Chapter 5: Problem 54
Graph the equation \(y=f(i)\) on the interval \([0,24] .\) Let \(y\) represent the outdoor temperature (in "F) at time \(t\) (in hours), where \(t=0\) corresponds to 9 A.M. Describe the temperature during the 24 -hour interval. $$y=80+22 \cos \left[\frac{\pi}{12}(t-3)\right]$$
Short Answer
Expert verified
Temperature ranges from 58°F to 102°F, peaking at noon and reaching a minimum at 3 A.M.
Step by step solution
01
Understand the Equation
The equation provided is a cosine function that models outdoor temperature over time. The function is given by \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \). This represents a temperature fluctuation around a mean temperature of 80°F with an amplitude of 22°F.
02
Determine the Period
The typical period of the cosine function \( \cos(x) \) is \( 2\pi \). In the equation \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \), the coefficient of \( t \) inside the cosine is \( \frac{\pi}{12} \). To find the period, divide \( 2\pi \) by the coefficient: \[ \text{Period} = \frac{2\pi}{\frac{\pi}{12}} = 24. \] Thus, the function repeats every 24 hours.
03
Analyze Shift and Amplitude
The term \( (t-3) \) indicates a horizontal shift to the right by 3 units. This means that the cosine function, which typically starts its cycle at \( t = 0 \), now starts at \( t = 3 \). The amplitude of 22 indicates the maximum deviation from the mean of 80°F, producing temperatures between 58°F and 102°F.
04
Determine Key Points
With a period of 24 hours, we can analyze key points: - At \( t = 3 \), \( y = 102 \) (maximum temperature).- At \( t = 3 + 12 = 15 \), \( y = 58 \) (minimum temperature).- At \( t = 3 + 6 = 9 \) and \( t = 3 + 18 = 21 \), \( y = 80 \) (mean temperature).
05
Graph the Function
Plot the cosine function over the interval \([0, 24]\): - Start at \( t = 0 \) with a temperature slightly above 80°F, considering the cosine shape. - Peak at \( t = 3 \) with 102°F.- Drop to 58°F at \( t = 15 \).- Return to 80°F at \( t = 9 \) and \( t = 21 \).This graph should display one complete cycle of temperature changes with a symmetry around the mean.
06
Describe the 24-hour Temperature Cycle
Throughout the day, the temperature starts slightly above 80°F at 9 A.M., reaching a peak of 102°F around noon. It returns to around 80°F by the evening, dips to 58°F at 3 A.M., and climbs back to around 80°F by 9 A.M. the next day.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Function
The cosine function is a fundamental concept in trigonometry. It helps describe periodic phenomena such as sound waves, light waves, and in this exercise, temperature changes. The general form of a cosine function is given by \( y = a \cos(bx + c) + d \). Here is a breakdown of the components: - **Amplitude (\( a \))**: This dictates how high and low the wave reaches from its center point. - **Frequency/B-value (\( b \))**: Affects the number of cycles within a given interval. - **Phase shift/C-value (\( c \))**: Determines horizontal shifting along the x-axis. - **Vertical shift/D-value (\( d \))**: Moves the function up or down the y-axis.
In this exercise, the cosine function helps model the outdoor temperature over time: - The equation is \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \). - Temperature fluctuates around a mean value (80°F), showcasing the natural cycle depicted by the changes in the wave via the cosine function.
In this exercise, the cosine function helps model the outdoor temperature over time: - The equation is \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \). - Temperature fluctuates around a mean value (80°F), showcasing the natural cycle depicted by the changes in the wave via the cosine function.
Amplitude and Period
Amplitude and period are two essential characteristics of a cosine function. Understanding them helps interpret models like the one we've seen with temperature changes. **Amplitude** The amplitude refers to the maximum deviation from the mean value in a wave. In the temperature function \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \), the amplitude is 22°F. This indicates that the temperature moves 22°F above and below the mean value of 80°F. So, temperatures range between 58°F and 102°F. **Period** Period describes the length of one full wave cycle, showing how long it takes for the function to repeat its behavior. The standard cosine function \( \cos(x) \) has a period of \( 2\pi \). However, the given function's period is influenced by the coefficient \( \frac{\pi}{12} \). Calculating the period: \[ \text{Period} = \frac{2\pi}{\frac{\pi}{12}} = 24 \] Thus, the temperature cycle repeats every 24 hours, highlighting a full daily temperature swing.
Horizontal Shift
Horizontal shift in a trigonometric function occurs when the whole wave is moved along the x-axis. This affects where the wave starts and can significantly change the interpretation of a function in real-world applications.
In our temperature model, \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \), the term \( (t-3) \) introduces a horizontal shift. The usual starting point of \( t = 0 \) is adjusted by \( +3 \), moving the start of the cosine wave to \( t = 3 \). This shift implies: - The maximum temperature occurs not at the initial point but 3 units (or hours) later in this 24-hour cycle. - We see the temperature peak at noon instead of 9 A.M., illustrating how a horizontal shift aligns the function closely with real-time changes.
In our temperature model, \( y = 80 + 22 \cos\left[ \frac{\pi}{12}(t-3) \right] \), the term \( (t-3) \) introduces a horizontal shift. The usual starting point of \( t = 0 \) is adjusted by \( +3 \), moving the start of the cosine wave to \( t = 3 \). This shift implies: - The maximum temperature occurs not at the initial point but 3 units (or hours) later in this 24-hour cycle. - We see the temperature peak at noon instead of 9 A.M., illustrating how a horizontal shift aligns the function closely with real-time changes.