Chapter 3: Problem 15
Find all values of \(x\) such that \(f(x)>0\) and all \(x\) such that \(f(x)<0,\) and sketch the graph of \(f\). $$f(x)=\frac{1}{4} x^{3}-2$$
Short Answer
Expert verified
For \(x > 2\), \(f(x) > 0\). For \(x < 2\), \(f(x) < 0\). The graph is a cubic curve crossing the x-axis at \(x=2\).
Step by step solution
01
Understand the Function
The function given is \( f(x) = \frac{1}{4}x^3 - 2 \). It is a cubic function which typically has an S-shape. We need to find where this function is positive (\( f(x) > 0 \)) and where it is negative (\( f(x) < 0 \)).
02
Solve the Inequality \(f(x) > 0\)
Set the inequality \( \frac{1}{4}x^3 - 2 > 0 \). Add 2 to both sides: \( \frac{1}{4}x^3 > 2 \). Multiply both sides by 4 to clear the fraction: \( x^3 > 8 \). Take the cube root: \( x > 2 \). Thus, \( f(x) \) is positive for \( x > 2 \).
03
Solve the Inequality \(f(x) < 0\)
Set the inequality \( \frac{1}{4}x^3 - 2 < 0 \). Add 2 to both sides: \( \frac{1}{4}x^3 < 2 \). Multiply both sides by 4: \( x^3 < 8 \). Take the cube root: \( x < 2 \). Thus, \( f(x) \) is negative for \( x < 2 \).
04
Combine the Solutions
From the previous steps, we found that \( f(x) > 0 \) when \( x > 2 \) and \( f(x) < 0 \) when \( x < 2 \). At \( x = 2 \), \( f(x) = 0 \).
05
Sketch the Graph of \(f(x)\)
Plot the critical point where \( x = 2 \), \( f(x) = 0 \). The graph of \( f(x) \) is a cubic graph and passes through \( y = -2 \) when \( x = 0 \). It crosses the x-axis at \( x = 2 \) because this is where \( f(x) = 0 \). For \( x < 2 \), the graph is below the x-axis (negative), and for \( x > 2 \), it is above the x-axis (positive). Draw a smooth S-shaped curve reflecting these behaviors.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inequalities
When dealing with inequalities involving a cubic function like \(f(x) = \frac{1}{4}x^3 - 2\), we seek to determine the intervals on which the function is positive or negative. Specifically:
By taking cube roots, we find the critical points at \(x = 2\), allowing us to conclude that:
- \(f(x) > 0\): Here, we want to find all \(x\) such that the function yields a positive result. This inequality signifies that the cubic graph lies above the x-axis.
- \(f(x) < 0\): In this case, \(x\) values should produce a negative \(f(x)\), meaning the graph is below the x-axis.
By taking cube roots, we find the critical points at \(x = 2\), allowing us to conclude that:
- \(f(x) > 0\) for \(x > 2\)
- \(f(x) < 0\) for \(x < 2\)
Graph Sketching
Graph sketching is a helpful tool to visually understand the behavior of functions across their domains. For a cubic function, we expect the graph to have an "S" shape due to its third-degree polynomial nature.When sketching the graph of \(f(x) = \frac{1}{4}x^3 - 2\), note the following:
- The function crosses the x-axis at \(x = 2\), where \(f(x) = 0\). This point is crucial as it divides the graph into the regions where the function is positive and negative.
- At \(x = 0\), the function value is \(f(x) = -2\), providing another point to help anchor the graph below the x-axis initially.
- The graph transitions from negative to positive as it moves from left to right across \(x = 2\).
Polynomial Functions
Polynomial functions are amongst the fundamental building blocks in algebra, characterized by terms that involve powers of \(x\), with coefficients. The function \(f(x) = \frac{1}{4}x^3 - 2\) is a specific type of polynomial, known as a cubic polynomial, due to its highest power being three.Key points to note:
- The leading term, \(\frac{1}{4}x^3\), dictates the function's end behavior. For large positive or negative \(x\), the function will increase or decrease without bound due to this term.
- The constant term, \(-2\), shifts the entire graph up or down on the y-axis.
- Cubic polynomials can have up to three x-intercepts, but in this case, we have one real root at \(x = 2\).