Chapter 9: Problem 35
Without expanding completely, find the indicated term(s) in the expansion of the expression. \(\left(3 c^{2 / 5}+c^{4 / 5}\right)^{25} ; \quad\) first three terms
Short Answer
Expert verified
First three terms are \(3^{25} c^{10}\), \(25 \times 3^{24} c^{49/5}\), and \(300 \times 3^{23} c^{54/5}\).
Step by step solution
01
Apply the Binomial Theorem
The binomial theorem states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\), where \(\binom{n}{k}\) is a binomial coefficient. Here, \(a = 3c^{2/5}\), \(b = c^{4/5}\), and \(n = 25\). We will apply this formula to find the first three terms.
02
Calculate the First Term
For the first term, set \(k = 0\): \[ T_0 = \binom{25}{0} (3c^{2/5})^{25} (c^{4/5})^0 = 1 \times 3^{25} \times (c^{2/5})^{25} \times 1 = 3^{25} c^{10} \]
03
Calculate the Second Term
For the second term, set \(k = 1\): \[ T_1 = \binom{25}{1} (3c^{2/5})^{24} (c^{4/5})^1 = 25 \times 3^{24} \times c^9 \times c^{4/5} = 25 \times 3^{24} \times c^{49/5} \]
04
Calculate the Third Term
For the third term, set \(k = 2\): \[ T_2 = \binom{25}{2} (3c^{2/5})^{23} (c^{4/5})^2 = \frac{25 \times 24}{2} \times 3^{23} \times c^{46/5} \times c^{8/5} = 300 \times 3^{23} \times c^{54/5} \]
05
Compile the First Three Terms
The first three terms of the expansion are:1. \(3^{25} c^{10}\)2. \(25 \times 3^{24} c^{49/5}\)3. \(300 \times 3^{23} c^{54/5}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
Binomial expansion is a way of expanding expressions that are raised to a power. When you see something like \((a+b)^n\), the binomial expansion enables you to express it as a sum of terms involving powers of \(a\) and \(b\). This is very handy because instead of multiplying \(a+b\) by itself \(n\) times, you can use the binomial theorem to directly calculate terms of the form \( \binom{n}{k} a^{n-k} b^k \).The binomial theorem formula is:
- \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \)
Binomial Coefficients
Binomial coefficients are the building blocks of the binomial expansion, represented as \( \binom{n}{k} \), which is read as "n choose k." These coefficients indicate the number of ways to choose \(k\) elements from a set of \(n\) elements, and they are essential for finding specific terms in a binomial expansion.Mathematically, the binomial coefficient is calculated as follows:
- \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
- First term: \( \binom{25}{0} = 1 \)
- Second term: \( \binom{25}{1} = 25 \)
- Third term: \( \binom{25}{2} = 300 \)
Exponents in Binomial Series
Understanding exponents is crucial in applying the binomial theorem, especially when finding terms in the expansion. In the expression \((a+b)^n\), every term is a product of different powers of \(a\) and \(b\).The general term of the expansion is given by \( \binom{n}{k} a^{n-k} b^k \). This reveals that the exponents on \(a\) and \(b\) always add up to \(n\). In our given problem, exponents played a key role, especially since the terms involved fractional powers such as \(c^{2/5}\) and \(c^{4/5}\):
- In the first term, \((3c^{2/5})^{25} = 3^{25} c^{10}\)
- In the second term, \((3c^{2/5})^{24} \times (c^{4/5})^1 = 3^{24} c^{49/5}\)
- In the third term, \((3c^{2/5})^{23} \times (c^{4/5})^2 = 3^{23} c^{54/5}\)