Chapter 5: Problem 26
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$y=\frac{1}{2} \cos \frac{\pi}{3} x$$
Short Answer
Expert verified
Amplitude: \( \frac{1}{2} \), Period: 6, Phase Shift: 0.
Step by step solution
01
Identify Amplitude
The amplitude of a cosine function is the absolute value of the coefficient in front of the cosine term. Here, the function is given as \( y = \frac{1}{2} \cos \frac{\pi}{3}x \). The coefficient is \( \frac{1}{2} \), so the amplitude is \( \left| \frac{1}{2} \right| = \frac{1}{2} \).
02
Determine the Period
The period of a cosine function \( y = a \cos(bx + c) \) is calculated as \( \frac{2\pi}{|b|} \). In this function, \( b = \frac{\pi}{3} \). Therefore, the period is \( \frac{2\pi}{\left| \frac{\pi}{3} \right|} = \frac{2\pi}{\frac{\pi}{3}} = 6 \).
03
Find the Phase Shift
The phase shift of a cosine function \( y = a \cos(bx + c) \) is calculated from \( -\frac{c}{b} \). In this equation, there is no \( c \) term (or \( c = 0 \)), so the phase shift is \( -\frac{0}{\frac{\pi}{3}} = 0 \). Thus, there is no horizontal shift of the graph.
04
Sketch the Graph
Using the amplitude \( \frac{1}{2} \), period 6, and no phase shift, sketch a cosine wave starting from the maximum point at \( x=0 \). The wave will complete one cycle from 0 to 6. The maximum occurs at \( y=\frac{1}{2} \), the minimum at \( y=-\frac{1}{2} \), and the graph crosses the x-axis at points 1.5 and 4.5.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
The amplitude of a trigonometric function such as a cosine function is a measure of its height. It tells you how far the peaks of the wave are from the midline. If you imagine the wave as rising and falling above and below a horizontal line, the amplitude measures this rise and fall.
In the equation you've been given, which is \( y = \frac{1}{2} \cos \frac{\pi}{3} x \), the amplitude is represented by the coefficient of the cosine function, in this case \( \frac{1}{2} \).
Here's how to determine it:
When graphing, this amplitude affects how "tall" or "short" the wave appears. A smaller amplitude results in a flatter wave, while a larger amplitude would stretch the wave vertically.
In the equation you've been given, which is \( y = \frac{1}{2} \cos \frac{\pi}{3} x \), the amplitude is represented by the coefficient of the cosine function, in this case \( \frac{1}{2} \).
Here's how to determine it:
- Identify the coefficient of the cosine term. This is the value that comes before the \( \cos \) term.
- The amplitude is simply the absolute value of this coefficient, ensuring it's always a positive quantity as it represents a distance.
When graphing, this amplitude affects how "tall" or "short" the wave appears. A smaller amplitude results in a flatter wave, while a larger amplitude would stretch the wave vertically.
Period
The period of a trigonometric function is the distance along the x-axis before the wave pattern repeats itself.
In the general form of a cosine function, \( y = a \cos(bx + c) \), the period is determined using the coefficient \( b \) of the \( x \) term.
The period is calculated as:
Understanding the period helps in sketching the graph and recognizing how compressed or stretched the wave will be compared to a standard cosine function, which has a default period of \( 2\pi \).
In the general form of a cosine function, \( y = a \cos(bx + c) \), the period is determined using the coefficient \( b \) of the \( x \) term.
The period is calculated as:
- \( \frac{2\pi}{|b|} \)
- Here, \( b = \frac{\pi}{3} \).
- The period then becomes \( \frac{2\pi}{\left| \frac{\pi}{3} \right|} = 6 \).
Understanding the period helps in sketching the graph and recognizing how compressed or stretched the wave will be compared to a standard cosine function, which has a default period of \( 2\pi \).
Phase Shift
Phase shift refers to the horizontal movement or shift of the graph of a trigonometric function along the x-axis.
In our general cosine equation \( y = a \cos(bx + c) \), the phase shift is determined by the constant \( c \). The formula used is:
Understanding phase shifts is important when comparing two trigonometric functions, as even identical functions can appear quite different if one starts further along the x-axis than the other. However, in this case, there's no shift to consider.
In our general cosine equation \( y = a \cos(bx + c) \), the phase shift is determined by the constant \( c \). The formula used is:
- \( -\frac{c}{b} \)
- Thus, the phase shift calculation is \( -\frac{0}{\frac{\pi}{3}} = 0 \).
Understanding phase shifts is important when comparing two trigonometric functions, as even identical functions can appear quite different if one starts further along the x-axis than the other. However, in this case, there's no shift to consider.