Chapter 2: Problem 29
Sketch the graph of the circle or semicircle. $$(x+3)^{2}+y^{2}=16$$
Short Answer
Expert verified
Circle center: (-3, 0); Radius: 4.
Step by step solution
01
Identify the Circle Equation Form
The given equation of the circle is \((x+3)^2 + y^2 = 16\). This is in the standard form for a circle, \((x-h)^2 + (y-k)^2 = r^2\) where \((h, k)\) is the center and \(r\) is the radius.
02
Determine the Center of the Circle
Compare the given equation \((x+3)^2 + y^2 = 16\) with the standard form \((x-h)^2 + (y-k)^2 = r^2\). We find that \(h = -3\) and \(k = 0\), so the center of the circle is \((-3, 0)\).
03
Find the Radius of the Circle
The equation \((x+3)^2 + y^2 = 16\) shows that \(r^2 = 16\). Taking the square root, the radius \(r = \sqrt{16} = 4\).
04
Sketch the Circle
With the center at \((-3, 0)\) and radius 4, sketch the circle on a coordinate plane. The circle will be centered at point \((-3, 0)\) and will pass through points 4 units away in all directions - horizontally, vertically, and diagonally.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Circle Equation
The equation of a circle is a crucial idea in coordinate geometry. It helps define the shape and location of a circle on the coordinate plane. The standard form of a circle's equation is \((x-h)^2 + (y-k)^2 = r^2\). In this equation:
In the specific example, \((x+3)^2+y^2=16\), \(h\) is \(-3\), \(k\) is \(0\), and \(r^2=16\). This tells you the circle's center is shifted left by 3 units on the \(x\)-axis, and the radius squared is 16.
- \((h, k)\) represents the center of the circle.
- \(r\) is the radius, or the distance from the center to any point on the circle.
In the specific example, \((x+3)^2+y^2=16\), \(h\) is \(-3\), \(k\) is \(0\), and \(r^2=16\). This tells you the circle's center is shifted left by 3 units on the \(x\)-axis, and the radius squared is 16.
Center and Radius
Determining the center and radius from a circle equation involves comparing it to the standard form and extracting values directly. The **center** of the circle is found at point \((h, k)\). In our example, \((x+3)^2 + y^2 = 16\) has
Finding the Center
The center, \(h\), is derived from the expression \((x+3)^2\), which corresponds to \((x-h)^2\). If you equate \((x-h)\) with \((x+3)\), \(h\) becomes \(-3\). Meanwhile, the \(y\) term \(y^2\) indicates that \(k\) is \(0\). Thus, the center is \((-3, 0)\).Calculating the Radius
The radius, \(r\), is the square root of the equation's right side. From \(r^2=16\), the radius \(r\) calculates to \(4\). This value for the radius shows that all points on the circle are 4 units from the center in every direction.Coordinate Plane
Graphing a circle on the coordinate plane involves positioning its center and drawing its outline based on the radius.
Placing the Center
The center of the circle from our example is \((-3, 0)\). On a coordinate plane, this point is located 3 units left along the \(x\)-axis, while remaining at the origin level on the \(y\)-axis.Drawing the Circle
Once centered at \((-3, 0)\), use the radius to draw the circle. Imagine or lightly draw a point 4 units outwards from the center in:- The positive and negative directions along the \(x\)-axis and \(y\)-axis, creating points like \((1,0)\) and \((-3,4)\).
- These points guide you to sketch a round shape.