Chapter 2: Problem 32
Sketch the graph of the circle or semicircle. $$9 x^{2}+9 y^{2}=4$$
Short Answer
Expert verified
The graph depicts a circle centered at the origin with radius \(\frac{2}{3}\).
Step by step solution
01
Understand the Equation
The given equation of the circle is \(9x^2 + 9y^2 = 4\). This equation represents a circle because it can be expressed in the standard form \(x^2 + y^2 = r^2\).
02
Simplify the Equation
Divide every term in the equation \(9x^2 + 9y^2 = 4\) by 9 to simplify it. This results in \(x^2 + y^2 = \frac{4}{9}\), which is in the standard form of a circle equation \(x^2 + y^2 = r^2\).
03
Identify the Radius
The equation \(x^2 + y^2 = \frac{4}{9}\) shows us that the circle is centered at the origin with a radius \(r = \sqrt{\frac{4}{9}} = \frac{2}{3}\).
04
Sketch the Circle
Draw a coordinate plane. Since the circle is centered at the origin, mark the center at (0,0). From the center, draw a circle with a radius extending \(\frac{2}{3}\) units in all directions (up, down, left, right). Ensure the circle touches as close as possible to the lines produced by \(x = \frac{2}{3}\), \(x = -\frac{2}{3}\), \(y = \frac{2}{3}\), and \(y = -\frac{2}{3}\).
05
Verify the Graph
Confirm that all points on the circle satisfy the equation \(x^2 + y^2 = \frac{4}{9}\). For example, the point \((\frac{2}{3}, 0)\) satisfies the equation, as does the point \((0, \frac{2}{3})\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of a Circle
The equation of a circle in its standard form is given by \[ x^2 + y^2 = r^2 \]where \(r\) represents the radius of the circle. In this equation, the center of the circle is located at the origin
To identify a circle from an equation, you need to first place it in the standard form. For example, in the original equation, \(9x^2 + 9y^2 = 4\), we can see every term multiplied by 9.
By dividing the whole equation by 9, it transforms into \( x^2 + y^2 = \frac{4}{9}\), which nicely fits the standard form and confirms it represents a circle.
- (0,0)
- (x,y)
To identify a circle from an equation, you need to first place it in the standard form. For example, in the original equation, \(9x^2 + 9y^2 = 4\), we can see every term multiplied by 9.
By dividing the whole equation by 9, it transforms into \( x^2 + y^2 = \frac{4}{9}\), which nicely fits the standard form and confirms it represents a circle.
Radius Calculation
The radius of a circle is the distance from the center to any point on its circumference. To find the radius in a given circle equation:
This gives us the radius:\[ r = \sqrt{\frac{4}{9}} = \frac{2}{3} \]
Therefore, the radius is \(\frac{2}{3}\) units. Calculating the square root is essential to understand how much the circle extends from its center. This process is critical for accurately sketching the graph.
- First, convert the equation to the standard form \(x^2 + y^2 = r^2\).
- The term on the right side of the equation, \(r^2\), is used to calculate the radius \(r\).
This gives us the radius:\[ r = \sqrt{\frac{4}{9}} = \frac{2}{3} \]
Therefore, the radius is \(\frac{2}{3}\) units. Calculating the square root is essential to understand how much the circle extends from its center. This process is critical for accurately sketching the graph.
Coordinate Graphing
Graphing a circle involves plotting it on a coordinate plane based on its equation in the standard form. Here’s how you can do it step by step:
This visual representation validates that every point \( (x, y) \) on the circle satisfies the equation \(x^2 + y^2 = \frac{4}{9}\). Coordinate graphing this way helps visualize the actual geometry of the circle and links algebraic equations to geometric figures.
- Identify the center of the circle. For the equation \(x^2 + y^2 = \frac{4}{9}\), the circle's center is at (0,0).
- Identify the radius, which we calculated as \(\frac{2}{3}\).
- Properly draw the coordinate axis. The origin (0,0) should be marked clearly at the center.
- Using the radius, mark points at this distance around the center. You'll reach points such as (\(\frac{2}{3}, 0\)), (\(0, \frac{2}{3}\)) on the coordinate plane.
This visual representation validates that every point \( (x, y) \) on the circle satisfies the equation \(x^2 + y^2 = \frac{4}{9}\). Coordinate graphing this way helps visualize the actual geometry of the circle and links algebraic equations to geometric figures.