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A drug is eliminated from the body through urine. Suppose that for an initial dose of 10 milligrams, the amount \(A(t)\) in the body \(t\) hours later is given by \(A(t)=10(0.8)^{t}\). (a) Estimate the amount of the drug in the body 8 hours after the initial dose. (b) What percentage of the drug still in the body is eliminated each hour?

Short Answer

Expert verified
(a) Approximately 1.68 milligrams; (b) 20% of the drug is eliminated each hour.

Step by step solution

01

Understanding the Formula

The formula provided is \(A(t) = 10(0.8)^t\), where \(t\) is the number of hours after the initial dose and \(A(t)\) is the amount of drug remaining in the body. The base of the exponent, 0.8, represents the fraction of the drug amount that remains each hour.
02

Calculate Amount After 8 Hours

Substitute \(t = 8\) in the formula \(A(t) = 10(0.8)^t\) to find the amount after 8 hours: \[ A(8) = 10(0.8)^8 \]Calculate this using a calculator:\[ A(8) = 10 \times 0.16777216 \approx 1.6777 \text{ milligrams} \]
03

Determine Percentage Eliminated Each Hour

The factor of 0.8 in \(A(t) = 10(0.8)^t\) indicates that 80% of the drug amount remains each hour, which means 20% of the drug is eliminated each hour. The percentage eliminated is simply the complement of the retention rate: 100% - 80% = 20%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drug Elimination
Understanding how drugs are eliminated from the body is crucial for safe medication use. Drugs are often processed and removed via organs such as the liver and finally expelled through urine. This process can be influenced by various factors, including the patient's metabolism and the properties of the drug itself. In pharmacokinetics, the concept of drug elimination can be modeled with mathematical formulas to predict how the concentration of a drug decreases over time. These formulas help in determining appropriate dosing schedules and ensuring therapeutic effectiveness without causing toxicity. In our example, the drug's elimination is expressed as an exponential decay function, giving us a precise understanding of the drug's behavior in the body over time.
Exponential Functions
Exponential functions are a type of mathematical function used in modeling many natural phenomena, including drug elimination. They are described by the general formula: \[ A(t) = A_0 imes b^t \]where \(A(t)\) is the current amount, \(A_0\) is the initial amount, \(b\) is the base of the exponential function, and \(t\) symbolizes time. In our example, \(A(t) = 10(0.8)^t\), the base 0.8 signifies the proportion of the drug that remains in the body each hour.
  • The initial dose, \(A_0\) = 10 milligrams, represents the amount of drug at the start.
  • The base, 0.8, tells us that each hour, 80% of the drug stays in the body.
  • Exponential functions inherently model processes of growth or decay, which makes them ideal for situations like drug elimination.
Percentage Decrease
In the context of our exercise, percentage decrease is pivotal for understanding how quickly a drug is eliminated from the body. The concept is simple: if 80% of the drug remains after each hour, then the elimination rate is 20% per hour. Here's how it works:
  • You start with 100% of the drug.
  • Each hour, 80% is retained, meaning 20% is eliminated.
This consistent percentage decrease is what makes the exponential function applicable. Even though the exact amount reduces over time, the rate of decay remains constant, simplifying predictions and adjustments for medical purposes.

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