Chapter 5: Problem 19
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=\sin \left(\frac{1}{2} x-\frac{\pi}{3}\right)\)
Short Answer
Expert verified
Amplitude: 1, Period: \(4\pi\), Phase shift: \(\frac{2\pi}{3}\) right.
Step by step solution
01
Identify the Amplitude
In the equation of the form \(y = a \sin(bx - c)\), the amplitude is given by the absolute value of \(a\). In this problem, since the function is \(y = \sin \left(\frac{1}{2} x - \frac{\pi}{3}\right)\), the coefficient of \(\sin\) (which is \(1\)) is the amplitude. Therefore, the amplitude is \(1\).
02
Determine the Period
The period of a sine function \(y = a \sin(bx - c)\) is given by \(\frac{2\pi}{b}\). Here, \(b = \frac{1}{2}\), so substituting in gives us the period: \[ \frac{2\pi}{\frac{1}{2}} = 4\pi. \] Thus, the period of the function is \(4\pi\).
03
Find the Phase Shift
The phase shift in a function \(y = a \sin(bx - c)\) is given by \(\frac{c}{b}\). Here, \(c = \frac{\pi}{3}\) and \(b = \frac{1}{2}\). Substituting these values gives: \[ \text{Phase Shift} = \frac{\frac{\pi}{3}}{\frac{1}{2}} = \frac{2\pi}{3}. \] Since the equation is subtracted by \(\frac{\pi}{3}\), the phase shift is to the right by \(\frac{2\pi}{3}\).
04
Sketch the Graph
To sketch the graph, start by plotting the sine function with the characteristics found: Amplitude \(1\), Period \(4\pi\), and phase shift to the right by \(\frac{2\pi}{3}\). Begin with the regular sine function, \(rac{1}{2}x\), stretched over \(4\pi\) and horizontally shifted to the right by \(\frac{2\pi}{3}\). The graph will oscillate between \(1\) and \(-1\) for each cycle over \(4\pi\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
In trigonometric functions, especially sinusoidal ones like sine and cosine, the amplitude is a crucial concept to understand. Amplitude refers to how much a wave oscillates above and below its central axis, essentially measuring the "height" of the wave. In the general equation of a sine function, which is formulated as
This amplitude describes the extent of vertical displacement from the x-axis, defining how "tall" or "short" the wave will appear on a graph.
- \(y = a\sin(bx - c)\)
- \(y = \sin \left(\frac{1}{2} x - \frac{\pi}{3}\right)\),
This amplitude describes the extent of vertical displacement from the x-axis, defining how "tall" or "short" the wave will appear on a graph.
- Amplitude = Absolute value of \(a\)
- For our function, the amplitude is \(|1| = 1\).
Period
The period of a trigonometric function describes how frequently the wave pattern repeats itself over the horizontal axis. It can be seen as the "length" before the function starts a new cycle. In the standard form of a sine function,
- \(y = a \sin(bx - c)\)
- \(\text{Period} = \frac{2\pi}{b}\)
- \(b = \frac{1}{2}\),
- \(\text{Period} = \frac{2\pi}{\frac{1}{2}} = 4\pi\).
Phase Shift
Phase shift refers to the horizontal translation of a trigonometric function along the x-axis. Essentially, it tells us where the wave begins relative to the standard position of the function. In the formula
- \(y = a\sin(bx - c)\)
- \(\text{Phase Shift} = \frac{c}{b}\)
- \(y = \sin \left(\frac{1}{2} x - \frac{\pi}{3}\right)\),
- \(c = \frac{\pi}{3}\)
- \(b = \frac{1}{2}\)
- \(\text{Phase Shift} = \frac{\frac{\pi}{3}}{\frac{1}{2}} = \frac{2\pi}{3}\).