Chapter 6: Problem 22
If \(\tan \alpha=-\frac{7}{24}\) and \(\cot \beta=\frac{3}{4}\) for a second- quadrant angle \(\alpha\) and a third-quadrant angle \(\boldsymbol{\beta},\) find (a) \(\sin (\alpha+\beta)\) \(\langle b\rangle \cos (\alpha+\beta)\) \(\langle c) \tan (\alpha+\beta)\) (d) \(\sin (\alpha-\beta)\) (e) \(\cos (\alpha-\beta)\) (f) \(\tan (\alpha-\beta)\)
Short Answer
Step by step solution
Determine sine and cosine for \(\alpha\)
Determine sine and cosine for \(\beta\)
Calculate \(\sin (\alpha + \beta)\)
Calculate \(\cos (\alpha + \beta)\)
Calculate \(\tan (\alpha + \beta)\)
Calculate \(\sin (\alpha - \beta)\)
Calculate \(\cos (\alpha - \beta)\)
Calculate \(\tan (\alpha - \beta)\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Angle Addition Identity
- For sine: \(\sin(\alpha + \beta) = \sin \alpha \cos \beta + \cos \alpha \sin \beta\).
- For cosine: \(\cos(\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta\).
- For tangent: \(\tan(\alpha + \beta) = \frac{\tan \alpha + \tan \beta}{1 - \tan \alpha \tan \beta}\).
A big hint here is to carefully identify the known values of \(\sin\), \(\cos\), and \(\tan\) for each angle before plugging them into these formulas.
Angle Subtraction Identity
- For sine: \(\sin(\alpha - \beta) = \sin \alpha \cos \beta - \cos \alpha \sin \beta\).
- For cosine: \(\cos(\alpha - \beta) = \cos \alpha \cos \beta + \sin \alpha \sin \beta\).
- For tangent: \(\tan(\alpha - \beta) = \frac{\tan \alpha - \tan \beta}{1 + \tan \alpha \tan \beta}\).
Trigonometric Functions
- \(\sin \theta = \frac{\text{Opposite side}}{\text{Hypotenuse}}\)
- \(\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse}}\)
- \(\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{\sin \theta}{\cos \theta}\)
Quadrants of the Unit Circle
- First Quadrant: Both sine and cosine are positive.
- Second Quadrant: Sine is positive, but cosine is negative.
- Third Quadrant: Both sine and cosine are negative.
- Fourth Quadrant: Sine is negative, whereas cosine is positive.