/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Determine whether the function \... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the function \(f\) is one-to-one. \(f(x)=\frac{1}{x}\)

Short Answer

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The function \(f(x) = \frac{1}{x}\) is one-to-one.

Step by step solution

01

Understand One-to-One Functions

A function is one-to-one (injective) if different inputs map to different outputs. Mathematically, a function \(f(x)\) is one-to-one if \(f(a) = f(b)\) implies \(a = b\) for all inputs \(a\) and \(b\). We need to check if this condition holds for \(f(x) = \frac{1}{x}\).
02

Assume Two Outputs Are Equal

Assume that for two different inputs \(a\) and \(b\), the function's outputs are the same: \(f(a) = f(b)\). For the given function, this implies \(\frac{1}{a} = \frac{1}{b}\).
03

Solve for Equality of Inputs

To determine if \(\frac{1}{a} = \frac{1}{b}\) leads to \(a = b\), we cross-multiply the equation: \(b \cdot 1 = a \cdot 1\), which simplifies to \(b = a\).
04

Conclusion on One-to-One Property

Since \(\frac{1}{a} = \frac{1}{b}\) implies \(a = b\), the function \(f(x) = \frac{1}{x}\) satisfies the condition for being one-to-one. Thus, the function is indeed one-to-one.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Injective Functions
Injective functions, or one-to-one functions, are essential concepts in mathematics, especially when learning about function types. An injective function ensures that every output of the function is produced by a unique input value. This means no two different input values should generate the same output value. In mathematical terms, a function \(f\) is injective if \(f(a)=f(b)\) always implies \(a=b\) for all possible inputs \(a\) and \(b\).

To establish the injectiveness of a function like \(f(x)=\frac{1}{x}\), we must verify that no two distinct values of the input \(x\) can lead to the same value of \(f(x)\). If such distinct inputs existed, it would mean that the function is not injective.

In summary, injective functions are a significant part of understanding how different function types operate. Recognizing a function as injective gives insights into its structural uniqueness and behavior.
Function Equality
Function equality is a central idea when assessing whether a function is injective. To determine function equality for injective verification, we assume that two function values, say \(f(a)\) and \(f(b)\), are equal and determine whether this forces the input values \(a\) and \(b\) to also be equal.

For the function \(f(x) = \frac{1}{x}\), we set \(f(a) = f(b)\). This implies \(\frac{1}{a} = \frac{1}{b}\). If the function is injective, we should see that this equation implies \(a = b\).

Function equality is essentially the test battery for ensuring that each output corresponds back to only one unique input. In practice, this means examining equations and determining if their implications hold for all variables involved.
Cross Multiplication
Cross multiplication is a technique commonly used to solve equations involving fractions. It's particularly useful in verifying function equality for injective functions.

When we have \(\frac{1}{a} = \frac{1}{b}\), cross multiplication provides a straightforward method to see that these two expressions are equal if and only if \(a = b\). By multiplying both sides of the equation by \(a\) and \(b\), we can remove the denominators, resulting in \(b \cdot 1 = a \cdot 1\) or simply \(b = a\).

This method efficiently demonstrates that assuming equal outputs forces equal inputs, which is vital for showing that the function is injective. Cross multiplication thus serves as a practical tool beyond the arithmetic, into conceptual mathematical reasoning.
Precalculus Concepts
Precalculus lays the groundwork for more advanced mathematical studies, introducing functions as key tools. It encourages students to explore different types of functions, such as injective, surjective, and bijective. In the context of precalculus, understanding injective functions involves recognizing patterns and relationships between input and output values, as demonstrated when analyzing \(f(x) = \frac{1}{x}\).

Precalculus often involves a deeper dive into understanding properties of functions related to graphing, transformations, and set theory. For instance, distinguishing between injective functions helps clarify which functions can be inversed or which mappings represent one-to-one relationships.

Exploring these concepts is not only fundamental for mathematical proficiency but also sharpens analytical skills that are useful in diverse problem-solving scenarios across fields like engineering, computer science, and economics. Embracing precalculus concepts, such as injectivity, builds a strong foundation for tackling complex mathematical challenges.

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Most popular questions from this chapter

If monthly payments \(p\) are deposited in a savings account paying an annual interest rate \(r,\) then the amount \(A\) in the account after \(n\) years is given by $$A=\frac{p\left(1+\frac{r}{12}\right)\left[\left(1+\frac{r}{12}\right)^{12 n}-1\right]}{\frac{r}{12}}$$ Graph \(A\) for each value of \(p\) and \(r,\) and estimate \(n\) for \(A=100,000 \text{dollars}\). $$p=100, \quad r=0.05$$

One hundred elk, each 1 year old, are introduced into a game preserve. The number \(\bar{N}(t)\) alive after \(t\) years is predicted to be \(N(t)=100(0.9)^{t}\). (a) Estimate the number alive after 5 years. (b) What percentage of the herd dies each year?

Glottochronology is a method of dating a language at a particular stage, based on the theory that over a long period of time linguistic changes take place at a fairly constant rate. Suppose that a language originally had \(N_{0}\) basic words and that at time \(t,\) measured in millennia (1 millennium = 1000 years), the number \(N(t)\) of basic words that remain in common use is given by \(N(t)=N_{0}(0.805)^{t}\). (a) Approximate the percentage of basic words lost every 100 years. (b) If \(N_{0}=200,\) sketch the graph of \(N\) for \(0 \leq t \leq 5\).

Bird calls decrease in intensity (loudness) as they travel through the atmosphere. The farther a bird is from an observer, the softer the sound. This decrease in intensity can be used to estimate the distance between an observer and a bird. A formula that can be used to measure this distance is $$I=I_{0}-20 \log d-k d \text { provided } 0 \leq I \leq I_{0}$$ where \(I_{0}\) represents the intensity (in decibels) of the bird at a distance of one meter (\(I_{0}\) is often known and usually depends only on the type of bird), I is the observed intensity at a distance \(d\) meters from the bird, and \(k\) is a positive constant that depends on the atmospheric conditions such as temperature and humidity. Given \(I_{0}, I,\) and \(k,\) graphically estimate the distance \(d\) between the bird and the observer. $$I_{0}=70, \quad I=20, \quad k=0.076$$

Cooling A jar of boiling water at \(212^{\circ} \mathrm{F}\) is set on a table in a room with a temperature of \(72^{\circ} \mathrm{F}\). If \(T(t)\) represents the temperature of the water after \(t\) hours, graph \(T(t)\) and determine which function best models the situation. (1) \(T(t)=212-50 t\) (2) \(T(t)=140 e^{-t}+72\) (3) \(T(t)=212 e^{-t}\) (4) \(T(t)=72+10 \ln (140 t+1)\)

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