Chapter 7: Problem 11
If \(\mathbf{a}=\langle- 4,5\rangle\) and \(\mathbf{b}=\langle 2,-8\rangle,\) sketch vectors corresponding to (a) \(\mathbf{a}+\mathbf{b}\) (b) \(\mathbf{a}-\mathbf{b}\) (c) \(2 a\) (d) \(-\frac{1}{2} \mathbf{b}\)
Short Answer
Expert verified
(a) \(\langle -2, -3 \rangle\), (b) \(\langle -6, 13 \rangle\), (c) \(\langle -8, 10 \rangle\), (d) \(\langle -1, 4 \rangle\)
Step by step solution
01
Understand Vector Operations
For a given vector \(\mathbf{v} = \langle v_1, v_2 \rangle\), vector addition is carried out by adding corresponding components: \(\mathbf{v} + \mathbf{w} = \langle v_1 + w_1, v_2 + w_2 \rangle\). Vector subtraction is similar: \(\mathbf{v} - \mathbf{w} = \langle v_1 - w_1, v_2 - w_2 \rangle\). Scalar multiplication involves multiplying each component of the vector by the scalar: \(c\mathbf{v} = \langle c \times v_1, c \times v_2 \rangle\).
02
Calculate \(\mathbf{a} + \mathbf{b}\)
Add the components of vectors \(\mathbf{a}\) and \(\mathbf{b}\): \(\mathbf{a} + \mathbf{b} = \langle -4 + 2, 5 - 8 \rangle = \langle -2, -3 \rangle\).
03
Calculate \(\mathbf{a} - \mathbf{b}\)
Subtract the components of \(\mathbf{b}\) from \(\mathbf{a}\): \(\mathbf{a} - \mathbf{b} = \langle -4 - 2, 5 + 8 \rangle = \langle -6, 13 \rangle\).
04
Calculate \(2 \mathbf{a}\)
Multiply each component of \(\mathbf{a}\) by 2: \(2 \mathbf{a} = 2 \times \langle -4, 5 \rangle = \langle -8, 10 \rangle\).
05
Calculate \(-\frac{1}{2} \mathbf{b}\)
Multiply each component of \(\mathbf{b}\) by \(-\frac{1}{2}\): \(-\frac{1}{2} \mathbf{b} = -\frac{1}{2} \times \langle 2, -8 \rangle = \langle -1, 4 \rangle\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
Vector addition is a fundamental operation involving two vectors. When adding two vectors, you simply add their corresponding components. In our example, we have two vectors:
- \( \mathbf{a} = \langle -4, 5 \rangle \)
- \( \mathbf{b} = \langle 2, -8 \rangle \)
- Add the first components: \( -4 + 2 = -2 \)
- Add the second components: \( 5 - 8 = -3 \)
Vector Subtraction
Vector subtraction allows us to find the difference between two vectors by subtracting their corresponding components. Suppose we have vectors \( \mathbf{a} = \langle -4, 5 \rangle \) and \( \mathbf{b} = \langle 2, -8 \rangle \). When subtracting, we do the following:
- Subtract the first components: \( -4 - 2 = -6 \)
- Subtract the second components: \( 5 - (-8) = 13 \)
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar, which scales the vector's magnitude without changing its direction, unless if the scalar is negative. Consider the vector \( \mathbf{a} = \langle -4, 5 \rangle \). To scale this vector by 2, perform the following:
- Multiply each component by 2: \( 2 \times -4 = -8 \) and \( 2 \times 5 = 10 \)
- Each component is \(-\frac{1}{2} \times 2 = -1 \) and \(-\frac{1}{2} \times -8 = 4 \)
Coordinate Vectors
Coordinate vectors simplify the representation and manipulation of vectors. They are especially useful in illustrating vector components within a Cartesian plane. For the vectors \( \mathbf{a} = \langle -4, 5 \rangle \) and \( \mathbf{b} = \langle 2, -8 \rangle \), the components \(-4\) and \(5\) for \( \mathbf{a} \) and \(2\) and \(-8\) for \( \mathbf{b} \) identify their positions in the plane. These coordinate vectors facilitate operations like addition, subtraction, and scalar multiplication through straightforward arithmetic.
- Each component corresponds to an axis: first for \(x\) and second for \(y\).