Chapter 1: Problem 29
Write the expression in the form \(a+b i\), where a and \(b\) are real numbers. $$(2-\sqrt{-4})(3-\sqrt{-16})$$
Short Answer
Expert verified
The expression is \(14 - 14i\).
Step by step solution
01
Simplify Complex Numbers
First, simplify the expressions with square roots of negative numbers. The square root of a negative number can be expressed in terms of imaginary unit \(i\), where \(i = \sqrt{-1}\). Thus, \(\sqrt{-4} = 2i\) and \(\sqrt{-16} = 4i\). Substitute these into the expression to get \((2-2i)(3-4i)\).
02
Apply the Distributive Property
To expand \((2-2i)(3-4i)\), apply the distributive property (also known as FOIL for binomials). That involves multiplying each term in the first bracket by each term in the second bracket. This yields: \(2 \cdot 3 + 2 \cdot (-4i) - 2i \cdot 3 - 2i \cdot 4i\).
03
Calculate Each Term
Calculate each term from the expansion:- \(2 \cdot 3 = 6\)- \(2 \cdot (-4i) = -8i\)- \(-2i \cdot 3 = -6i\)- \(-2i \cdot 4i = -8i^2\).
04
Simplify the Result
Combine the real and imaginary components. The term \(-8i^2\) simplifies since \(i^2 = -1\), therefore \(-8i^2 = 8\). Combine to find\[6 + 8 - 8i - 6i = 14 - 14i\].
05
Write in Standard Form
Write the simplified expression in the standard form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. The expression is now \(14 - 14i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Unit
The concept of the imaginary unit is pivotal in understanding complex numbers. A complex number is a number that comprises a real part and an imaginary part and is often expressed in the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. The imaginary unit is denoted by \(i\) and is defined as \(i = \sqrt{-1}\). This definition allows us to express the square roots of negative numbers in terms of \(i\).
For example, the square root of \(-4\) is \(\sqrt{-4} = \sqrt{4} \cdot \sqrt{-1} = 2i\), and similarly, \(\sqrt{-16} = 4i\). Utilizing \(i\) enables the simplification of expressions involving square roots of negative numbers, paving the way for handling complex numbers with ease.
For example, the square root of \(-4\) is \(\sqrt{-4} = \sqrt{4} \cdot \sqrt{-1} = 2i\), and similarly, \(\sqrt{-16} = 4i\). Utilizing \(i\) enables the simplification of expressions involving square roots of negative numbers, paving the way for handling complex numbers with ease.
Distributive Property
The distributive property is a fundamental rule in algebra that helps in the expansion of expressions. It states that for any numbers \(a\), \(b\), and \(c\), the equation \(a(b+c) = ab + ac\) holds true. This property is especially useful when expanding products of binomials, such as in our example.
When expanding the expression \((2-2i)(3-4i)\), the distributive property is applied by treating each term separately:
When expanding the expression \((2-2i)(3-4i)\), the distributive property is applied by treating each term separately:
- Multiply each term in the first binomial \((2 - 2i)\) by each term in the second binomial \((3 - 4i)\).
- This results in: \(2 \cdot 3\), \(2 \cdot (-4i)\), \(-2i \cdot 3\), and \(-2i \cdot 4i\).
Binomial Expansion
Binomial expansion in the context of complex numbers involves applying the distributive property to obtain a final expression in its simplest form. A binomial expression is one that includes two terms, as seen in \((2-2i)\) and \((3-4i)\) in our example. The process of expanding these binomials involves using the FOIL method, an acronym that stands for First, Outside, Inside, Last:
- First: Multiply the first terms in each binomial: \(2 \cdot 3\).
- Outside: Multiply the outer terms: \(2 \cdot (-4i)\).
- Inside: Multiply the inner terms: \(-2i \cdot 3\).
- Last: Multiply the last terms: \(-2i \cdot 4i\).