Chapter 7: Problem 53
Express in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$\sqrt{34} \text { cis }\left(\tan ^{-1} \frac{3}{5}\right)$$
Short Answer
Expert verified
The complex number in rectangular form is \(5 + 3i\).
Step by step solution
01
Understand the Given Expression
The expression given is \( \sqrt{34} \text{ cis }(\tan^{-1} \frac{3}{5}) \). This represents a complex number in polar form, where \( r = \sqrt{34} \) and \( \theta = \tan^{-1} \frac{3}{5} \). We need to convert this into rectangular form, \( a + bi \).
02
Use Formular for Rectangular Form
The polar form \( r \text{ cis } \theta \) can be converted to rectangular form using \( a = r \cos(\theta) \) and \( b = r \sin(\theta) \). Here, \( a = \sqrt{34} \cos(\tan^{-1} \frac{3}{5}) \) and \( b = \sqrt{34} \sin(\tan^{-1} \frac{3}{5}) \).
03
Calculate \( \cos(\tan^{-1}(\frac{3}{5})) \) and \( \sin(\tan^{-1}(\frac{3}{5})) \)
\( \theta = \tan^{-1}(\frac{3}{5}) \) implies \( \tan \theta = \frac{3}{5} \). Consider a right triangle where the opposite side is 3 and the adjacent side is 5. Using the Pythagorean theorem, the hypotenuse \( h = \sqrt{3^2 + 5^2} = \sqrt{34} \). Therefore, \( \cos \theta = \frac{5}{\sqrt{34}} \) and \( \sin \theta = \frac{3}{\sqrt{34}} \).
04
Solve for \( a \) and \( b \)
Now substitute \( \cos(\theta) \) and \( \sin(\theta) \) computed in the previous step into the formulas for \( a \) and \( b \). So, \( a = \sqrt{34} \cdot \frac{5}{\sqrt{34}} = 5 \) and \( b = \sqrt{34} \cdot \frac{3}{\sqrt{34}} = 3 \).
05
Write the Answer in Rectangular Form
The expression in rectangular form is \( a + bi \), where \( a = 5 \) and \( b = 3 \). Thus, the complex number is \( 5 + 3i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
The polar form of a complex number is an elegant way to represent complex numbers graphically. Instead of using two real numbers to define the horizontal and vertical positions on a plane, polar form uses a distance from the origin and an angle. In this form, a complex number is expressed as \( r \text{ cis }\theta \), where \( r \) is the magnitude and \( \theta \) is the angle.
- \( r \), the magnitude, represents the distance from the origin to the point.
- \( \theta \), the angle, is measured in radians and tells you where the point is relative to the positive x-axis.
Rectangular Form
The rectangular form of a complex number is a more familiar format for those acquainted with algebra. A complex number in rectangular form is written as \( a + bi \), where \( a \) and \( b \) are real numbers.
- \( a \): The real component. Represents horizontal displacement on the complex plane.
- \( b \): The imaginary component. Represents vertical displacement and is multiplied by the imaginary unit \( i \), where \( i^2 = -1 \).
Trigonometry
Trigonometry is the mathematical field that studies relationships between side lengths and angles within triangles. It plays a vital role in converting between polar and rectangular forms of complex numbers.In the given problem:- Trigonometric functions help determine the coordinates \( a \) and \( b \) based on an angle \( \theta \).- The angle \( \theta = \tan^{-1}\left(\frac{3}{5}\right) \) is derived using the tangent function, which is the ratio of the opposite to adjacent sides in a right triangle.Primary trigonometric functions used in these conversions include:
- \( \cos(\theta) \): Determines the adjacent side to the angle or the x-coordinate.
- \( \sin(\theta) \): Determines the opposite side to the angle or the y-coordinate.
- \( \tan(\theta) \): Ratio of the opposite over adjacent side, fundamental in defining angles like \( \theta \).
Pythagorean Theorem
A cornerstone of geometry, the Pythagorean Theorem relates the lengths of the sides in a right triangle. It is especially crucial when moving between polar and rectangular forms, as it helps find the magnitude of a complex number.The theorem states:\[ a^2 + b^2 = c^2 \]Here, \( c \) represents the hypotenuse, while \( a \) and \( b \) are the triangle's base and height. To find \( r \), the magnitude of the complex number, the theorem is used with the triangle formed by the real, imaginary parts and the modulus:
- Given: \( a = 5 \) and \( b = 3 \)
- The magnitude \( r = \sqrt{a^2 + b^2} = \sqrt{34} \)