/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Simplify the permutation. $$P(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify the permutation. $$P(n, 0)$$

Short Answer

Expert verified
The simplified permutation \(P(n, 0)\) is 1.

Step by step solution

01

Understand the Concept

Permutations, denoted as \(P(n, r)\), represent the arrangement of \(r\) objects from a set of \(n\) objects. When \(r = 0\), it means we want to arrange zero objects.
02

Apply Permutation Formula

The formula for permutations is given by \(P(n, r) = \frac{n!}{(n-r)!}\). When \(r = 0\), substitute into the formula to get \(P(n, 0) = \frac{n!}{(n-0)!}\).
03

Simplify the Expression

Simplifying the expression from the previous step, we get \(P(n, 0) = \frac{n!}{n!}\).
04

Calculate the Result

Since the factorial of a number divided by itself is 1, we have \(P(n, 0) = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation Formula
The permutation formula is a fundamental tool in set theory and combinatorics, used to determine the number of ways to arrange or order certain items. Mathematically, permutations are noted as \( P(n, r) \), where \(n\) denotes the total number of items in a set, while \(r\) indicates the number of items to be arranged or selected from this set. The formula for permutations is:\[P(n, r) = \frac{n!}{(n-r)!}\]This formula calculates the possible arrangements by taking into account that each selection reduces the pool of available choices. Therefore, it's dividing \(n!\) by \((n-r)!\) to account for the non-chosen elements. This results in a precise count of different sequential arrangements for \(r\) items from \(n\).
Understanding permutations is essential in fields where the order of elements is significant, such as in scheduling or cryptography.
Factorial
The factorial, often symbolized by an exclamation mark (!), is a mathematical operation that multiplies a number by every number below it down to one. Factorials are pivotal in many areas of mathematics, prominently in permutations and combinations.
For example:
  • \(3! = 3 \times 2 \times 1 = 6\)
  • \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\)
The concept of a factorial arises from the idea of counting permutations of items. When calculating permutations, factorials help to determine the number of potential arrangements by considering each item's place in a sequence. The factorial \(n!\) gives the total number of ways to organize \(n\) distinct items in a sequence.
Another important aspect is the definition of \(0!\), which is uniquely set to be 1 by convention, making calculations, especially involving permutations with zero selections, consistent and mathematically valid.
Permutations with Zero Items
Permutations with zero items is a scenario that might seem abstract initially. However, understanding \(P(n, 0)\) is crucial in grasping permutation concepts fully. When \(r = 0\), it means we are choosing zero items to arrange from \(n\) items.
The permutation formula simplifies to:\[P(n, 0) = \frac{n!}{(n-0)!} = \frac{n!}{n!}\]The division results in 1 because any non-zero number divided by itself is 1. This makes logical sense as there is exactly one way (doing nothing) to "arrange" zero items. This principle helps maintain consistency in mathematical operations and is foundational to understanding more complex arrangements and combinatorial arguments.
Recognizing that \(P(n, 0) = 1\) aligns our understanding with the reality that in some systems, the absence of elements or the 'empty set' itself is a valid configuration.*

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Most popular questions from this chapter

The outcomes \(1,2, \ldots, 6\) of an experiment and their probabilities are listed in the table. $$\begin{array}{l|cccccc}\\\\\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Probability } & 0.25 & 0.10 & 0.15 & 0.20 & 0.25 & 0.05 \\\\\hline\end{array}$$.For the Indicated events, find (a) \(P\left(E_{2}\right),\) (b) \(P\left(E_{1} \cap E_{2}\right)\) (c) \(P\left(E_{1} \cup E_{2}\right),\) and \((d) P\left(E_{2} \cup E_{3}^{\prime}\right)\). $$E_{1}=\\{1,2,3,6\\} ; \quad E_{2}=\\{3,4\\} ; \quad E_{3}=\\{4,5,6\\}$$

Exer. \(61-62:\) Some calculators use an algorithm similar to the following to approximate \(\sqrt{N}\) for a positive real number \(N:\) Let \(x_{1}=N / 2\) and find successive approximations \(x_{2}, x_{3}, \ldots\) by using $$ x_{2}=\frac{1}{2}\left(x_{1}+\frac{N}{x_{1}}\right), \quad x_{3}=\frac{1}{2}\left(x_{2}+\frac{N}{x_{2}}\right), \quad \dots $$ until the desired accuracy is obtained. Use this method to approximate the radical to six-decimal-place accuracy. $$\sqrt{18}$$

A committee is going to select 30 students from a pool of 1000 to receive scholarships. How many ways could the students be selected if each scholarship is worth the same amount? (b) a different amount?

Track ranidings Twelve sprinters are running a heat; those with the best four times will advance to the finals. (a) In how many ways can this group of four be selected? (b) If the four best times will be seeded (ranked) in the finals, in how many ways can this group of four be selected and seeded?

Exer. \(39-42:\) (a) Graph \(C(n, r)\) for the given value of \(n\) where \(r=1,2,3, \ldots, n .\) (b) Determine the maximum of \(C(n, r)\) and the value(s) of \(r\) where this maximum occurs. $$n=20$$

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