Chapter 1: Problem 10
Express as a polynomial. $$(\sqrt{x}+\sqrt{y})^{2}(\sqrt{x}-\sqrt{y})^{2}$$
Short Answer
Expert verified
The expression simplifies to the polynomial \( x^2 - 2xy + y^2 \).
Step by step solution
01
Expand the First Expression
Start by expanding \( (\sqrt{x} + \sqrt{y})^2 \) using the formula for a perfect square: \[ (a + b)^2 = a^2 + 2ab + b^2 \] Thus, \( (\sqrt{x} + \sqrt{y})^2 = x + 2\sqrt{x}\sqrt{y} + y \).
02
Expand the Second Expression
Similarly, expand \( (\sqrt{x} - \sqrt{y})^2 \) using the formula for a perfect square: \[ (a - b)^2 = a^2 - 2ab + b^2 \] Thus, \( (\sqrt{x} - \sqrt{y})^2 = x - 2\sqrt{x}\sqrt{y} + y \).
03
Multiply the Expanded Expressions
Now multiply the two expanded results from Steps 1 and 2: \[ (x + 2\sqrt{x}\sqrt{y} + y)(x - 2\sqrt{x}\sqrt{y} + y) \].
04
Apply the Difference of Squares Formula
Recognize the expression as a difference of squares: \[ (a+b)(a-b) = a^2 - b^2 \] Let \( a = x + y \) and \( b = 2\sqrt{x}\sqrt{y} \). Thus, \[ (x + y)^2 - (2\sqrt{x}\sqrt{y})^2 \].
05
Simplify Each Term
Calculate each part of the expression: \( (x+y)^2 = x^2 + 2xy + y^2 \) and \( (2\sqrt{x}\sqrt{y})^2 = 4xy \).
06
Combine the Expressions
Subtract the squared terms: \[ x^2 + 2xy + y^2 - 4xy \]. Simplify it to: \[ x^2 - 2xy + y^2 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Expanding Expressions
Expanding expressions is a crucial step in dealing with polynomial expressions. It involves multiplying out expressions enclosed in parentheses to simplify or reformat them. Let's take the expression
- \( (\sqrt{x} + \sqrt{y})^2 \).
- \((a + b)^2 = a^2 + 2ab + b^2\),
- \(x + 2\sqrt{x}\sqrt{y} + y\).
- \((\sqrt{x} - \sqrt{y})^2\),
- \(x - 2\sqrt{x}\sqrt{y} + y\).
Perfect Square Formulas
The perfect square formula is an essential tool for simplifying algebraic expressions. It helps in expanding expressions like \((a + b)^2\) or \((a - b)^2\). These formulas are comprised of three main parts:
- \(a^2\)
- \(2ab\)
- \(b^2\)
- \(x + 2\sqrt{x}\sqrt{y} + y\).
- \(x - 2\sqrt{x}\sqrt{y} + y\).
Difference of Squares
The difference of squares is a mathematical formula used to factor expressions. It simplifies the multiplication of terms such as
- \((a+b)(a-b)\)
- \(a^2 - b^2\).
- \((x + 2\sqrt{x}\sqrt{y} + y)(x - 2\sqrt{x}\sqrt{y} + y)\).
- \((x+y)^2 - (2\sqrt{x}\sqrt{y})^2\).
Simplifying Expressions
The final step in handling polynomial expressions usually involves simplification. After expanding and applying the difference of squares, you are left with a more complex expression that appears as
- \((x+y)^2 - (2\sqrt{x}\sqrt{y})^2\).
- \((x+y)^2 = x^2 + 2xy + y^2\)
- \((2\sqrt{x}\sqrt{y})^2 = 4xy\).
- \(x^2 - 2xy + y^2\).