Chapter 3: Problem 41
The third-degree Legendre polynomial \(P(x)=\frac{1}{2}\left(5 x^{3}-3 x\right)\) occurs in the solution of heat transfer problems in physics and engineering. Find all values of \(x\) such that \(P(x)>0\) and all \(x\) such that \(P(x)<0\) and sketch the graph of \(P\).
Short Answer
Expert verified
\(P(x) > 0\) for \(-\sqrt{\frac{3}{5}} < x < 0\) and \(x > \sqrt{\frac{3}{5}}\); \(P(x) < 0\) for \(x < -\sqrt{\frac{3}{5}}\) and \(0 < x < \sqrt{\frac{3}{5}}\).
Step by step solution
01
Understand the Polynomial
The given polynomial is a third-degree Legendre polynomial given by \(P(x) = \frac{1}{2} (5x^3 - 3x)\). Our task is to find the intervals of \(x\) for which \(P(x) > 0\) and \(P(x) < 0\).
02
Factor the Polynomial
We start by factoring the polynomial inside the parentheses: \(5x^3 - 3x = x(5x^2 - 3)\). Thus, the Legendre polynomial can be written as \(P(x) = \frac{1}{2} x (5x^2 - 3)\).
03
Find the Zeros
Set \(P(x) = 0\) to find where the polynomial equals zero. Solving \(\frac{1}{2} x (5x^2 - 3) = 0\) gives \(x = 0\) or \(5x^2 - 3 = 0\). Solving \(5x^2 - 3= 0\) results in \(x = \pm\sqrt{\frac{3}{5}}\).
04
Analyze Intervals Based on Zeros
The zeros divide the real number line into intervals: \((-\infty, -\sqrt{\frac{3}{5}})\), \((-\sqrt{\frac{3}{5}}, 0)\), \((0, \sqrt{\frac{3}{5}})\), and \((\sqrt{\frac{3}{5}}, \infty)\). Evaluate \(P(x)\) in each of these intervals to determine where it is positive or negative.
05
Determine Sign of P(x) in Each Interval
1. For \(x < -\sqrt{\frac{3}{5}}\), choose a test point, such as \(x = -1\): \(P(-1) = \frac{1}{2}(-1)(5(-1)^2 - 3) = -1\). Thus, \(P(x) < 0\) in this interval.2. For \(-\sqrt{\frac{3}{5}} < x < 0\), choose a test point, such as \(x = -0.1\): \(P(-0.1) = \frac{1}{2}(-0.1)(5(-0.1)^2 - 3) > 0\). Thus, \(P(x) > 0\).3. For \(0 < x < \sqrt{\frac{3}{5}}\), choose a test point, such as \(x = 0.1\): \(P(0.1) = \frac{1}{2}(0.1)(5(0.1)^2 - 3) < 0\). Thus, \(P(x) < 0\).4. For \(x > \sqrt{\frac{3}{5}}\), choose a test point, such as \(x = 1\): \(P(1) = \frac{1}{2}(1)(5(1)^2 - 3) > 0\). Thus, \(P(x) > 0\).
06
Sketch the Graph of P(x)
Sketch \(P(x)\) based on the sign analysis. Mark points where the polynomial crosses the x-axis at \(x = -\sqrt{\frac{3}{5}}, 0, \sqrt{\frac{3}{5}}\). The graph should reflect negative, positive, negative, positive regions in the intervals described. Ensure the cubic shape is correct with inflection near \(x = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Roots of Polynomials
Finding the roots of a polynomial is essential to understand the points where it crosses the x-axis. For the Legendre polynomial given by:\[ P(x) = \frac{1}{2} \left(5x^3 - 3x\right) \]Finding the roots involves setting the polynomial equal to zero:\[ \frac{1}{2}x(5x^2 - 3) = 0 \]To solve this, you break it down into simpler equations:
- \( x = 0 \)
- \( 5x^2 - 3 = 0 \)
Graphing Polynomials
Graphing polynomials becomes more intuitive once you know the roots. These roots divide the graph into regions or intervals. For our Legendre polynomial:\( P(x) = \frac{1}{2}x(5x^2 - 3) \), we have roots at \( x = 0 \), \( x = \sqrt{\frac{3}{5}}\), and \( x = -\sqrt{\frac{3}{5}} \). The sign of the polynomial in each interval is determined by selecting test points within them:
- When \( x < -\sqrt{\frac{3}{5}} \), \( P(x) < 0 \).
- When \(-\sqrt{\frac{3}{5}} < x < 0 \), \( P(x) > 0 \).
- When \( 0 < x < \sqrt{\frac{3}{5}} \), \( P(x) < 0 \).
- When \( x > \sqrt{\frac{3}{5}} \), \( P(x) > 0 \).
Interval Notation
Interval notation is a concise way of expressing the set of all possible values of \( x \) for which a polynomial either stays positive or negative. We use these intervals to specify where the polynomial \( P(x) = \frac{1}{2}(5x^3 - 3x) \) is greater than or less than zero.The roots you've calculated split the x-axis into specific intervals:
- \((-\infty, -\sqrt{\frac{3}{5}})\) : Here, \( P(x) < 0 \)
- \((-\sqrt{\frac{3}{5}}, 0)\) : Here, \( P(x) > 0 \)
- \((0, \sqrt{\frac{3}{5}})\) : Here, \( P(x) < 0 \)
- \((\sqrt{\frac{3}{5}}, \infty)\) : Here, \( P(x) > 0 \)