/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Show that \(\left(\begin{array}{... [FREE SOLUTION] | 91Ó°ÊÓ

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Show that \(\left(\begin{array}{l}n \\\ 0\end{array}\right)=\left(\begin{array}{l}n \\ n\end{array}\right)\) for \(n \geq 0\).

Short Answer

Expert verified
\( \binom{n}{0} = \binom{n}{n} = 1 \) for all \( n \geq 0 \).

Step by step solution

01

Understand the Notation

The notation \( \binom{n}{k} \) represents a binomial coefficient, which counts the number of ways to choose \( k \) elements from a set of \( n \) elements without considering the order.
02

Recall the Binomial Coefficient Formula

The binomial coefficient is defined as \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \), where \( n! \) ("n factorial") is the product of all positive integers up to \( n \).
03

Calculate \( \binom{n}{0} \)

Substituting \( k = 0 \) into the formula gives \( \binom{n}{0} = \frac{n!}{0!(n-0)!} = \frac{n!}{1 \cdot n!} = 1 \), since \( 0! = 1 \).
04

Calculate \( \binom{n}{n} \)

Substituting \( k = n \) into the formula gives \( \binom{n}{n} = \frac{n!}{n!(n-n)!} = \frac{n!}{n! \cdot 1} = 1 \).
05

Conclude the Equality

Since both \( \binom{n}{0} \) and \( \binom{n}{n} \) evaluate to 1 for any non-negative integer \( n \), we conclude that \( \binom{n}{0} = \binom{n}{n} \) for \( n \geq 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a fascinating field of mathematics that deals with counting, arrangement, and combination of objects. It explores the different ways you can select or arrange items from a given set. This branch of mathematics is incredibly useful in a variety of practical applications such as cryptography, logistics, and computer science.
In combinatorics, one common concept is the "combination," which refers to the selection of items from a set where the order does not matter. We often use binomial coefficients, denoted as \( \binom{n}{k} \), to represent combinations. These coefficients tell us how many ways we can choose \( k \) items from a collection of \( n \) items.
  • For example, the number of ways to choose 2 fruits from a set of 5 different fruits is a combination.
  • Unlike permutations, combinations do not consider the order of selection.
By understanding these basic concepts of combinatorics, students can tackle various problems involving arrangement and selection with ease.
Factorial Notation
Factorial notation is a fundamental aspect closely tied to combinatorics, particularly in calculating combinations and permutations. The factorial of a non-negative integer \( n \), written as \( n! \), is the product of all positive integers less than or equal to \( n \).
This notation is a convenient way to express calculations involving sequences of descending natural numbers.
  • For instance, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
  • Factorials grow at a very rapid pace, making them a crucial part of calculating large combinatorial expressions.
  • Special cases include \( 0! = 1 \), which is an important convention in mathematics used to simplify many combinatorial formulas.
Understanding factorial notation is key to grasping how we compute the number of combinations and permutations mathematically. It serves as the backbone of calculations in combinatorics.
Binomial Theorem
The Binomial Theorem is a powerful formula that expands expressions raised to a power. It is closely associated with the concept of binomial coefficients. According to the theorem, for any positive integer \( n \), the expression \( (x + y)^n \) can be expanded into a sum involving terms of the form \( \binom{n}{k}x^{n-k}y^k \).
This means each term in the expansion represents a combination of choosing \( k \) items. The coefficients for these terms are precisely the binomial coefficients \( \binom{n}{k} \).
  • The Binomial Theorem helps in efficiently expanding polynomial expressions without direct multiplication.
  • It is essential for understanding probabilities, particularly in binomial distributions often used in statistics.
Mastering the Binomial Theorem not only helps in algebraic expansions but also gives insights into deeper mathematical concepts encountered in statistics and probability.

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Most popular questions from this chapter

Card and die experiment Each suit in a deck is made up of an ace (A), nine numbered cards \((2,3, \ldots, 10),\) and three face cards (J, Q, K). An experiment consists of drawing a single card from a deck followed by rolling a single die. Describe the sample space \(S\) of the experiment, and find \(n(S)\) Let \(E_{1}\) be the event consisting of the outcomes in which a numbered card is drawn and the number of dots on the die is the same as the number on the card. Find \(n\left(E_{1}\right), n\left(E_{1}^{\prime}\right),\) and \(P\left(E_{1}\right)\) Let \(E_{2}\) be the event in which the card drawn is a face card, and let \(E_{3}\) be the event in which the number of dots on the die is even. Are \(E_{2}\) and \(E_{3}\) mutually exclusive? Are they independent? Find \(P\left(E_{2}\right), P\left(E_{3}\right)\) \(P\left(E_{2} \cap E_{3}\right),\) and \(P\left(E_{2} \cup E_{3}\right)\) Are \(E_{1}\) and \(E_{2}\) mutually exclusive? Are they independent? Find \(P\left(E_{1} \cap E_{2}\right)\) and \(P\left(E_{1} \cup\right.\) \(\left.E_{2}\right)\)

In an average year during \(1995-1999\), smoking caused \(442,398\) deaths in the United States. Of these deaths, cardiovascular disease accounted for \(148,605\) cancer for \(155,761,\) and respiratory diseases such as emphysema for \(98,007\) (a) Find the probability that a smoking-related death was the result of either cardiovascular disease or cancer. (b) Determine the probability that a smoking-related death was not the result of respiratory diseases.

Exer. \(39-42:\) (a) Graph \(C(n, r)\) for the given value of \(n\) where \(r=1,2,3, \ldots, n .\) (b) Determine the maximum of \(C(n, r)\) and the value(s) of \(r\) where this maximum occurs.$$n=19$$

Letter and number experiment An experiment consists of selecting a letter from the alphabet and one of the digits 0 , \(\therefore 9\). (a) Describe the sample space \(S\) of the experiment, and find \(n(S)\) (b) Suppose the letters of the alphabet are assigned numbers as follows: \(A=1, B=2, \ldots, Z=26 .\) Let \(E_{1}\) be the event in which the units digit of the number assigned to the letter of the alphabet is the same as the digit selected. Find \(n\left(E_{1}\right), n\left(E_{1}^{\prime}\right),\) and \(P\left(E_{1}\right)\) Let \(E_{2}\) be the event that the letter is one of the five vowels and \(E_{3}\) the event that the digit is a prime number. Are \(E_{2}\) and \(E_{3}\) mutually exclusive? Are they independent? Find \(P\left(E_{2}\right), P\left(E_{3}\right), P\left(E_{2} \cap E_{3}\right),\) and \(P\left(E_{2} \cup E_{3}\right)\) Let \(E_{4}\) be the event that the numerical value of the letter is even. Are \(E_{2}\) and \(E_{4}\) mutually exclusive? Are they independent? Find \(P\left(E_{2} \cap E_{4}\right)\) and \(P\left(E_{2} \cup E_{4}\right)\)

The outcomes \(1,2, \ldots, 6\) of an experiment and their probabilities are listed in the table. $$\begin{array}{l|cccccc}\\\\\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Probability } & 0.25 & 0.10 & 0.15 & 0.20 & 0.25 & 0.05 \\\\\hline\end{array}$$.For the Indicated events, find (a) \(P\left(E_{2}\right),\) (b) \(P\left(E_{1} \cap E_{2}\right)\) (c) \(P\left(E_{1} \cup E_{2}\right),\) and \((d) P\left(E_{2} \cup E_{3}^{\prime}\right)\). $$E_{1}=\\{1,2\\} ; \quad E_{2}=\\{2,3,4\\} ; \quad E_{3}=\\{4,6\\}$$

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