Chapter 10: Problem 20
Find an equation in \(x\) and \(y\) whose graph contains the points on the curve \(C\). Sketch the graph of \(C\), and indicate the orientation. $$x=\boldsymbol{e}^{t}, \quad \boldsymbol{y}=\boldsymbol{e}^{-t}\quad t \text { in } \mathbb{R}$$
Short Answer
Expert verified
The equation is \( y = 1/x \). The graph is a hyperbola with orientation from (1,1) down to the fourth quadrant as \( t \) increases.
Step by step solution
01
Understand the Given Parametric Equations
We are given the parametric equations: \( x = e^t \) and \( y = e^{-t} \). These represent a relationship between \( x \) and \( y \) through the parameter \( t \), which is a real number.
02
Express One Parameter in Terms of Another
To eliminate the parameter \( t \), we can express \( t \) in terms of \( x \) using the equation \( x = e^t \). Take the natural logarithm on both sides to obtain \( t = \ln x \).
03
Substitute to Eliminate Parameter
Substitute \( t = \ln x \) into the equation for \( y = e^{-t} \). Since \( y = e^{-t} = 1/e^t \), and knowing \( e^t = x \), it follows that \( y = 1/x \). This is the equation in terms of \( x \) and \( y \).
04
Check the Equation
Check the derived equation \( y = 1/x \) by substituting back into the parameterized form. If \( x = e^t \), \( y = 1/x = 1/e^t = e^{-t} \), which matches the original parameterization for \( y \). The equation is correct.
05
Sketch the Graph
The equation \( y = 1/x \) is the equation of a rectangular hyperbola. It consists of two branches in the first and third quadrants of the Cartesian plane. Both branches approach the x-axis and y-axis but never touch them.
06
Indicate the Orientation
The orientation of the curve as \( t \) increases is from the point (1, 1) towards the fourth quadrant along the branch in the first quadrant, and from the point (-1, -1) towards the second quadrant along the branch in the third quadrant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graph Sketching
Graph sketching is a critical step in visualizing mathematical equations. By graphing equations, we can better understand their properties and behaviors. In this exercise, we consider the equation derived from parametric forms: \( y = \frac{1}{x} \). This equation represents a rectangular hyperbola. To sketch, identify key characteristics:
- The hyperbola has two main branches located symmetrically about both axes.
- The x-axis and y-axis act as asymptotes, which means the branches approach them but never actually touch or cross.
Equation Derivation
Equation derivation involves eliminating parameters to form a direct relationship between variables. In this situation, starting with the parametric equations \( x = e^t \) and \( y = e^{-t} \), our objective was to express \( y \) directly in terms of \( x \). First, recognize that expressing \( t \) as a function of \( x \) helps eliminate the parameter. Since \( x = e^t \), rewrite it using logarithms to isolate \( t \): \( t = \ln x \). Substituting back into the second equation \( y = e^{-t} \), we replace \( t \) with \( \ln x \), simplifying it to \( y = e^{-\ln x} = \frac{1}{e^{\ln x}} = \frac{1}{x} \).Thus, the parameter-free equation is \( y = \frac{1}{x} \). This equation signifies a hyperbola and simplifies the relationship between \( x \) and \( y \) without the intermediary variable \( t \), making analysis easier and more direct.
Hyperbola
A hyperbola is a type of curve on a plane, defined by its distinct geometric properties. In this context, the equation \( y = \frac{1}{x} \) describes a rectangular hyperbola. A hyperbola consists of two disconnected curves, or branches, which reflect symmetrically relative to the origin and their respective asymptotes.Key features of the hyperbola:
- It has asymptotes, lines that the branches of the hyperbola approach but do not intersect.
- The curve is symmetric about the lines \( y = x \) and \( y = -x \), especially visible in rectangular hyperbolas.
- As \( x \) moves towards zero, \( y \) tends towards infinity.
- Similarly, as \( x \) becomes very large or very small, \( y \) tends towards zero.
Orientation of Curves
The orientation of curves describes the direction in which a curve is traced as the parameter increases. For the parametric equations \( x = e^t \) and \( y = e^{-t} \), understanding orientation helps to predict and comprehend movement along the curve. When plotting the hyperbola \( y = \frac{1}{x} \), relate
- The orientation is from (1, 1) moving towards the fourth quadrant while \( x \) increases in the first quadrant.
- Likewise, for negative values, it begins at (-1, -1) leading to the second quadrant in the third quadrant.