Chapter 6: Problem 64
Either show that the equation \(i s\) an identity or show that the equation \(is\quad not\) an identity. $$\csc ^{2} x+\sec ^{2} x=\csc ^{2} x \sec ^{2} x$$
Short Answer
Expert verified
The equation is an identity.
Step by step solution
01
Understand the Problem
We need to determine whether the trigonometric equation \( \csc ^{2} x+\sec ^{2} x=\csc ^{2} x \sec ^{2} x \) holds true for all allowed values of \( x \). If it holds for every valid input, it's an identity; otherwise, it's not.
02
Recall Trigonometric Identities
Recall the definitions:\( \csc x = \frac{1}{\sin x} \) and \( \sec x = \frac{1}{\cos x} \). Therefore, \( \csc^2 x = \frac{1}{\sin^2 x} \) and \( \sec^2 x = \frac{1}{\cos^2 x} \). Substitute these into the given equation.
03
Substitute into the Equation
Substitute \( \csc^2 x = \frac{1}{\sin^2 x} \) and \( \sec^2 x = \frac{1}{\cos^2 x} \) into the equation:\[ \frac{1}{\sin^2 x} + \frac{1}{\cos^2 x} = \frac{1}{\sin^2 x} \cdot \frac{1}{\cos^2 x} \].
04
Find a Common Denominator
Combine the left side into a single fraction:\[ \frac{1}{\sin^2 x} + \frac{1}{\cos^2 x} = \frac{\cos^2 x + \sin^2 x}{\sin^2 x \cos^2 x} \].
05
Simplify Using Pythagorean Identity
Recognize that \( \sin^2 x + \cos^2 x = 1 \), then substitute:\[ \frac{\cos^2 x + \sin^2 x}{\sin^2 x \cos^2 x} = \frac{1}{\sin^2 x \cos^2 x} \].
06
Reduce the Right Hand Side
Recall that the right side of the original equation is:\[ \frac{1}{\sin^2 x \cos^2 x} \], which matches the simplified left side.
07
Conclusion
Since both sides of the equation are equal, \( \frac{1}{\sin^2 x \cos^2 x} = \frac{1}{\sin^2 x \cos^2 x} \), the given equation is an identity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosecant Function
The cosecant function, denoted as \( \csc x \), is a fundamental trigonometric function closely related to the sine function. It is defined as the reciprocal of sine:
To express \( \csc^2 x \), we square the basic definition of the cosecant, resulting in:
- \( \csc x = \frac{1}{\sin x} \)
To express \( \csc^2 x \), we square the basic definition of the cosecant, resulting in:
- \( \csc^2 x = \left( \frac{1}{\sin x} \right)^2 = \frac{1}{\sin^2 x} \)
Secant Function
The secant function, denoted as \( \sec x \), is another key trigonometric function defined as the reciprocal of the cosine function:
When squaring the secant function, we get:
- \( \sec x = \frac{1}{\cos x} \)
When squaring the secant function, we get:
- \( \sec^2 x = \left( \frac{1}{\cos x} \right)^2 = \frac{1}{\cos^2 x} \)
Pythagorean Identity
The Pythagorean identity is a cornerstone of trigonometry. It's derived from the Pythagorean theorem and relates the squares of the sine and cosine functions:
For example, in the given problem, understanding that \( \sin^2 x + \cos^2 x = 1 \) allows us to replace these sums in the equation:
By grasping the Pythagorean identity, students can tackle a wide range of trigonometric problems with more confidence, knowing that the sum of squares of sine and cosine will always equal one.
- \( \sin^2 x + \cos^2 x = 1 \)
For example, in the given problem, understanding that \( \sin^2 x + \cos^2 x = 1 \) allows us to replace these sums in the equation:
- \( \frac{\cos^2 x + \sin^2 x}{\sin^2 x \cos^2 x} = \frac{1}{\sin^2 x \cos^2 x} \)
By grasping the Pythagorean identity, students can tackle a wide range of trigonometric problems with more confidence, knowing that the sum of squares of sine and cosine will always equal one.