Chapter 7: Problem 27
Express the complex number in trigonometric form with \(0 \leq \theta<2 \pi\) $$-4-4 i$$
Short Answer
Expert verified
The trigonometric form of
\(-4 - 4i\) is
\[4\sqrt{2}(\cos \frac{5\pi}{4} + i\sin \frac{5\pi}{4})\].
Step by step solution
01
Identify Real and Imaginary Parts
The complex number given is \(-4 - 4i\). This can be broken down into its real part, \(-4\), and its imaginary part, \(-4\).
02
Calculate the Magnitude
The magnitude (modulus) of the complex number is given by the formula:\[ r = \sqrt{a^2 + b^2} \]Substituting the values \(a = -4\) and \(b = -4\):\[ r = \sqrt{(-4)^2 + (-4)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2}\]
03
Find the Argument
The argument \(\theta\) of a complex number is found using the tangent function: \[ \theta = \tan^{-1}\left(\frac{b}{a}\right) \]Plug in the values: \[ \theta = \tan^{-1}\left(\frac{-4}{-4}\right) = \tan^{-1}(1)\]For the fourth quadrant, the angle \(\theta = \frac{5\pi}{4}\) satisfies the condition \(0 \leq \theta < 2\pi\) because the complex number is in the second quadrant due to the negative real and imaginary components. Thus,\(\theta = \pi + \frac{\pi}{4} = \frac{5\pi}{4}\).
04
Express in Trigonometric Form
Express the complex number \(-4 - 4i\) in trigonometric form:\[-4 - 4i = r(\cos \theta + i\sin \theta)\]Substitute \(r = 4\sqrt{2}\) and \(\theta = \frac{5\pi}{4}\):\[-4 - 4i = 4\sqrt{2}(\cos \frac{5\pi}{4} + i\sin \frac{5\pi}{4})\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Form
The trigonometric form, also known as the polar form, of a complex number provides a unique way to express complex numbers using both distance and angle. This is useful because it translates a complex number into a circle format within the complex plane. The general form is:
\[ z = r(\cos \theta + i\sin \theta) \]where:
\[ z = r(\cos \theta + i\sin \theta) \]where:
- \( z \) is the complex number.
- \( r \) is the magnitude of the complex number.
- \( \theta \) is the argument, representing the angle.
Magnitude
The magnitude of a complex number, often referred to as the modulus, measures its distance from the origin of the complex plane. You calculate the magnitude using the formula:
\[ r = \sqrt{a^2 + b^2} \]where \( a \) and \( b \) are the real and imaginary components, respectively. So, for \(-4 - 4i\):
\[ r = \sqrt{a^2 + b^2} \]where \( a \) and \( b \) are the real and imaginary components, respectively. So, for \(-4 - 4i\):
- Substitute \(a = -4\) and \(b = -4\) into the magnitude formula.
- The value is \( r = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \).
Argument
The argument is the angle a complex number makes with the positive real axis within the complex plane. This angle provides information about the direction of the number. To find it, use:
\[ \theta = \tan^{-1}\left(\frac{b}{a}\right) \]When calculating the argument for \(-4 - 4i\):
\[ \theta = \tan^{-1}\left(\frac{b}{a}\right) \]When calculating the argument for \(-4 - 4i\):
- Since both real and imaginary parts are negative, the number lies in the third quadrant.
- The angle is \( \tan^{-1}(1)\), which is traditionally \( \frac{\pi}{4}\).
- In the correct quadrant, adjust it to \( \frac{5\pi}{4} \).
Complex Plane
The complex plane is an essential concept when working with complex numbers. It allows a visual representation where each complex number corresponds to a unique point. The horizontal axis (real axis) represents the real part of the complex number, and the vertical axis (imaginary axis) represents its imaginary part. In this plane:
- A point like \(-4 - 4i\) is represented by moving 4 units left on the real axis and 4 units down on the imaginary axis.
- The position is seen as a vector from the origin \((0,0)\) to the point \((-4, -4)\).
- The trigonometric form helps depict this vector as having both direction (argument) and length (magnitude).