/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Find the number. $$P(7,6)$$... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the number. $$P(7,6)$$

Short Answer

Expert verified
The number of permutations is 5040.

Step by step solution

01

Understand the permutation notation

The notation \( P(n, r) \) represents the number of permutations of \( n \) items taken \( r \) at a time. In this exercise, \( P(7, 6) \) means we need to find the number of ways to arrange 7 items while taking 6 at a time.
02

Permutation formula

The formula for permutations is given by \( P(n, r) = \frac{n!}{(n-r)!} \). Here, \( n \) is 7 and \( r \) is 6.
03

Calculate the factorials

Calculate the factorial of \( n \) and \( n-r \). So, we have:- \( 7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040 \).- \( (7-6)! = 1! = 1 \).
04

Substitute the values into the permutation formula

Substitute the factorial values into the formula: \( P(7, 6) = \frac{7!}{1!} = \frac{5040}{1} \).
05

Simplify the expression

Simplify \( \frac{5040}{1} \) to get \( 5040 \). This is the number of ways to arrange 7 items taken 6 at a time.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Factorials
When dealing with permutations, understanding the concept of a "factorial" is crucial. A factorial, denoted by an exclamation mark (!), is the product of all positive integers up to a specific number. For example, the factorial of 7, represented as \(7!\), is calculated as follows:

\[7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 5040\]

Factorials are a foundational component in many mathematics problems involving permutations and combinations. They essentially count the number of ways objects can be arranged. This becomes particularly useful in determining the number of unique arrangements possible for a set of items. Remember that \(0!\) is defined as 1; this definition ensures that mathematical formulas work perfectly even in special cases.
Exploring Arrangements in Permutations
An arrangement refers to the specific sequence of items. In permutation problems such as finding \( P(7,6) \), we are interested in how we can arrange a certain number of items from a larger set. This arrangement is important because, unlike combinations, the order in which items appear matters significantly.

For instance, consider letters A, B, and C. The arrangements for choosing two letters at a time are AB, AC, BA, BC, CA, and CB. Notice that AB is different from BA, highlighting the importance of order in permutation problems.

Using the permutation formula, \( P(n, r) = \frac{n!}{(n-r)!} \), we can determine how many possible arrangements exist when selecting "r" items from a group of "n". It’s all about finding how many different sequences (or orders) can be formed.
Combinatorics in Practice
Combinatorics is the area of mathematics that deals with counting, arrangements, and the combination of objects. It encompasses both permutations and combinations and is fundamental in solving problems like estimating probabilities or optimally arranging items.

For permutations specifically, combinatorics provides the framework to systematically choose and arrange objects. The permutation problem \( P(7,6) \) is a direct application where we select and arrange 6 items from a set of 7. The general approach involves utilizing factorials to handle extensive listings and ensure every possible arrangement is captured. This approach gives a robust mechanism to explore all feasible scenarios in structured ways.

Understanding these principles within combinatorics not only aids in solving mathematical problems but also applies to various real-world scenarios. Whether scheduling tasks, creating passwords, or optimizing resources, the principles of combinatorics provide the necessary tools to count and organize efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the specified term of the arithmetic sequence that has the two given terms. $$a_{500} ; a_{9}=-253, \quad a_{412}=2971$$

Find the sum \(S_{n}\) of the arithmetic sequence that satisfies the stated conditions. $$a_{1}=5, \quad a_{20}=9, \quad n=20$$

The sequence defined recursively by \(x_{k+1}=x_{k} /\left(1+x_{k}\right)\) occurs in genetics in the study of the elimination of a deficient gene from a population. Show that the sequence whose \(n\) th term is \(1 / x_{n}\) is arithmetic.

Chlorine levels Chlorine is often added to swimming pools to control microorganisms. If the level of chlorine rises above 3 ppm (parts per million), swimmers will experience burning eyes and skin discomfort. If the level drops below 1 ppm, there is a possibility that the water will turn green because of a large algae count. Chlorine must be added to pool water at regular intervals. If no chlorine is added to a pool during a 24 -hour period, approximately \(20 \%\) of the chlorine will dissipate into the atmosphere and \(80 \%\) will remain in the water. (a) Determine a recursive sequence \(a_{n}\) that expresses the amount of chlorine present after \(n\) days if the pool has \(a_{0}\) ppm of chlorine initially and no chlorine is added. (b) If a pool has 7 ppm of chlorine initially, construct a table to determine the first day on which the chlorine level will drop below 3 ppm.

For the given \(n\) th term \(a_{n}=f(n)\) of a sequence, use the graph of \(y=f(x)\) on the interval \([1,100]\) to verify that as \(n\) increases without bound, \(a_{n}\) approaches some real number \(c\) $$a_{n}=\left(2.1^{n}+1\right)^{1 / n}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.