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An investment of \(P\) dollars increased to \(A\) dollars in \(t\) years. If interest was compounded continuously, find the interest rate. $$A=890.20, \quad P=400, \quad t=16$$

Short Answer

Expert verified
The interest rate is approximately 4.994%.

Step by step solution

01

Understand the Formula for Continuous Compounding

The formula used for continuous compounding is given by \( A = P e^{rt} \), where \( A \) is the amount of money accumulated after \( t \) years, including interest, \( P \) is the principal amount (initial investment), \( r \) is the interest rate, and \( e \) is the base of the natural logarithm.
02

Plug in Known Values

Insert the given values into the formula: \( A = 890.20 \), \( P = 400 \), and \( t = 16 \). The equation becomes: \[ 890.20 = 400 e^{16r} \]
03

Solve for \( e^{16r} \)

Divide both sides by \( 400 \) to isolate the exponential term: \[ e^{16r} = \frac{890.20}{400} = 2.2255 \]
04

Apply Natural Logarithm

Take the natural logarithm of both sides to solve for \( r \): \[ \ln(e^{16r}) = \ln(2.2255) \] This simplifies to: \[ 16r = \ln(2.2255) \]
05

Calculate the Natural Logarithm

Use a calculator to find \( \ln(2.2255) \), which is approximately \( 0.7991 \). Substitute back into the equation: \[ 16r = 0.7991 \]
06

Solve for the Interest Rate \( r \)

Divide both sides by 16 to find \( r \): \[ r = \frac{0.7991}{16} \approx 0.04994 \]
07

Convert the Interest Rate into Percentage

Multiply \( r \) by 100 to convert it into a percentage: \[ r \approx 4.994\% \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
Exponential growth is a concept that describes a situation where the rate of growth is directly proportional to the amount present at any given time. This means that as a value grows, it keeps getting larger by multiplying by a constant factor. In financial terms, exponential growth is integral to understanding how investments increase over time when interest is compounded. The principle is simple: more money you have, the more it will increase over a continuous period.
  • In continuous compounding, your investment doesn't grow at fixed intervals, like annually or semi-annually, but rather it is compounded at an infinite number of times per year.
  • This leads to exponential growth because the interest earned on the investment itself earns interest, continuously building on itself.
Understanding exponential growth helps us better grasp concepts of savings, investments, and the importance of reinvestment or compounding. It's the cornerstone of modern finance and explains why starting to save early can lead to more significant financial growth over time.
Natural Logarithm
The natural logarithm is a mathematical function that serves as the inverse of the exponential function with the base 'e'. The number 'e' is approximately equal to 2.71828 and is fundamental in calculating continuous growth processes. When we talk about continuous compounding, the natural logarithm becomes an essential tool for solving equations involving exponential expressions.
  • Natural logarithms are denoted as \( \ln(x) \) and help us decipher complex exponential relationships.
  • In financial calculations, particularly those involving compounding, \( \ln \) is used to "undo" the exponential function, allowing us to isolate variables like the interest rate \( r \).
For example, when we have an equation like \( e^{16r} = 2.2255 \), taking the natural logarithm of both sides simplifies it to \( 16r = \ln(2.2255) \), making it far easier to solve for any unknown variables. This property makes the natural logarithm indispensable in continuous growth and decay models, helping you decode the exponential growth pattern.
Compound Interest Formula
The compound interest formula is a fundamental equation used to calculate the amount of money that an investment will grow to when interest is compounded over time. For continuous compounding, this is refined to the formula \( A = P e^{rt} \), where you need to understand each variable:
  • \( A \): The amount of money accumulated after \( t \) years, including initial principal and interest.
  • \( P \): The principal amount, or initial investment.
  • \( r \): The annual interest rate, expressed as a decimal.
  • \( t \): The time in years the money is invested for.
  • \( e \): The constant that is approximately equal to 2.71828, representing the base of the natural log.
In continuous compounding, this formula helps investors understand how quickly their investments grow without waiting for periodic compounding. By plugging in the known values of \( P \), \( A \), and \( t \), you can solve for \( r \), giving you a clear picture of the investment's growth rate. This provides a simple yet powerful framework to project future financial growth and make informed investment decisions.

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Most popular questions from this chapter

Coal consumption A country presently has coal reserves of 50 million tons. Last year 6.5 million tons of coal was consumed. Past years' data and population projections suggest that the rate of consumption \(R\) (in million tons/year) will increase according to the formula \(R=6.5 e^{0.02 t}\) and the total amount \(T\) (in million tons) of coal that will be used in t years is given by the formula \(T=325\left(e^{0.02 t}-1\right) .\) If the country uses only its own resources, when will the coal reserves be depleted?

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Graph \(f\) on the interval [0.2, 16]. (a) Estimate the intervals where \(f\) is increasing or is decreasing. (b) Estimate the maximum and minimum values of \(f\) on \([0.2,16]\). $$f(x)=2 \log 2 x-1.5 x+0.1 x^{2}$$

Cholesterol level in women Studies relating serum cholesterol level to coronary heart disease suggest that a risk factor is the ratio \(x\) of the total amount \(C\) of cholesterol in the blood to the amount \(H\) of high-density lipoprotein cholesterol in the blood. For a female, the lifetime risk \(R\) of having a heart attack can be approximated by the formula $$ R=2.07 \ln x-2.04 \quad \text { provided } \quad 0 \leq R \leq 1 $$ For example, if \(R=0.65,\) then there is a \(65 \%\) chance that a woman will have a heart attack over an average lifetime. (a) Calculate \(R\) for a female with \(C=242\) and \(H=78\) (b) Graphically estimate \(x\) when the risk is \(75 \% .\)

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