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(a) Graph \(f\) using a graphing utility. (b) Sketch the graph of \(g\) by taking the reciprocals of \(y\) -coordinates in (a), without using a graphing utility. $$f(x)=\frac{e^{x}+e^{-x}}{2} ; \quad g(x)=\frac{2}{e^{x}+e^{-x}}$$

Short Answer

Expert verified
Graph \( f(x) \) using a utility. Sketch \( g(x) \) as the reciprocal of \( \cosh(x) \), peaking at 1 then approaching 0.

Step by step solution

01

Graph Function f(x) using a Graphing Utility

First, we will graph the function \( f(x) = \frac{e^{x} + e^{-x}}{2} \). This function represents the hyperbolic cosine function \( \cosh(x) \). Using a graphing utility, plot the curve by inputting the function. The graph should display a U-shaped curve with the lowest point at \( f(0) = 1 \). As \( x \) approaches infinity in either direction, \( f(x) \) should increase asymptotically due to the exponential terms.
02

Understand the Relationship between f(x) and g(x)

The function \( g(x) = \frac{2}{e^{x} + e^{-x}} \) is derived by taking the reciprocal of \( f(x) \) where \( f(x) = \frac{e^{x} + e^{-x}}{2} \). Simplifying \( g(x) \), we have: \[ g(x) = \frac{2}{2 \cdot \cosh(x)} = \frac{1}{\cosh(x)} \]. This corresponds to the hyperbolic secant function \( \text{sech}(x) \).
03

Sketch g(x) without a Graphing Utility

To sketch \( g(x) \), use the graph of \( f(x) \) from Step 1. Since \( g(x) \) is the reciprocal of \( f(x) \), at points where \( f(x) \) is large, \( g(x) \) will be small, and vice versa. \( g(x) \) will have its maximum at \( x = 0 \), where \( g(0) = \frac{1}{\cosh(0)} = 1 \). As \( |x| \) increases, \( \cosh(x) \) increases, making \( g(x) \) approach 0. The sketch should illustrate \( g(x) \) as a peak at the origin, tapering off towards the x-axis as \( x \) moves away from 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graph Sketching
When sketching graphs, a systematic approach can be very helpful. Begin by examining key points that define the behavior of the function. For instance, if you are sketching the hyperbolic cosine function, denoted as \( f(x) = \frac{e^{x} + e^{-x}}{2} \), you should note its U-shape and symmetry about the y-axis.
Since this is a hyperbolic function, check the value at the origin, which is \( f(0) = 1 \). This will mark the vertex of the curve. Then observe the direction towards which the curve extends. As \( x \) moves away from 0 in either direction, the exponential components \( e^{x} \) and \( e^{-x} \) cause the function to increase.
By plotting additional values on either side of \( x = 0 \), you can predictably describe how the curve will ascend. Always bear in mind that hyperbolic cosine is continuous and smooth, creating a gentle "U" covering the y-axis up to any horizontal extent desired.
Remember that sketching effectively boils down to understanding the essential characteristics of the function—like peak, growth, or decay—and then translating them visually.
Reciprocal Functions
A reciprocal function takes another function and flips its y-values about the line \( y = 1 \). For instance, if you start with \( f(x) = \cosh(x) \), its reciprocal will be \( g(x) = \frac{1}{\cosh(x)} \). Understanding this inversion is vital to mastering reciprocal functions.
First, recognize that where \( f(x) \) is at its smallest, \( g(x) \) will be at its largest and vice versa. For hyperbolic functions such as \( \cosh(x) \), as it tends to increase as \( \left| x \right| \) increases, the reciprocal will tend toward zero.
  • The maximum point for \( g(x) \) occurs at the minimum point of \( f(x) \). Hence, at \( x = 0 \), \( g(0) = 1 \), given \( f(0) = 1 \).
  • As \( x \) moves further from zero, the denominator \( \cosh(x) \) rises, causing \( g(x) \) to shrink.
While sketching, always keep these reciprocal dynamics in mind. The original function's behavior informs how its reciprocal behaves— a peak transforms into a trough, a valley into a prominence. Recognize the reciprocal as stretching and compressing in an inverted manner compared to the original function.
Hyperbolic Cosine
The hyperbolic cosine function, denoted as \( \cosh(x) \), is a fundamental hyperbolic function used to model real-world scenarios, such as the shape of a hanging cable, known as catenary.
Defined as \( \cosh(x) = \frac{e^{x} + e^{-x}}{2} \), this function has properties similar to its trigonometric counterpart, the cosine function. However, unlike the periodic cosine function, the hyperbolic cosine steadily grows without bound in both directions of the x-axis.
  • It's an even function, exhibiting symmetry about the y-axis. This means \( \cosh(-x) = \cosh(x) \).
  • The function is continuously increasing as \( |x| \) increases, highlighting its exponential growth nature.
  • At \( x = 0 \), we find \( \cosh(0) = 1 \), which is the lowest point (vertex) of its curve.
The hyperbolic cosine describes a continuous, smooth "U" shape stretching upwards, providing a foundational understanding for hyperbolic geometries. Observing this behavior helps when comparing with its reciprocal or other hyperbolic functions, such as hyperbolic sine \( \sinh(x) \), which complements the understanding with an odd-symmetric counterpart.

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