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(a) Use the quadratic formula to find the zeros of \(f .\) (b) Find the maximum or minimum value of \(f(x)\) (c) Sketch the graph of \(f\) $$f(x)=-4 x^{2}+4 x-1$$

Short Answer

Expert verified
The zero is \( x = \frac{1}{2} \), the maximum value is 0, and the graph is a downward-opening parabola peaking at the vertex \( (\frac{1}{2}, 0) \).

Step by step solution

01

Determine the Coefficients

To use the quadratic formula, identify the coefficients of the quadratic equation \( f(x) = -4x^2 + 4x - 1 \). Here, \( a = -4 \), \( b = 4 \), and \( c = -1 \).
02

Apply the Quadratic Formula

Substitute the coefficients into the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Plug in the values: \[ x = \frac{-4 \pm \sqrt{4^2 - 4(-4)(-1)}}{2(-4)} \]This simplifies to: \[ x = \frac{-4 \pm \sqrt{16 - 16}}{-8} \]Thus, \( x = \frac{-4 \pm \sqrt{0}}{-8} \), which further simplifies to \( x = \frac{-4}{-8} \) or \( x = \frac{1}{2} \).
03

Find the Vertex

The vertex form of a quadratic function is given by \( f(x) = ax^2 + bx + c = a(x-h)^2 + k \), where \( (h, k) \) is the vertex and the value at \( h \) gives the maximum or minimum. Calculate \( h \) using \( h = -\frac{b}{2a} \):\[ h = -\frac{4}{2(-4)} = \frac{1}{2} \]Now, find \( k \) by substituting \( h \) back into \( f(x) \):\[ k = f\left(\frac{1}{2}\right) = -4\left(\frac{1}{2}\right)^2 + 4\left(\frac{1}{2}\right) - 1 \]\[ k = -4 \cdot \frac{1}{4} + 2 - 1 = -1 + 2 - 1 = 0 \]Therefore, the vertex is \( (\frac{1}{2}, 0) \) and it provides a maximum value of 0.
04

Sketch the Graph

Using the vertex \( (\frac{1}{2}, 0) \) and the information that the graph opens downwards (since \( a = -4 \), which is negative), plot the graph. The zero found earlier at \( x = \frac{1}{2} \) makes the vertex the x-intercept. Draw the parabola showing it opening downwards and peaking at the vertex.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are equations of the form \( f(x) = ax^2 + bx + c \). If you want to find the zeros of a quadratic function, meaning the points where its graph crosses the x-axis, the quadratic formula can help. It's expressed as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula helps you determine the values of \( x \) when \( f(x) = 0 \). Here's how you can apply it:
  • Identify the coefficients \( a \), \( b \), \( c \) from your quadratic function. For example, in \( f(x) = -4x^2 + 4x - 1 \), we have \( a = -4 \), \( b = 4 \), and \( c = -1 \).
  • Plug these values into the formula to find the roots, \( x = \frac{-4 \pm \sqrt{16 - 16}}{-8} \), which simplifies to \( x = \frac{1}{2} \). In this case, the discriminant \( \sqrt{b^2 - 4ac} \) is zero, indicating one repeated root.
Using the quadratic formula not only helps find the zeros, but it also gives insight into the nature of the function's roots by examining the discriminant \( (b^2 - 4ac) \). A positive discriminant indicates two real roots, a zero discriminant indicates one real root, and a negative discriminant indicates complex roots.
Vertex of a Parabola
Finding the vertex of a parabola is crucial, especially when determining whether the parabola has a maximum or minimum value. The vertex can be understood as the peak (maximum) or the trough (minimum) of the graph. For a parabola given as \( ax^2 + bx + c \), the x-coordinate of the vertex \( (h,k) \) can be found using:\[ h = -\frac{b}{2a}\]After calculating \( h \), substitute it back into the function to find \( k \).
  • In \( f(x) = -4x^2 + 4x - 1 \), calculate \( h \): \( h = -\frac{4}{2(-4)} = \frac{1}{2} \).
  • Use this value to find \( k \): \( k = f\left(\frac{1}{2}\right) = 0 \), making the vertex \( \left(\frac{1}{2}, 0\right) \).
A negative leading coefficient, as \( a = -4 \), implies the parabola opens downwards, and thus has a maximum at the vertex. Here, the maximum value of the function is 0, occurring at \( x = \frac{1}{2} \). Understanding the vertex is essential in graphing quadratics as it serves as a guide for the direction and position of the parabola.
Graphing Quadratics
Graphing quadratic functions involves plotting a parabola on a coordinate plane. These functions can be graphed systematically by understanding their key features: the vertex, axis of symmetry, direction, and intercepts.To start, identify the vertex, which is \( \left(\frac{1}{2}, 0\right) \) for the function \( f(x) = -4x^2 + 4x - 1 \). This tells us the highest point on the graph since the parabola opens downward.Several steps are involved in sketching the graph:
  • Vertex: Plot the vertex point on the graph.
  • Axis of Symmetry: Draw a vertical line through the vertex. The parabola is symmetric about this line.
  • Direction: Since \( a = -4 \) is negative, the parabola opens downward.
  • Zero: As solved using the quadratic formula, the parabola touches the x-axis at \( x = \frac{1}{2} \). This intersection is both a vertex and a root.
Understanding these aspects will help you correctly draw the parabola on a graph. The vertex shows where the parabola reaches its peak, the axis of symmetry provides balance, and the zeros indicate where the function crosses the x-axis.

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