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Group discount A travel agency offers group tours at a rate of \(\$ 60\) per person for the first 30 participants. For larger groups - up to \(90-\) each person receives a \(\$ 0.50\) discount for every participant in excess of \(30 .\) For example, if 31 people participate, then the cost per person is \(\$ 59.50\). Determine the size of the group that will produce the maximum amount of money for the agency.

Short Answer

Expert verified
75 participants maximize agency revenue.

Step by step solution

01

Understand the Problem

The agency charges $60 per person for the first 30 participants, and for each additional participant, the cost per person decreases by $0.50. We need to find the group size that maximizes the total revenue.
02

Set Up the Revenue Function

Define the number of participants beyond 30 as \( x \), so the total number of people is \( 30 + x \). The price per person is then \( 60 - 0.5x \). The revenue \( R \) can be defined as a function of \( x \), which is \( R(x) = (30 + x)(60 - 0.5x) \).
03

Simplify the Revenue Function

Expand the equation: \[ R(x) = 30(60 - 0.5x) + x(60 - 0.5x) \] which simplifies to:\[ R(x) = 1800 - 15x + 60x - 0.5x^2 \]. Simplify further: \[ R(x) = 1800 + 45x - 0.5x^2 \].
04

Find the Maximum Revenue

The revenue function \( R(x) = 1800 + 45x - 0.5x^2 \) is a quadratic equation. To find the maximum revenue, we find the vertex of the parabola, which occurs at \( x = -\frac{b}{2a} \). Here, \( a = -0.5 \) and \( b = 45 \), so:\[ x = -\frac{45}{2(-0.5)} = 45 \].
05

Calculate Total Group Size

The additional participants \( x = 45 \) mean the total number of participants is \( 30 + 45 = 75 \). This is the size of the group that maximizes revenue.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
In the realm of mathematics, a quadratic function is a type of polynomial which takes the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, with \( a eq 0 \). These functions form a parabolic shape when graphed on a coordinate plane. For our exercise, the revenue function \( R(x) = 1800 + 45x - 0.5x^2 \) is quadratic. Quadratic functions are fundamental for modeling various real-world situations like our group's pricing strategy. They are known for displaying a single highest or lowest point along their curve.

Why are quadratics important here? They help us determine the maximum or minimum values by finding the peak of the parabola. This trait is invaluable in optimization problems across different fields, such as economics and physics, where the greatest efficiency or output is often sought after.
Key concepts to remember include:
  • The general form: \( ax^2 + bx + c \).
  • The parabolic curve which either opens upwards \((a > 0)\) or downwards \((a < 0)\).
  • The vertex, indicating the maximum or minimum value.
Parabola Vertex
The parabola vertex is crucial in determining where the maximum or minimum of a quadratic function occurs. In our context, understanding the parabola's vertex allows us to find the group size that generates the highest revenue.

For a quadratic function \( ax^2 + bx + c \), the vertex \((h, k)\) can be found using the formula \( h = -\frac{b}{2a} \). This gives you the x-value where the maximum or minimum point lies. Once you've found \( x \), you can plug this back into the function to find the corresponding \( y \)-value.
This is exactly what we did in the exercise. Using \( R(x) = 1800 + 45x - 0.5x^2 \), we calculated the vertex to find the additional participants \( x = 45 \). Then, the group size total was \( 30 + 45 = 75 \).

Key takeaways regarding the parabola vertex:
  • The vertex formula helps identify extreme values.
  • The vertex formula is \( h = -\frac{b}{2a} \).
  • This point on the parabola gives us the maximum revenue, in our specific problem.
Price Optimization
Price optimization involves adjusting the price of goods or services to achieve the highest possible revenue or profit. It's a crucial application of revenue maximization and leverages mathematical concepts like quadratic functions to make informed decisions.

In our exercise, price optimization was necessary because altering the price per person after 30 participants changed the revenue dynamics. As more participants joined, the price per person decreased by $0.50, forming the entire revenue function \( R(x) = 1800 + 45x - 0.5x^2 \). By using these principles, the travel agency could determine the optimal number of participants to maximize their revenue.
For practical use, understanding price optimization means:
  • Balancing the number of participants with the price per person.
  • Using tools like quadratic functions to find optimum pricing.
  • Adjusting other factors that may influence revenue, like demand or cost of service.
Achieving the right price results in maximum profitability and competitive advantage.

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