/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Given the indicated parts of tri... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) find the exact values of the remaining parts. $$a=5, \quad b=5$$

Short Answer

Expert verified
\( c = 5\sqrt{2} \), \( \alpha = 45^\circ \), \( \beta = 45^\circ \).

Step by step solution

01

Identify the Right Triangle Properties

Since \( \gamma = 90^{\circ} \), triangle \( \triangle ABC \) is a right triangle with \( C \) being the right angle. The sides \( a \) and \( b \) are the legs of the triangle and \( c \) is the hypotenuse.
02

Apply the Pythagorean Theorem

For any right triangle, the Pythagorean theorem states \( a^2 + b^2 = c^2 \). Since \( a = 5 \) and \( b = 5 \), substitute these values into the equation: \( 5^2 + 5^2 = c^2 \). Calculate \( c \).
03

Solving for the Hypotenuse \( c \)

Calculate \( 5^2 + 5^2 = c^2 \). This gives \( 25 + 25 = c^2 \), so \( c^2 = 50 \). Solving for \( c \), we find \( c = \sqrt{50} = 5\sqrt{2} \).
04

Calculate \( \alpha \) and \( \beta \) Using Trigonometric Ratios

Since both legs \( a \) and \( b \) are equal, the triangle is isosceles. In an isosceles right triangle, the angles opposite the equal sides are equal. Using the property \( \alpha + \beta + \gamma = 180^\circ \), \( \alpha + \beta = 90^\circ \), we find \( \alpha = \beta = 45^\circ \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in right triangle trigonometry. It states that in any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides, called the legs. Mathematically, it is expressed as:\[ a^2 + b^2 = c^2 \]where:
  • \(a\) and \(b\) are the lengths of the two legs,
  • \(c\) is the length of the hypotenuse.
For example, in an isosceles right triangle where both legs are equal, say \(a = b = 5\), you can apply the Pythagorean Theorem. Here, substituting the values gives:\[ 5^2 + 5^2 = c^2 \]This simplifies to \(50 = c^2\), where solving for \(c\) yields \(c = \sqrt{50} = 5\sqrt{2}\). This demonstrates how the theorem helps us determine unknown sides of right triangles when other sides are known.
Isosceles Right Triangle
An isosceles right triangle is a specific type of right triangle where two of its sides are equal in length. This also means that the angles opposite those sides are equal. By definition:
  • The two equal sides are known as the legs of the triangle.
  • The angle between these equal sides is \(90^{\circ}\) .
  • The two other angles in the triangle are \(45^{\circ}\) each.
In our original problem, the triangle had legs \(a\) and \(b\) both equal to \(5\), making it an isosceles right triangle. The symmetry of the triangle ensures that both non-right angles \(\alpha\) and \(\beta\) measure \(45^{\circ}\), while the Pythagorean Theorem confirms that the hypotenuse is \(5\sqrt{2}\). This property simplifies calculating angles and sides, as you already know the angles if you know two sides are equal.
Trigonometric Ratios
Trigonometric ratios are essential tools that relate the angles and sides of triangles. In right triangles, the primary trigonometric ratios are sine, cosine, and tangent. These are defined as follows:
  • Sine (\(\sin\)): opposite leg over hypotenuse
  • Cosine (\(\cos\)): adjacent leg over hypotenuse
  • Tangent (\(\tan\)): opposite leg over adjacent leg
For the isosceles right triangle in our example:
  • The sine and cosine of \(45^{\circ}\) are both equal to \( \frac{1}{\sqrt{2}} \) or \( \frac{\sqrt{2}}{2} \).
  • The tangent of \(45^{\circ}\) is 1, as the opposite and adjacent sides are equal.
Understanding these ratios helps in calculating unknown sides or angles in right triangles. Particularly when solving for angles using sides, these ratios are invaluable.
Angle Calculation in Right Triangles
Angle calculation in right triangles is straightforward, thanks to the sum of angles in a triangle being \(180^{\circ}\). In any right triangle, this principle simplifies to:\[ \alpha + \beta + \gamma = 180^{\circ} \]Where \(\gamma\) is the right angle, thus:\[ \alpha + \beta = 90^{\circ} \]For an isosceles right triangle, where the other two angles are equal, each measures \(45^{\circ}\). Calculating angles is crucial when you're given some values and need the others. Since the triangle in our exercise is isosceles with equal legs, this inherent property saves time and steps. Knowing the equal split of the remaining \(90^{\circ}\) between two equal angles, the quick calculation leads directly to \(\alpha = \beta = 45^{\circ}\). This property of angles is used frequently in solving real-life problems involving right triangles.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Potation of compact disces (COs) The drive motor of a particular CD player is controlled to rotate at a speed of \(200 \mathrm{rpm}\) when reading a track 5.7 centimeters from the center of the CD. The speed of the drive motor must vary so that the reading of the data occurs at a constant rate. (a) Find the angular speed (in radians per minute) of the drive motor when it is reading a track 5.7 centimeters from the center of the CD.(b) Find the linear speed (in \(\mathrm{cm} / \mathrm{sec}\) ) of a point on the CD that is 5.7 centimeters from the center of the CD. Find the angular speed (in rpm) of the drive motor when it is reading a track 3 centimeters from the center of the CD. Find a function \(S\) that gives the drive motor speed in \(\mathrm{rpm}\) for any radius \(r\) in centimeters, where \(2.3 \leq r \leq 5.9\) What type of variation exists between the drive motor speed and the radius of the track being read? Check your answer by graphing \(S\) and finding the speeds for \(r=3\) and \(r=5.7\)

\(A\) conveyor belt 9 meters long can be hydraulically rotated up to an angle of \(40^{\circ}\) to unload cargo from airplanes (see the figure). (a) Find, to the nearest degree, the angle through which the conveyor belt should be rotated up to reach a door that is 4 meters above the platform supporting the belt. (b) Approximate the maximum height above the platform that the belt can reach. (IMAGE CAN NOT COPY)

Graph the function \(f\) on \([-\pi, \pi],\) and estimate the high and low points. $$f(x)=\cos 2 x+2 \sin 4 x-\sin x$$

Graph the equation on the Interval \([-2,2]\), and describe the behavior of \(y\) as \(x \rightarrow 0^{-}\) and as \(x \rightarrow 0^{+}\) \(y=|x| \sin \frac{1}{x}\)

Cargo winch A large winch of diameter 3 feet is used to hoist cargo, as shown in the figure. (a) Find the distance the cargo is lifted if the winch rotates through an angle of radian measure \(7 \pi / 4\) (b) Find the angle (in radians) through which the winch must rotate in order to lift the cargo \(d\) feet.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.