Chapter 7: Problem 34
Find the magnitude of the vector a and the smallest positive angle \(\boldsymbol{\theta}\) from the positive \(x\) -axis to the vector \(O P\) that corresponds to a. $$a=101-10 j$$
Short Answer
Expert verified
Magnitude of vector is approximately 101.49, smallest positive angle is 354.29°.
Step by step solution
01
Identify the Components of Vector a
We are given the vector \(a = 101 - 10j\). This vector can be broken down into its real and imaginary parts. The real part is 101, and the imaginary part is -10. In terms of vector components, this means \(a = (101, -10)\).
02
Calculate the Magnitude of Vector a
The magnitude of a vector \( (x, y) \) is calculated using the formula \( \sqrt{x^2 + y^2} \). For \(a = (101, -10)\), the magnitude \( ||a|| = \sqrt{101^2 + (-10)^2} \). Calculate: \( ||a|| = \sqrt{10201 + 100} = \sqrt{10301} \approx 101.49 \).
03
Determine the Angle with the Positive x-Axis
The angle \( \theta \) that the vector \( a \) makes with the positive x-axis is given by \( tan^{-1}(\frac{y}{x}) \). Substitute the components: \( \theta = tan^{-1}(\frac{-10}{101}) \). Calculate \( \theta \approx tan^{-1}(-0.099) \approx -5.71^\circ \).
04
Adjust for the Smallest Positive Angle
Since angles are typically measured positive from the positive x-axis, and the calculated \( \theta \) is negative, we adjust it to obtain the smallest positive equivalent angle: \( \theta = 360^\circ - 5.71^\circ = 354.29^\circ \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers combine a real part and an imaginary part. In the vector \( a = 101 - 10j \), 101 is the real component, while -10j is the imaginary component. This combination allows complex numbers to be plotted on a two-dimensional plane, with the real part corresponding to the x-axis and the imaginary part to the y-axis.
Complex numbers are written in the form \( z = a + bj \), where \( a \) is the real component and \( b \) is the coefficient of the imaginary component \( j \). The imaginary unit \( j \) represents \( \sqrt{-1} \). By interpreting complex numbers as vectors, they become very useful in various mathematical computations and physics contexts.
Complex numbers are written in the form \( z = a + bj \), where \( a \) is the real component and \( b \) is the coefficient of the imaginary component \( j \). The imaginary unit \( j \) represents \( \sqrt{-1} \). By interpreting complex numbers as vectors, they become very useful in various mathematical computations and physics contexts.
- The real part indicates horizontal displacement.
- The imaginary part corresponds to vertical displacement.
Angle Calculation
Calculating angles in vector analysis helps to understand the direction of a vector relative to a fixed axis, typically the positive x-axis. In our example, we need to find the angle \( \theta \) of vector \( a = 101 - 10j \) relative to the positive x-axis. For this, we use the formula:
\[ \theta = \tan^{-1}\left(\frac{y}{x}\right) \]
Here, \( x \) is the real part (101), and \( y \) is the imaginary part (-10). Substituting these values, we calculate \( \theta = \tan^{-1}\left(\frac{-10}{101}\right) \).
\[ \theta = \tan^{-1}\left(\frac{y}{x}\right) \]
Here, \( x \) is the real part (101), and \( y \) is the imaginary part (-10). Substituting these values, we calculate \( \theta = \tan^{-1}\left(\frac{-10}{101}\right) \).
- A negative angle signifies a clockwise direction.
- Since our result is \(-5.71^\circ\), which is negative, it shows that vector \( a \) is slightly below the positive x-axis.
Polar Coordinates
Polar coordinates provide an alternative method to describe the position of a point in a plane. Instead of using rectangular coordinates (x, y), polar coordinates utilize the vector's magnitude (r) and direction (angle θ). For example, the vector \( a = 101 - 10j \) can be expressed in polar form.
Here, the magnitude \( r \) represents the distance from the origin to the point and is calculated with:
\[ r = \sqrt{x^2 + y^2} \]
Substituting our values, we get \( r = \sqrt{101^2 + (-10)^2} \approx 101.49 \). This tells us how far the point is from the origin. The angle \( \theta = 354.29^\circ \), calculated previously, indicates the direction of the vector from the positive x-axis.
Here, the magnitude \( r \) represents the distance from the origin to the point and is calculated with:
\[ r = \sqrt{x^2 + y^2} \]
Substituting our values, we get \( r = \sqrt{101^2 + (-10)^2} \approx 101.49 \). This tells us how far the point is from the origin. The angle \( \theta = 354.29^\circ \), calculated previously, indicates the direction of the vector from the positive x-axis.
- Polar coordinates are widely used in scenarios where angles and distances are more intuitive representations than flat grid references.
- They are particularly beneficial in circular or rotational systems, like waves and orbits.