Chapter 7: Problem 34
Express the complex number in trigonometric form with \(0 \leq \theta<2 \pi\) $$-5$$
Short Answer
Expert verified
-5 in trigonometric form is expressed as \(5(\cos \pi + i\sin \pi)\).
Step by step solution
01
Identify Real and Imaginary Components
The complex number \(-5\) can be written in the standard form \(a + bi\). Here, \(a = -5\) and \(b = 0\). The number has a real component \(-5\) and no imaginary component.
02
Calculate the Magnitude
The magnitude \(r\) of a complex number \(a + bi\) is calculated as \( r = \sqrt{a^2 + b^2} \). Substituting the values \(a = -5\) and \(b = 0\), we get \( r = \sqrt{(-5)^2 + 0^2} = \sqrt{25} = 5 \).
03
Determine the Argument
The argument \(\theta\) is the angle the line from the origin to the point makes with the positive real axis. For \(-5\), which lies entirely on the negative real axis, the angle \(\theta\) is \(\pi\), or 180°.
04
Write the Trigonometric Form
A complex number in trigonometric form is represented as \( r(\cos \theta + i\sin \theta) \). Substituting \(r = 5\) and \(\theta = \pi\), we express \(-5\) as \( 5(\cos \pi + i\sin \pi) = 5(-1 + 0i) = -5 \). Hence, the trigonometric form is \(5(\cos \pi + i\sin \pi)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Complex Numbers
The magnitude, also known as the absolute value, of a complex number measures its distance from the origin in the complex plane. Just like how you find the distance between two points in geometry, the magnitude is computed using a formula based off of the Pythagorean theorem.
For a complex number of the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part, the magnitude \(r\) is calculated as follows: \[ r = \sqrt{a^2 + b^2} \] In the exercise, for the complex number \(-5\), we identify \(a = -5\) and \(b = 0\). Therefore, the magnitude is: \[ r = \sqrt{(-5)^2 + 0^2} = \sqrt{25} = 5 \] The simplicity arises because the imaginary component is zero, leaving us with just the absolute value of the real component.
Steps to remember:
For a complex number of the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part, the magnitude \(r\) is calculated as follows: \[ r = \sqrt{a^2 + b^2} \] In the exercise, for the complex number \(-5\), we identify \(a = -5\) and \(b = 0\). Therefore, the magnitude is: \[ r = \sqrt{(-5)^2 + 0^2} = \sqrt{25} = 5 \] The simplicity arises because the imaginary component is zero, leaving us with just the absolute value of the real component.
Steps to remember:
- Identify \(a\) and \(b\).
- Apply the magnitude formula.
- Simplify to find \(r\).
Argument of Complex Numbers
The argument of a complex number, denoted by \(\theta\), is the angle formed between the positive real axis and the line representing the complex number. This angle provides a way to locate the direction of the number in the complex plane.
To find the argument, consider the position of the complex number. For the number \(-5\), which lies entirely on the negative real axis, the angle \(\theta\) is directly \(\pi\) radians, or 180 degrees, from the positive axis.
Here are some tips:
To find the argument, consider the position of the complex number. For the number \(-5\), which lies entirely on the negative real axis, the angle \(\theta\) is directly \(\pi\) radians, or 180 degrees, from the positive axis.
Here are some tips:
- For complex numbers on the real axis: \(\theta\) is either \(0\), \( \pi \) (for negative numbers), or \(2\pi\).
- If the number is purely imaginary, use \(\frac{\pi}{2}\) or \(\frac{3\pi}{2}\).
- For other complex numbers, calculate \(\tan^{-1}(\frac{b}{a})\) and choose the correct quadrant.
Complex Numbers in Standard Form
Complex numbers can be expressed in multiple forms, each providing different insights. The standard form is typically written as \(a + bi\), where \(a\) is the real component and \(b\) is the imaginary component.
For the number in question, \(-5\), the standard form is straightforward: \(-5 + 0i\). There is no imaginary part.
Essential insights:
For the number in question, \(-5\), the standard form is straightforward: \(-5 + 0i\). There is no imaginary part.
Essential insights:
- The real part, \(a\): Represents horizontal placement on the complex plane.
- The imaginary part, \(b\): Represents vertical placement.
- In the standard form, it's evident how a complex number splits into real and imaginary components.