Chapter 2: Problem 21
Sketch, on the same coordinate plane, the graphs of \(f\) for the given values of \(c\). (Make use of symmetry, shifting, stretching, compressing, or reflecting.) $$f(x)=c \sqrt{4-x^{2}} ; \quad c=-2,1,3$$
Short Answer
Expert verified
Draw semicircles for each \(c\) value, considering stretching and reflection.
Step by step solution
01
Understanding the Function
The function given is \(f(x) = c \sqrt{4 - x^2}\). This is a transformation of the basic function \(g(x) = \sqrt{4 - x^2}\), which is a semicircle with radius 2 centered at the origin on the x-axis.
02
Identify Base Graph
The graph of \(g(x) = \sqrt{4-x^2}\), is the top half of a circle of radius 2, centered at the origin. It has endpoints at (-2,0) and (2,0), and the highest point at (0,2).
03
Effect of Parameter c
The parameter \(c\) acts as a vertical stretch/shrink and a reflection. \(f(x) = c \cdot g(x)\) will scale \(g(x)\) vertically by a factor of \(|c|\), and if \(c < 0\), it will also reflect it across the x-axis.
04
Sketch for c = -2
For \(c = -2\), the graph of \(-2 \sqrt{4 - x^2}\) is a reflection of \(\sqrt{4 - x^2}\) about the x-axis, and then vertically stretched by a factor of 2. This semicircle will have its highest absolute point of \((0, -4)\). Endpoints remain at (-2,0) and (2,0).
05
Sketch for c = 1
For \(c = 1\), the graph \(1 \cdot \sqrt{4 - x^2}\) is the same as the base graph \(g(x)\). The graph remains the top half of a circle with endpoints at (-2,0) and (2,0), and the highest point at (0,2).
06
Sketch for c = 3
For \(c = 3\), the graph \(3 \cdot \sqrt{4 - x^2}\) is the original semicircle vertically stretched by a factor of 3. The graph has a highest point at (0,6), with endpoints still at (-2,0) and (2,0).
07
Combine Sketches
On the same coordinate plane, sketch the semicircles for each value of \(c\):- For \(c = -2\), draw the reflected and stretched semicircle reaching down to (0,-4).- For \(c = 1\), draw the standard semicircle reaching up to (0,2).- For \(c = 3\), draw the stretched semicircle reaching up to (0,6).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertical Stretching
Vertical stretching is a transformation that scales a function along the y-axis by multiplying the function by a constant. In our example, the base function is a semicircle equation, and we apply vertical stretching through the parameter \( c \). When \( c = 1 \), there is no vertical stretching since \( f(x) = \sqrt{4 - x^2} \) remains unchanged. However, for \( c = 3 \), we have \( f(x) = 3 \sqrt{4 - x^2} \), meaning that the semicircle is stretched vertically. The maximum height of the semicircle changes from \( 2 \) to \( 6 \), effectively tripling the y-values of all points on the curve.
- Vertical stretching changes the height and shape of a graph.
- The greater the value of \( c \), the more the graph stretches vertically.
- It's important to note that endpoints along the x-axis remain unchanged.
Reflection Across X-Axis
Reflection across the x-axis involves flipping a graph over the x-axis. This occurs when the parameter \( c \) in our function is negative. For our semicircle function, this is represented mathematically as \( f(x) = c \cdot \sqrt{4 - x^2} \) where \( c < 0 \). Consider \( c = -2 \) from our exercise. The function becomes \( f(x) = -2 \sqrt{4 - x^2} \). First, we reflect the positive semicircle across the x-axis, turning all positive y-values negative. Then, due to the magnitude (\( 2 \)), the semicircle stretches twice as much downward.
- Reflection flips all positive y-values to negative.
- It results in a mirror image being formed below the x-axis.
- Reflection influences both shape and position on the coordinate plane.
Semicircle Graph
The semicircle graph is a simple yet important geometric shape often used in transformations. Represented by \( \, \sqrt{4 - x^2} \) in its basic form, it depicts the top half of a circle.This graph is centered at the origin with a radius of \( 2 \), reaching from \( -2 \) to \( 2 \) on the x-axis. By identifying the original semicircle graph, one can understand transformations better.
- Endpoints lie at (-2, 0) and (2, 0).
- The peak (or highest point) is at (0,2) for the untransformed graph.
- Transforms such as stretching or reflection change the graph's shape but not its x-values.
Graph Sketching
Graph sketching involves plotting a visual representation of functions on a coordinate plane. It is both an art and a science which facilitates understanding of how different values transform a base graph.To sketch graphs with varying \( c \) values, combine knowledge of vertical stretching, reflection, and the semicircle graph.
- First, sketch the base function, here it's: \( \sqrt{4 - x^2} \).
- Apply the transformation for each \( c \): \(-2\), \(1\), and \(3\).
- Ensure distinct sketches for each transformation on the same plane.