows us to express the square root of any negative number as some multiple of 'i'. For example, \(\sqrt{-4} = 2i\) because \(\sqrt{-4} = \sqrt{4 \cdot (-1)} = \sqrt{4} \cdot \sqrt{-1} = 2i\).
In practice, whenever you see a negative number under a square root, you can convert it into an imaginary number using these properties.
Complex Numbers
Complex numbers extend the idea of imaginary numbers to include both real and imaginary parts. A complex number has the form \(a + bi\), where 'a' and 'b' are real numbers, and 'i' is the imaginary unit.
In the quadratic formula exercise, the final solution was \(0.4 + 0.2i\).
Here, '0.4' is the real part and '0.2i' is the imaginary part.
Complex numbers can be added, subtracted, and multiplied. For instance:
In the quadratic formula exercise, the final solution was \(0.4 + 0.2i\).
Here, '0.4' is the real part and '0.2i' is the imaginary part.
Complex numbers can be added, subtracted, and multiplied. For instance:
- \((a + bi) + (c + di) = (a+c) + (b+d)i\)
- \((a + bi) - (c + di) = (a-c) + (b-d)i\)
- \((a + bi)(c + di) = (ac - bd) + (ad + bc)i\)
Simplification
Simplification involves rewriting an expression in a simpler or more aesthetically pleasing form. Considering our quadratic expression, let's break down the simplification steps:
1. **Simplify the inner expression**: Before taking the square root, simplify any arithmetic inside the square root. For the given exercise, you found \((-4)^{2} - 4(5)(1) = 16 - 20 = -4\).
2. **Evaluate the square root**: Once simplified, evaluate the square root. For \sqrt{-4}\, this becomes `2i`. Knowing the properties of imaginary numbers helps here.
3. **Simplify the overall expression**: Combine all parts back into the quadratic formula. \frac{-(-4) + 2i}{2(5)}\ simplifies to \frac{4 + 2i}{10}\.
4. **Divide each part separately**: Finally, divide the real and imaginary parts by the denominator separately. So, \frac{4}{10} + \frac{2i}{10} = 0.4 + 0.2i\.
Simplification is crucial to make complex expressions easier to understand and work with.
1. **Simplify the inner expression**: Before taking the square root, simplify any arithmetic inside the square root. For the given exercise, you found \((-4)^{2} - 4(5)(1) = 16 - 20 = -4\).
2. **Evaluate the square root**: Once simplified, evaluate the square root. For \sqrt{-4}\, this becomes `2i`. Knowing the properties of imaginary numbers helps here.
3. **Simplify the overall expression**: Combine all parts back into the quadratic formula. \frac{-(-4) + 2i}{2(5)}\ simplifies to \frac{4 + 2i}{10}\.
4. **Divide each part separately**: Finally, divide the real and imaginary parts by the denominator separately. So, \frac{4}{10} + \frac{2i}{10} = 0.4 + 0.2i\.
Simplification is crucial to make complex expressions easier to understand and work with.