/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The 2.4 - Meter Rule A 2.4 -mete... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The 2.4 - Meter Rule A 2.4 -meter sailboat is a one-person boat that is about \(13 \mathrm{ft}\) in length, has a displacement of about \(550 \mathrm{lb},\) and a sail area of about \(81 \mathrm{ft}^{2} .\) To compete in the 2.4-meter class, a boat must satisfy the formula $$2.4=\frac{L+2 D-F \sqrt{S}}{2.37}$$ where \(L=\) length, \(F=\) freeboard, \(D=\) girth, and \(S=\) sail area. Solve the formula for \(D\).

Short Answer

Expert verified
D = \frac{5.688 - L + F \sqrt{S}}{2}.

Step by step solution

01

- Understand the Given Formula

The formula given is: \[ 2.4 = \frac{L + 2D - F \sqrt{S}}{2.37} \]We need to solve for \(D\).
02

- Eliminate the Denominator

Multiply both sides of the equation by 2.37 to get rid of the denominator: \[ 2.4 \times 2.37 = L + 2D - F \sqrt{S} \]This simplifies to: \[ 5.688 = L + 2D - F \sqrt{S} \]
03

- Isolate the Term with D

We need to isolate the term \(2D\). First, subtract \(L\) and add \(F \sqrt{S}\) to both sides: \[ 5.688 - L + F \sqrt{S} = 2D \]
04

- Solve for D

Finally, divide by 2 to solve for \(D\): \[ D = \frac{5.688 - L + F \sqrt{S}}{2} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

solving equations
Solving equations means finding the value of a variable that makes an equation true. It's like piecing together a puzzle. Each piece or step brings you closer to the final answer. In this case, we need to solve the formula for the variable \( D \). To start, always make sure you understand the given formula. For example, the formula \[ 2.4 = \frac{L + 2D - F \sqrt{S}}{2.37} \] needs to be rearranged to find \ D \. By isolating \ D \ and performing algebraic operations step-by-step, you can solve the equation.
algebraic manipulation
Algebraic manipulation involves rearranging equations using mathematical operations like addition, subtraction, multiplication, and division. Here, we want to isolate the variable \( D \). Start by eliminating any denominators to simplify the equation. Multiply both sides by 2.37: \[ 2.4 \times 2.37 = L + 2D - F \sqrt{S} \] This gives: \[ 5.688 = L + 2D - F \sqrt{S} \] Next, focus on the term with \ 2D \. Subtract \ L \ and add \ F \sqrt{S} \ to both sides: \[ 5.688 - L + F \sqrt{S} = 2D \] Now, divide the entire equation by 2 to isolate \ D \ and simplify the expression: \[ D = \frac{5.688 - L + F \sqrt{S}}{2} \]
precise calculations
Precise calculations are crucial in algebra to ensure the accuracy of your results. Missteps in arithmetic can lead to incorrect solutions. Here, be careful with your multiplications and divisions.
For instance, multiplying 2.4 by 2.37 correctly gives \ 5.688 \. Make sure to keep track of every number and operation as you manipulate the equation. To isolate \ D \, follow these precise steps:
After multiplication to eliminate the denominator: \[ 5.688 = L + 2D - F \sqrt{S} \]
Carefully subtract \ L \ and add \ F \sqrt{S}: \[ 5.688 - L + F \sqrt{S} = 2D \]
Finally, divide by 2, ensuring all operations are performed correctly: \[ D = \frac{5.688 - L + F \sqrt{S}}{2} \]
Accurate calculations ensure you solve the equation correctly and arrive at the right value for \ D \.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

$$\text { Solve } 3-5|x-4|=0$$

Raising a Batting Average At one point during the 2008 season, a baseball player had 97 hits in 387 times at bat for an average of 0.251 a. How many more times would he have to bat to get his average over \(0.300,\) assuming he got a hit every time? b. How many more times would he have to bat to get his average over \(0.300,\) assuming he got a hit \(50 \%\) of the time?

Hall can shovel the snow from a long driveway in 24 minutes. If Shanna helps, they can do the job in 18 minutes. How long would it take Shanna to do the job alone?

Find an exact solution to each problem. If the solution is irrational, then find an approximate solution also. Computer Design Using a computer design package, Tina can write and design a direct-mail package in two days less time than it takes to create the same package using tradition \(=\) design methods. If Tina uses the computer and her assistant Curt uses traditional methods, and together they complete the job in 3.5 days, then how long would it have taken Curt to d the job alone using traditional methods? Which Curt's rate is \(1 / x\) job/day and Tina's rate is \(1 /(x-2)\) job/day.

Find an exact solution to each problem. If the solution is irrational, then find an approximate solution also. Mixing Antifreeze in a Radiator Steve's car had a large radiator that contained an unknown amount of pure water. He added two quarts of antifrecze to the radiator. After testing, he decided that the percentage of antifreeze in the radiator was not large enough. Not knowing how to solve mixture problems, Steve decided to add one quart of water and another quart of antifreeze to the radiator to see what he would get. After testing he found that the last addition increased the percentage of antifreeze by three percentage points. How much water did the radiator contain originally?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.