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If possible, find \(\begin{array}{ll}\text { (a) } f^{-1}(5) & \text { (b) } g^{-1}(6)\end{array}\). \(\begin{array}{|l|l|l|l|}\hline t & 0 & 3 & 5 \\\\\hline f(t) & 2 & 5 & 6 \\\\\hline\end{array}\) \(\begin{array}{|c|c|c|c|}\hline t & 1 & 2 & 4 \\\\\hline g(t) & 3 & 6 & 6 \\\\\hline\end{array}\)

Short Answer

Expert verified
(a) \( f^{-1}(5) = 3 \), (b) \( g^{-1}(6) = 2 \) or 4.

Step by step solution

01

Understanding the Problem

We need to find the inverse values of two functions, specifically: (a) when \( f(t) = 5 \) and (b) when \( g(t) = 6 \). This means finding the values of \( t \) such that \( f(t) \) becomes 5 and \( g(t) \) becomes 6.
02

Step 2a: Finding \( f^{-1}(5) \)

We refer to the table for function \( f(t) \), which provides:\[ \begin{array}{|l|l|l|l|}\hline t & 0 & 3 & 5 \hline f(t) & 2 & 5 & 6 \hline\end{array}\]By checking the values of \( f(t) \), we find that \( f(3) = 5 \). Therefore, \( f^{-1}(5) = 3 \).
03

Step 2b: Finding \( g^{-1}(6) \)

We refer to the table for function \( g(t) \), which provides:\[ \begin{array}{|c|c|c|c|}\hline t & 1 & 2 & 4 \hline g(t) & 3 & 6 & 6 \hline\end{array}\]Checking the values, we find both \( g(2) = 6 \) and \( g(4) = 6 \). So, the inverse \( g^{-1}(6) \) gives both 2 and 4, showing the function is not one-to-one in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Table of Values
A table of values is a convenient way to represent how a function behaves at certain points. For each input value, or 't', the table provides the corresponding output value of the function. This is particularly useful when dealing with inverse functions, where identifying specific output values helps us discover the input that led to that output.

The table allows us to work backwards: given an output, we can find the associated input by locating the output in the table and seeing its matching input. This is a great visual tool for solving inverse function problems because it provides a quick reference to identify pairs of input and output.

For example, if you have a table that shows values for the function \( f(t) \), and you need \( f^{-1}(5) \), you can find this by looking for 5 in the row of \( f(t) \) and reading its corresponding \( t \) value. This is precisely how we found that \( f^{-1}(5) = 3 \) in the given exercise.
One-to-One Functions
A one-to-one function, or injective function, is special because it ensures that each element in the function's range is mapped from a unique element in its domain. This unique mapping means that no two different inputs can have the same output, which is crucial for a function to have an inverse.

In simple terms, if a function is one-to-one, each output value comes from one and only one input value. This property of functions matters significantly when determining inverses because only one-to-one functions have inverses that are also functions.

In the exercise, when we looked at the function \( g(t) \), we saw both \( g(2) = 6 \) and \( g(4) = 6 \). Because two different inputs give the same output, \( g(t) \) is not one-to-one. Hence, when a function isn't one-to-one, it can’t have a well-defined inverse that assigns exactly one output (input in the inverse sense) to each potential input.
Function Inverses
Function inverses undo the effect of a function. If \( f \) maps \( x \) to \( y \), the inverse \( f^{-1} \) maps \( y \) back to \( x \). This is only possible when the function is one-to-one and onto (bijective), ensuring every output has a corresponding input.

To find the inverse of a function using a table, you look at each output value to find the corresponding input. Suppose \( f(t) = y \), then \( f^{-1}(y) = t \).

Our task was to find \( f^{-1}(5) \) and \( g^{-1}(6) \). We could find \( f^{-1}(5) = 3 \), which means when \( f \) produces 5, it started with input 3. This process of reversing functions is vital for numerous mathematical analyses, such as solving equations and modeling inverses in real-world applications like decoding signals.

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Most popular questions from this chapter

Computer chips For manufacturers of computer chips, it is important to consider the fraction \(F\) of chips that will fail after \(t\) years of service. This fraction can sometimes be approximated by the formula \(F=1-e^{-c t},\) where \(c\) is a positive constant. (a) How does the value of \(c\) affect the reliability of a chip? (b) If \(c=0.125,\) after how many years will \(35 \%\) of the chips have failed?

Sketch the graph of the equation. (a) Estimate \(y\) if \(x=40 .\) (b) Estimate \(x\) if \(y=2\). $$y=(1.0525)^{x}$$

Drug absorption If a 100 -milligram tablet of an asthma drug is taken orally and if none of the drug is present in the body when the tablet is first taken, the total amount \(A\) in the bloodstream after \(t\) minutes is predicted to be $$ A=100[1-(0.9)] \quad \text { for } \quad 0 \leq t \leq 10 $$ (a) Sketch the graph of the equation. (b) Determine the number of minutes needed for 50 milligrams of the drug to have entered the bloodstream.

Exer. \(69-70:\) It is suspected that the following data points lie on the graph of \(y=c \log (k x+10),\) where \(c\) and \(k\) are constants. If the data points have three-decimal-place accuracy, is this suspicion correct? $$(0,0.7),(1,0.782),(2,0.847),(4,0.945)$$

Graph \(f\) on the given interval. (a) Estimate the largest interval \([a, b]\) with \(a< 0< b\) on which \(f\) is one-to-one. (b) If \(g\) is the function with domain \([a, b]\) such that \(g(x)=f(x)\) for \(a \leq x \leq b,\) estimate the domain and range of \(g^{-1}.\) $$f(x)=2.1 x^{3}-2.98 x^{2}-2.11 x+3 ; \quad[-1,2]$$

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