Chapter 6: Problem 2
Find all solutions of the equation. $$\cos t=-1$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 6: Problem 2
Find all solutions of the equation. $$\cos t=-1$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
The given equation has the form \(y=f(x)\) (a) Find the domain of \(f .\) (b) Find the range of \(f .\) (c) Solve for \(x\) in terms of \(y\) $$y=3 \tan ^{-1}(2 x+1)$$
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. $$6 \sin 2 x-8 \cos x+9 \sin x-6=0 ; \quad\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$$
The altitude of the sun is the angle \(\phi\) that the sun's rays make with the horizon at a given time and place. Determining \(\phi\) is important in tilting a solar collector to obtain maximum efficiency. On June 21 at a latitude of \(51.7^{\circ} \mathrm{N}\), the altitude of the sun can be approximated using the formula \(\sin \phi=\sin 23.5^{\circ} \sin 51.7^{\circ}+\cos 23.5^{\circ} \cos 51.7^{\circ} \cos H\) where \(H\) is called the hour angle, with \(H=-\pi / 2\) at 6 A.M., \(H=0\) at noon, and \(H=\pi / 2\) at 6 P.M. Solve the formula for \(\phi,\) and graph the resulting equation for \(-\pi / 2 \leq H \leq \pi / 2\) (b) Estimate the times when \(\phi=45^{\circ}\).
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. $$6 \sin ^{3} \theta+18 \sin ^{2} \theta-5 \sin \theta-15=0 ; \quad\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$$
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. $$\begin{aligned} &(\cos x)(15 \cos x+4)=3\\\ &[0,2 \pi) \end{aligned}$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.